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Domain & Range HELP! Please help with two functions. Click here and see the coming soon drawing...UPDATE: Drawing is now available!!!
 one year ago
 one year ago
Domain & Range HELP! Please help with two functions. Click here and see the coming soon drawing...UPDATE: Drawing is now available!!!
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.1
domain of sine is all real numbers
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
range of sine is \([1,1]\) so range of 3 sine is \([3,3]\) no algebra needed for that one
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
oh i didn't see the \(+1\) out at the end. adjust by adding one to get range of \([2,4]\)
 one year ago

Study23Best ResponseYou've already chosen the best response.0
How do I find the domain of the sine equation?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
domain of sine is all real numbers, so unless there is some restriction inside, there is no restriction
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
domain of \(2x^45\) is all reals, so no worries here
 one year ago

Study23Best ResponseYou've already chosen the best response.0
Okay... What about the second one? I know that the denominator cant equal 0, but what about range??
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
for range find the range of \[\frac{x2}{x+1}\] and then exclude what you would get if \(x=1\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
since in the original function you know \(x\neq 1\)
 one year ago

Study23Best ResponseYou've already chosen the best response.0
I'm having difficulty finding the range..
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
this thing can never be 1 because a fraction is only one if the numerator and denominator are equal, and in this case they are not
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
other than that, it is all real numbers. so you have only to exclude two values from the range. it cannot be 1 and it cannot be \[\frac{12}{1+1}=\frac{1}{2}\] because you are not allowed to evaluate at \(x=1\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
if you want some more math to do to make your teacher happy, solve for \(x\) in \[y=\frac{x2}{x+1}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
or switch \(x\) and \(y\) and solve for \(y\), either way will do it can you do that algebra?
 one year ago

Study23Best ResponseYou've already chosen the best response.0
I think I got it now, @satellite73! Thanks so much! I have a Functions Test tomorrow!
 one year ago
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