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Study23 Group Title

Range on this function!!!!!

  • 2 years ago
  • 2 years ago

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  1. Study23 Group Title
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    |dw:1347947263239:dw|

    • 2 years ago
  2. mukushla Group Title
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    this one is a little bit hard to get...at least for me but i'll do it with \[x=\frac{2}{\cos \theta}\]with \(0<\theta<\pi\)

    • 2 years ago
  3. mukushla Group Title
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    because i know domain is |x|>2

    • 2 years ago
  4. experimentX Group Title
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    is it -2 to inf?

    • 2 years ago
  5. experimentX Group Title
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    looks like there a hole.

    • 2 years ago
  6. mukushla Group Title
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    it becomes\[y=4\frac{\frac{1}{\cos \theta}+1}{|\tan \theta|}\]

    • 2 years ago
  7. Study23 Group Title
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    \(\ cos \theta? \)

    • 2 years ago
  8. mukushla Group Title
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    range is\[(-2,0)\cup (2,\infty)\]

    • 2 years ago
  9. mukushla Group Title
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    yeah \(\cos \theta\) do u know why ?

    • 2 years ago
  10. Study23 Group Title
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    No, I don't

    • 2 years ago
  11. experimentX Group Title
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    oh ... i didn't realize \[ \frac{2 ( \sqrt{x+ 2})^2}{\sqrt{x+2}\sqrt{x-2}}= \frac{2 \sqrt{x+2}}{\sqrt{x-2}}\] there isn't asymptotic behaviour at x=-2

    • 2 years ago
  12. Study23 Group Title
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    ? I don't get the whole cos thing... and where did the 2 come from?

    • 2 years ago
  13. mukushla Group Title
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    wait forgot cos thing...

    • 2 years ago
  14. mukushla Group Title
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    exper got it

    • 2 years ago
  15. experimentX Group Title
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    check for these behaviour on these intervals (-inf, -2), (-2, 2), (2, inf)

    • 2 years ago
  16. Study23 Group Title
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    ? How?

    • 2 years ago
  17. experimentX Group Title
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    the - infinity part is always confusing, don't cancel .... for that. rest is just same as you did.

    • 2 years ago
  18. experimentX Group Title
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    the - infinity part is always confusing, don't cancel to for that. rest is just same as you did.

    • 2 years ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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