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Domain & Range HELP! Please help with two functions. Click here and see the coming soon drawing...UPDATE: Drawing is now available!!!

Mathematics
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|dw:1347943151983:dw|
domain of sine is all real numbers
range of sine is \([-1,1]\) so range of -3 sine is \([-3,3]\) no algebra needed for that one

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Other answers:

oh i didn't see the \(+1\) out at the end. adjust by adding one to get range of \([-2,4]\)
How do I find the domain of the sine equation?
domain of sine is all real numbers, so unless there is some restriction inside, there is no restriction
domain of \(2x^4-5\) is all reals, so no worries here
Okay... What about the second one? I know that the denominator cant equal 0, but what about range??
for range find the range of \[\frac{x-2}{x+1}\] and then exclude what you would get if \(x=1\)
since in the original function you know \(x\neq 1\)
I'm having difficulty finding the range..
this thing can never be 1 because a fraction is only one if the numerator and denominator are equal, and in this case they are not
other than that, it is all real numbers. so you have only to exclude two values from the range. it cannot be 1 and it cannot be \[\frac{1-2}{1+1}=-\frac{1}{2}\] because you are not allowed to evaluate at \(x=1\)
if you want some more math to do to make your teacher happy, solve for \(x\) in \[y=\frac{x-2}{x+1}\]
or switch \(x\) and \(y\) and solve for \(y\), either way will do it can you do that algebra?
I think I got it now, @satellite73! Thanks so much! I have a Functions Test tomorrow!
good luck!

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