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Let PQR be a right angled isosceles triangle in a cartesian plane, right angled at P(2,1). If the equation of the line QR is 2x+y = 3, then the equation representing the pair PQ and PR is..
 one year ago
 one year ago
Let PQR be a right angled isosceles triangle in a cartesian plane, right angled at P(2,1). If the equation of the line QR is 2x+y = 3, then the equation representing the pair PQ and PR is..
 one year ago
 one year ago

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ChmEBest ResponseYou've already chosen the best response.0
Draw a picture first. it always helps visualize
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
Well there wasn't one but neway heres what I can do..
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
When it says right angled at (2,1) I think at that point it is 90 deg
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
dw:1347994216890:dw
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
yes dats pretty obvious isn't it??
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
Right angle isoceles means that the sides to each side of the right angle are equal. Ya I'd say so after the picture.
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
yup, both the angles will be 45 degrees, i.e, 45+45+90
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
Can't anybody solve this??
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
I want to say PQ is just x=2 and PR is just y=1, but what if the triangle is at an angle..
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
just find points Q and R, given that we know P
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
then use point slope and all that business
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
Its an isosceles right angled triangle that means 2 of its angle are 45 degrees and one is at 90 degrees..
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
@TuringTest the question is HOW???
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
let's draw a bigger pic
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
dw:1347994331965:dw
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
btw the answers ae PQ = x+3y 5 and PR = 3xy5
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
lol does that help?
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
@bahrom7893 No dude!!! Its already in the question... :P
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
dw:1347994441088:dw
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
I got it so far!!! next step will be what??
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
calm down dude I am explaining...
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
:P Sorry its just that its getting in my head bad!!
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
well all that is given in the ques, no additionally details are provided..
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
though I must admit I;m not sure exactly what they are asking the equation for the pair? what do they mean?
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
hahhahahahah.. Exactly what Ive stumbled upon..
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
by pair of lines they mean PQ and PR
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
but infinitely I assume, not a finite line segment....
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
nope its finite alright!!!
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
then the answer must give bounds to x and y
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
Look will it help if I write the solution down, The thing is Ive got the solution but I don't really understand it very well...
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
dw:1347994766490:dw
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
yeah that may help me understand what they are asking
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
The equations of PQ and Pr are... y2 = [2 /+ tan 45/1+/ (2)tan 45] * (x2) <=> HOW??? Solving this they Got PQ ad PR...
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
oh I misinterpreted the problem I see
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
dw:1347994998473:dwso my assumption that the legs of the triangle followed the grid was wrong
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
@TuringTest Still don't get...
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
well now the problem is harder than I thought, so let me think on it I was eating lunch as I was doing this because I thought it would be easy lol
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
:P well it isn't @hartnn DUDE!!! You were saying u got it ryt?? Will you do the honor of telling me how??
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
even i thought that lines are vertical and horizontal.....but they r not.....even i m stuck...
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
that seems the formula for tan(A+B) ....in the solution u mentioned....do u have some standard formulas in this topic ?
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
I know!!! just one , but I don't understand hw to implement it in this one..
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
Two lines will be perpendicular to each other if...coeff of x^2 + coeff of y^2 = 0
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
but this is a first degreeequation so can't really put that in...
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
Think people THINK!!!! The person who can solve this will be titled a born genius.. :P
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
dw:1347995522447:dw
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
I dunno I'll have to drop this for now...
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
NOOOOOOOOOOOOOOOOOOOOOOOOOOO!!!! :'(
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
dw:1347995617810:dw i don't know what i m doing......
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
6 equations 8 unknowns.
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
1 more equation and we are done.
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
you mean one more equation if was provided??
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
1 more equation WE need to find.
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
Take all the time you need, Ill be here for a while....
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
lol, very big equation it is!! PQ=PR and distance formula :P
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
we getting 8 equations and 8 unknowns but its almost impossible to solve them simultaneously.....there must be another way...
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
I typed in the equation and the solution that was given in the text.. The only questions bugging my mind is Y and HOW??
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
and even how y2 and x2 ?? y2 and x1 maybe.....
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
we can use help of @ganeshie8 here....
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
do u have formulas like this somewhere ? \(\huge yy_1=\frac{m_1\pm m_2}{1\mp m_1m_2}(xx_1)\) with this u directly get to answer..............
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
m1 is slope of given line = 2 m2 is slope between lines = tan 45 .............
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1347997360648:dw
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
im trying to work this out by finding out inclination angles for the two lines PR and PQ
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
since we have a point P(1, 2 ) already, we just need to find the inclination angle
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1347997747693:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
nice hint @ganeshie8 , i have some idea now....
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
inclination angles easy to find.........
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
no this is roundabout way... im sure using ur formula we get to the answer much faste.r...
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
can someone just elucidate what or how I can solve the problem??
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
did u get that figure ? @robinfr93
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
dw:1347998406604:dw solved!
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
main thing was to find slope of one of the line = 3 using inclination angles....
 one year ago
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