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Find the equation of the normal to the curve y = 3x^22x1 which parellel to the line y = x3
 one year ago
 one year ago
Find the equation of the normal to the curve y = 3x^22x1 which parellel to the line y = x3
 one year ago
 one year ago

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zaphodBest ResponseYou've already chosen the best response.0
@sauravshakya @TuringTest @satellite73
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.2
find y', set it equal to 1 and solve for x; that's an x coord. on your line. plug into y = 3x^22x1to get a y coord. you have a point and the slope now.. find the line?
 one year ago

mykoBest ResponseYou've already chosen the best response.0
1º. Find the derivative of y 2º Put it in some form you like (slope intercept, general...) 3º change it's direction vector to perpendicular 4º find x, for which it's slope is 1
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
i got the points, why is the slope 1, it has to be 1 since we take the normal line?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.2
if slope of the tangent = 1, slope of the normal =1.
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
can u show it in a diagram?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.2
dw:1347988256856:dw
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
i cant picture the problem clearly?
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
@Algebraic! where the parellel like y=x3?
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
can u show the parellel line y =x3 in the diagram?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.2
dw:1347988441351:dw
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.2
this was just a general sketch to illustrate the point. this isn't your parabola. but that's the line x3 in black
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
why cant we directly get the gradient as m=1 instead of 1
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
im getting a different answer and the answer is wrong
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.2
what's your answer?
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
dy/dx= 6x  2 6x  2 = 1 x= 1/2 y= 5/4
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.2
find y', set it equal to 1 and solve for x; that's an x coord. on your line. plug into y = 3x^22x1to get a y coord. you have a point and the slope now.. find the line?
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
why do we set it equal to 1 instead of 1?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.2
you don't like negative one so you went with one instead? and got the wrong answer?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.2
when the tangent to the parabola has a slope of 1, the normal at that point has a slope of 1
 one year ago
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