1. anonymous

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2. anonymous

domain of sine is all real numbers

3. anonymous

range of sine is $$[-1,1]$$ so range of -3 sine is $$[-3,3]$$ no algebra needed for that one

4. anonymous

oh i didn't see the $$+1$$ out at the end. adjust by adding one to get range of $$[-2,4]$$

5. anonymous

How do I find the domain of the sine equation?

6. anonymous

domain of sine is all real numbers, so unless there is some restriction inside, there is no restriction

7. anonymous

domain of $$2x^4-5$$ is all reals, so no worries here

8. anonymous

Okay... What about the second one? I know that the denominator cant equal 0, but what about range??

9. anonymous

for range find the range of $\frac{x-2}{x+1}$ and then exclude what you would get if $$x=1$$

10. anonymous

since in the original function you know $$x\neq 1$$

11. anonymous

I'm having difficulty finding the range..

12. anonymous

this thing can never be 1 because a fraction is only one if the numerator and denominator are equal, and in this case they are not

13. anonymous

other than that, it is all real numbers. so you have only to exclude two values from the range. it cannot be 1 and it cannot be $\frac{1-2}{1+1}=-\frac{1}{2}$ because you are not allowed to evaluate at $$x=1$$

14. anonymous

if you want some more math to do to make your teacher happy, solve for $$x$$ in $y=\frac{x-2}{x+1}$

15. anonymous

or switch $$x$$ and $$y$$ and solve for $$y$$, either way will do it can you do that algebra?

16. anonymous

I think I got it now, @satellite73! Thanks so much! I have a Functions Test tomorrow!

17. anonymous

good luck!