Domain & Range HELP! Please help with two functions. Click here and see the coming soon drawing...UPDATE: Drawing is now available!!!

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- anonymous

- schrodinger

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- anonymous

|dw:1347943151983:dw|

- anonymous

domain of sine is all real numbers

- anonymous

range of sine is \([-1,1]\) so range of -3 sine is \([-3,3]\)
no algebra needed for that one

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## More answers

- anonymous

oh i didn't see the \(+1\) out at the end. adjust by adding one to get range of \([-2,4]\)

- anonymous

How do I find the domain of the sine equation?

- anonymous

domain of sine is all real numbers, so unless there is some restriction inside, there is no restriction

- anonymous

domain of \(2x^4-5\) is all reals, so no worries here

- anonymous

Okay... What about the second one? I know that the denominator cant equal 0, but what about range??

- anonymous

for range find the range of
\[\frac{x-2}{x+1}\] and then exclude what you would get if \(x=1\)

- anonymous

since in the original function you know \(x\neq 1\)

- anonymous

I'm having difficulty finding the range..

- anonymous

this thing can never be 1 because a fraction is only one if the numerator and denominator are equal, and in this case they are not

- anonymous

other than that, it is all real numbers. so you have only to exclude two values from the range.
it cannot be 1 and it cannot be
\[\frac{1-2}{1+1}=-\frac{1}{2}\] because you are not allowed to evaluate at \(x=1\)

- anonymous

if you want some more math to do to make your teacher happy, solve for \(x\) in
\[y=\frac{x-2}{x+1}\]

- anonymous

or switch \(x\) and \(y\) and solve for \(y\), either way will do it
can you do that algebra?

- anonymous

I think I got it now, @satellite73! Thanks so much! I have a Functions Test tomorrow!

- anonymous

good luck!

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