A community for students.
Here's the question you clicked on:
 0 viewing
wendy67
 2 years ago
SImplify:
Help Please!
wendy67
 2 years ago
SImplify: Help Please!

This Question is Closed

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1+2i }{ \sqrt{2}+i }\]

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0Multiply both numerator and denominator by the conjugate of the denominator.I mean

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1+2i}{\sqrt{2}+i}\cdot \frac{\sqrt{2}i}{\sqrt{2}i}\]

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0I got: \[\frac{ \sqrt{2}i+2i \sqrt{2}2i ^{2} }{ 2i ^{2}}\]

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0but also you know that \[i^2=1\]

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0so, it would be: \[\frac{ \sqrt{2}i+2i \sqrt{2}2(1) }{ 2(1) }\]

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0yes, now just make arithmetic operations.

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0ok i got: \[\frac{ \sqrt{2}i+2i \sqrt{2}+2 }{ 3 }\] and this where i got stuck

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0is there a specific anwer you need to get?

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0yes i should get : \[\frac{ 2+\sqrt{2} }{ 3 }+\frac{ 2\sqrt{2}1 }{ 3 }\]

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0I got: \[\frac{\sqrt{2}+2}{3}\frac{1+2\sqrt{2}}{3}i\]

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0ok so how did you get that?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.