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wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1+2i }{ \sqrt{2}+i }\]

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0Multiply both numerator and denominator by the conjugate of the denominator.I mean

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1+2i}{\sqrt{2}+i}\cdot \frac{\sqrt{2}i}{\sqrt{2}i}\]

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0I got: \[\frac{ \sqrt{2}i+2i \sqrt{2}2i ^{2} }{ 2i ^{2}}\]

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0but also you know that \[i^2=1\]

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0so, it would be: \[\frac{ \sqrt{2}i+2i \sqrt{2}2(1) }{ 2(1) }\]

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0yes, now just make arithmetic operations.

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0ok i got: \[\frac{ \sqrt{2}i+2i \sqrt{2}+2 }{ 3 }\] and this where i got stuck

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0is there a specific anwer you need to get?

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0yes i should get : \[\frac{ 2+\sqrt{2} }{ 3 }+\frac{ 2\sqrt{2}1 }{ 3 }\]

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0I got: \[\frac{\sqrt{2}+2}{3}\frac{1+2\sqrt{2}}{3}i\]

wendy67
 2 years ago
Best ResponseYou've already chosen the best response.0ok so how did you get that?
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