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wendy67Best ResponseYou've already chosen the best response.0
\[\frac{ 1+2i }{ \sqrt{2}+i }\]
 one year ago

NodataBest ResponseYou've already chosen the best response.0
Multiply both numerator and denominator by the conjugate of the denominator.I mean
 one year ago

NodataBest ResponseYou've already chosen the best response.0
\[\frac{1+2i}{\sqrt{2}+i}\cdot \frac{\sqrt{2}i}{\sqrt{2}i}\]
 one year ago

wendy67Best ResponseYou've already chosen the best response.0
I got: \[\frac{ \sqrt{2}i+2i \sqrt{2}2i ^{2} }{ 2i ^{2}}\]
 one year ago

NodataBest ResponseYou've already chosen the best response.0
but also you know that \[i^2=1\]
 one year ago

wendy67Best ResponseYou've already chosen the best response.0
so, it would be: \[\frac{ \sqrt{2}i+2i \sqrt{2}2(1) }{ 2(1) }\]
 one year ago

NodataBest ResponseYou've already chosen the best response.0
yes, now just make arithmetic operations.
 one year ago

wendy67Best ResponseYou've already chosen the best response.0
ok i got: \[\frac{ \sqrt{2}i+2i \sqrt{2}+2 }{ 3 }\] and this where i got stuck
 one year ago

NodataBest ResponseYou've already chosen the best response.0
is there a specific anwer you need to get?
 one year ago

wendy67Best ResponseYou've already chosen the best response.0
yes i should get : \[\frac{ 2+\sqrt{2} }{ 3 }+\frac{ 2\sqrt{2}1 }{ 3 }\]
 one year ago

NodataBest ResponseYou've already chosen the best response.0
I got: \[\frac{\sqrt{2}+2}{3}\frac{1+2\sqrt{2}}{3}i\]
 one year ago

wendy67Best ResponseYou've already chosen the best response.0
ok so how did you get that?
 one year ago
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