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moongazer Group Title

find the derivative: Y(x) = 1/sqrt x please check my answer :)

  • one year ago
  • one year ago

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  1. moongazer Group Title
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    |dw:1347972647599:dw|

    • one year ago
  2. moongazer Group Title
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    I used the definition

    • one year ago
  3. m_charron2 Group Title
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    Yes, that seems essentially correct. However, I've never seen it written this way. Usually, we group up the Xs, so you'd get this : |dw:1347971974141:dw|

    • one year ago
  4. m_charron2 Group Title
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    or this : |dw:1347971995093:dw|

    • one year ago
  5. moongazer Group Title
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    What is the correct (best) way to right the derivative of a function? isn't it that there should be no radical in the denominator ? that's why I made it that way :)

    • one year ago
  6. mathslover Group Title
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    \[\large{\frac{d}{dx}\frac{1}{\sqrt{x}}}\] \[\large{\frac{d}{dx}{\sqrt{x}^{-1}}}\] \[\large{\frac{d}{dx}x^{-\frac{1}{2}}}\] \[\large{\frac{-1}{2\sqrt{x^3}}}\]

    • one year ago
  7. mathslover Group Title
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    this is what I did. .. well do you mean by rationalizing? @moongazer

    • one year ago
  8. moongazer Group Title
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    yes, do you still need to rationalize it ?

    • one year ago
  9. mathslover Group Title
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    If u will then it will look ugly.. let it be in this way

    • one year ago
  10. ParthKohli Group Title
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    Yeah, you may rationalize if you need.

    • one year ago
  11. ParthKohli Group Title
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    Rationalizing beautifies the fraction; it doesn't make it ugly. lol

    • one year ago
  12. mathslover Group Title
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    or u can right : \[\large{\frac{-1}{2x^{\frac{3}{2}}}}\]

    • one year ago
  13. mathslover Group Title
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    lol \[\large{\frac{-1\times x^{\frac{3}{2}}}{2x^3}}\]

    • one year ago
  14. mathslover Group Title
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    \[\large{\frac{-\sqrt{x^3}}{2x^3}}\] @moongazer

    • one year ago
  15. mathslover Group Title
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    got it @moongazer ?

    • one year ago
  16. moongazer Group Title
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    yes, based on your answers, Does it mean that you can write the derivative of a function in anyway you like as long as it doesn't change the meaning of your derivative? it could be in exponential,rationalized, not rationalized or any other forms.

    • one year ago
  17. moongazer Group Title
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    @mathslover

    • one year ago
  18. mathslover Group Title
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    yes

    • one year ago
  19. moongazer Group Title
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    Thanks :)

    • one year ago
  20. m_charron2 Group Title
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    Also, if you choose to keep it simply as \[\frac{ -1 }{ 2x^{3/2} }\] is that it makes it simpler if you need to find its derivative after that (because sometimes, they just love to have you chain-derive something)

    • one year ago
  21. moongazer Group Title
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    Thanks for the info :)

    • one year ago
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