Evaluate: tan105deg using the sum and difference formulas. I

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Evaluate: tan105deg using the sum and difference formulas. I

Mathematics
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tan(a+b)=(tan a +tan b)/(1-tan a tan b)....put a =60 and b =45 and solve
where u got 60 and 45?
tan(60+45)=tan105...right

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Other answers:

can u do it nw
tan 60 =\[\sqrt{3}\] and tan 45 =1
i am getting stuck at the part where it is: |dw:1347964171044:dw|
so \[\tan105= (1+\sqrt{3})/(1-\sqrt{3}) \]
|dw:1347964267571:dw|
can u solve this now
wait. why did you square that?
|dw:1347965085424:dw|
arent you suppposed to mutliply it by the bottom one?
no it is rationalization u multiply num and den both by a coomon value so that the expression remains unaffected
so it is always the numerator?
no depends on what simplifies the root if 1-root 3 was there in numerator and 1+root 3 in den the you would multiply num and den by 1-root 3...since (1+root 3)(1-root3)=1-3...using a^2-b^2
how would you know which one to multiply by tho?
multiply with a value that would make denominator a rational one

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