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 2 years ago
Domain & Range HELP! Please help with two functions. Click here and see the coming soon drawing...UPDATE: Drawing is now available!!!
 2 years ago
Domain & Range HELP! Please help with two functions. Click here and see the coming soon drawing...UPDATE: Drawing is now available!!!

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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1domain of sine is all real numbers

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1range of sine is \([1,1]\) so range of 3 sine is \([3,3]\) no algebra needed for that one

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1oh i didn't see the \(+1\) out at the end. adjust by adding one to get range of \([2,4]\)

Study23
 2 years ago
Best ResponseYou've already chosen the best response.0How do I find the domain of the sine equation?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1domain of sine is all real numbers, so unless there is some restriction inside, there is no restriction

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1domain of \(2x^45\) is all reals, so no worries here

Study23
 2 years ago
Best ResponseYou've already chosen the best response.0Okay... What about the second one? I know that the denominator cant equal 0, but what about range??

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1for range find the range of \[\frac{x2}{x+1}\] and then exclude what you would get if \(x=1\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1since in the original function you know \(x\neq 1\)

Study23
 2 years ago
Best ResponseYou've already chosen the best response.0I'm having difficulty finding the range..

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1this thing can never be 1 because a fraction is only one if the numerator and denominator are equal, and in this case they are not

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1other than that, it is all real numbers. so you have only to exclude two values from the range. it cannot be 1 and it cannot be \[\frac{12}{1+1}=\frac{1}{2}\] because you are not allowed to evaluate at \(x=1\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1if you want some more math to do to make your teacher happy, solve for \(x\) in \[y=\frac{x2}{x+1}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1or switch \(x\) and \(y\) and solve for \(y\), either way will do it can you do that algebra?

Study23
 2 years ago
Best ResponseYou've already chosen the best response.0I think I got it now, @satellite73! Thanks so much! I have a Functions Test tomorrow!
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