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yea but i don't need to square 1+h because why? lol

usually i have to square it... that's why. especially for a slope problem.

in other words, you do square (1+h)

but when i squared (1+h), the 4's and 3's cancel. i get 8.04 when the answer should be 8.4 m/s

\[4(h ^{2}+2h+1) +3-4(1)^{2}-3\] since t =1?

and t = 1+h

if you factor out 4h, it should be 4h(h+2) and 4(h+2) after dividing by h

yea that's my mistake... i left the squared. thanks :)

i can't believe it was that miniscule

so close....

i know! such a tiny mistake could cost me an answer by one decimal place -_-

sometimes it just doesn't work out...good luck!