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  • 3 years ago

Evaluate: tan105deg using the sum and difference formulas. I

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  1. akash_809
    • 3 years ago
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    tan(a+b)=(tan a +tan b)/(1-tan a tan b)....put a =60 and b =45 and solve

  2. ¿Did_You_Know?
    • 3 years ago
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    where u got 60 and 45?

  3. akash_809
    • 3 years ago
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    tan(60+45)=tan105...right

  4. akash_809
    • 3 years ago
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    can u do it nw

  5. akash_809
    • 3 years ago
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    tan 60 =\[\sqrt{3}\] and tan 45 =1

  6. ¿Did_You_Know?
    • 3 years ago
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    i am getting stuck at the part where it is: |dw:1347964171044:dw|

  7. akash_809
    • 3 years ago
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    so \[\tan105= (1+\sqrt{3})/(1-\sqrt{3}) \]

  8. akash_809
    • 3 years ago
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    |dw:1347964267571:dw|

  9. akash_809
    • 3 years ago
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    can u solve this now

  10. ¿Did_You_Know?
    • 3 years ago
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    wait. why did you square that?

  11. akash_809
    • 3 years ago
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    |dw:1347965085424:dw|

  12. ¿Did_You_Know?
    • 3 years ago
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    arent you suppposed to mutliply it by the bottom one?

  13. akash_809
    • 3 years ago
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    no it is rationalization u multiply num and den both by a coomon value so that the expression remains unaffected

  14. ¿Did_You_Know?
    • 3 years ago
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    so it is always the numerator?

  15. akash_809
    • 3 years ago
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    no depends on what simplifies the root if 1-root 3 was there in numerator and 1+root 3 in den the you would multiply num and den by 1-root 3...since (1+root 3)(1-root3)=1-3...using a^2-b^2

  16. ¿Did_You_Know?
    • 3 years ago
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    how would you know which one to multiply by tho?

  17. akash_809
    • 3 years ago
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    multiply with a value that would make denominator a rational one

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