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zaphod
Group Title
Find the equation of the normal to the curve y = 3x^22x1 which parellel to the line y = x3
 2 years ago
 2 years ago
zaphod Group Title
Find the equation of the normal to the curve y = 3x^22x1 which parellel to the line y = x3
 2 years ago
 2 years ago

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zaphod Group TitleBest ResponseYou've already chosen the best response.0
@sauravshakya @TuringTest @satellite73
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
find y', set it equal to 1 and solve for x; that's an x coord. on your line. plug into y = 3x^22x1to get a y coord. you have a point and the slope now.. find the line?
 2 years ago

myko Group TitleBest ResponseYou've already chosen the best response.0
1º. Find the derivative of y 2º Put it in some form you like (slope intercept, general...) 3º change it's direction vector to perpendicular 4º find x, for which it's slope is 1
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
i got the points, why is the slope 1, it has to be 1 since we take the normal line?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
if slope of the tangent = 1, slope of the normal =1.
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
can u show it in a diagram?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
dw:1347988256856:dw
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
i cant picture the problem clearly?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic! where the parellel like y=x3?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
can u show the parellel line y =x3 in the diagram?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
dw:1347988441351:dw
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
this was just a general sketch to illustrate the point. this isn't your parabola. but that's the line x3 in black
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
why cant we directly get the gradient as m=1 instead of 1
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
try it and see
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
im getting a different answer and the answer is wrong
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
what's your answer?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
dy/dx= 6x  2 6x  2 = 1 x= 1/2 y= 5/4
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
cn u shw the working
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
find y', set it equal to 1 and solve for x; that's an x coord. on your line. plug into y = 3x^22x1to get a y coord. you have a point and the slope now.. find the line?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
why do we set it equal to 1 instead of 1?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
you don't like negative one so you went with one instead? and got the wrong answer?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
when the tangent to the parabola has a slope of 1, the normal at that point has a slope of 1
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
i got it thanks :)
 2 years ago
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