anonymous
  • anonymous
Range on this function!!!!!
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1347947263239:dw|
anonymous
  • anonymous
this one is a little bit hard to get...at least for me but i'll do it with \[x=\frac{2}{\cos \theta}\]with \(0<\theta<\pi\)
anonymous
  • anonymous
because i know domain is |x|>2

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experimentX
  • experimentX
is it -2 to inf?
experimentX
  • experimentX
looks like there a hole.
anonymous
  • anonymous
it becomes\[y=4\frac{\frac{1}{\cos \theta}+1}{|\tan \theta|}\]
anonymous
  • anonymous
\(\ cos \theta? \)
anonymous
  • anonymous
range is\[(-2,0)\cup (2,\infty)\]
anonymous
  • anonymous
yeah \(\cos \theta\) do u know why ?
anonymous
  • anonymous
No, I don't
experimentX
  • experimentX
oh ... i didn't realize \[ \frac{2 ( \sqrt{x+ 2})^2}{\sqrt{x+2}\sqrt{x-2}}= \frac{2 \sqrt{x+2}}{\sqrt{x-2}}\] there isn't asymptotic behaviour at x=-2
anonymous
  • anonymous
? I don't get the whole cos thing... and where did the 2 come from?
anonymous
  • anonymous
wait forgot cos thing...
anonymous
  • anonymous
exper got it
experimentX
  • experimentX
check for these behaviour on these intervals (-inf, -2), (-2, 2), (2, inf)
anonymous
  • anonymous
? How?
experimentX
  • experimentX
the - infinity part is always confusing, don't cancel .... for that. rest is just same as you did.
experimentX
  • experimentX
the - infinity part is always confusing, don't cancel to for that. rest is just same as you did.

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