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moser90

  • 3 years ago

Solve the system of equations using matrices. Use Gauss-Jordan elimination 3x-7y-7z = 7 6x+4y-3z=67 -6x-3y+z=-62

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  1. across
    • 3 years ago
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    Hint:\[\begin{bmatrix} 3 & -7 & -7\\ 6 & 4 & -3\\ -6 & -3 & 1 \end{bmatrix}\begin{bmatrix} x\\ y\\ z \end{bmatrix}=\begin{bmatrix} 7\\ 67\\ -62 \end{bmatrix}.\]

  2. moser90
    • 3 years ago
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    so does x = 7

  3. nincompoop
    • 3 years ago
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    hmm

  4. nincompoop
    • 3 years ago
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    did you use Michael Jordan Elimination method to arrive at x=7?

  5. moser90
    • 3 years ago
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    the book I am using is really confusing it says I have to get 1 on top but I don't know how

  6. nincompoop
    • 3 years ago
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    http://ceee.rice.edu/Books/CS/chapter2/linear44.html

  7. moser90
    • 3 years ago
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    I see how to do it when the number is 0 or 1 but I don't know how to start with the 3

  8. psi9epsilon
    • 3 years ago
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    @across almost gave you the cramers rule use it to find values of x, y, and z

  9. nincompoop
    • 3 years ago
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    http://www.karlscalculus.org/cgi-bin/linear.pl

  10. moser90
    • 3 years ago
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    okay I used that but my answers I think are what is confusing me these are my choices a. {(7,1,7)} b. {14,7,-7)} c. {(-7,7,14)} d. {(7,7,1)}

  11. across
    • 3 years ago
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    If you have choices, all you have to do is substitute, I mean, slam-dunk them and check!

  12. moser90
    • 3 years ago
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    I did that and none of them equal up

  13. moser90
    • 3 years ago
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    that is the way they are

  14. Hero
    • 3 years ago
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    I'm interested in knowing that this Michael Jordan method is

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