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anonymous
 3 years ago
Solve the system of equations using matrices. Use GaussJordan elimination
3x7y7z = 7
6x+4y3z=67
6x3y+z=62
anonymous
 3 years ago
Solve the system of equations using matrices. Use GaussJordan elimination 3x7y7z = 7 6x+4y3z=67 6x3y+z=62

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across
 3 years ago
Best ResponseYou've already chosen the best response.1Hint:\[\begin{bmatrix} 3 & 7 & 7\\ 6 & 4 & 3\\ 6 & 3 & 1 \end{bmatrix}\begin{bmatrix} x\\ y\\ z \end{bmatrix}=\begin{bmatrix} 7\\ 67\\ 62 \end{bmatrix}.\]

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.2did you use Michael Jordan Elimination method to arrive at x=7?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the book I am using is really confusing it says I have to get 1 on top but I don't know how

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I see how to do it when the number is 0 or 1 but I don't know how to start with the 3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@across almost gave you the cramers rule use it to find values of x, y, and z

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay I used that but my answers I think are what is confusing me these are my choices a. {(7,1,7)} b. {14,7,7)} c. {(7,7,14)} d. {(7,7,1)}

across
 3 years ago
Best ResponseYou've already chosen the best response.1If you have choices, all you have to do is substitute, I mean, slamdunk them and check!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I did that and none of them equal up

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that is the way they are

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0I'm interested in knowing that this Michael Jordan method is
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