anonymous
  • anonymous
Find the equation of the normal to the curve y = 3x^2-2x-1 which parellel to the line y = x-3
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
@sauravshakya @TuringTest @satellite73
anonymous
  • anonymous
find y', set it equal to -1 and solve for x; that's an x coord. on your line. plug into y = 3x^2-2x-1to get a y coord. you have a point and the slope now.. find the line?
anonymous
  • anonymous
1º. Find the derivative of y 2º Put it in some form you like (slope intercept, general...) 3º change it's direction vector to perpendicular 4º find x, for which it's slope is 1

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anonymous
  • anonymous
i got the points, why is the slope 1, it has to be -1 since we take the normal line?
anonymous
  • anonymous
if slope of the tangent = -1, slope of the normal =1.
anonymous
  • anonymous
can u show it in a diagram?
anonymous
  • anonymous
|dw:1347988256856:dw|
anonymous
  • anonymous
i cant picture the problem clearly?
anonymous
  • anonymous
@Algebraic! where the parellel like y=x-3?
anonymous
  • anonymous
wut
anonymous
  • anonymous
can u show the parellel line y =x-3 in the diagram?
anonymous
  • anonymous
|dw:1347988441351:dw|
anonymous
  • anonymous
this was just a general sketch to illustrate the point. this isn't your parabola. but that's the line x-3 in black
anonymous
  • anonymous
why cant we directly get the gradient as m=1 instead of -1
anonymous
  • anonymous
try it and see
anonymous
  • anonymous
im getting a different answer and the answer is wrong
anonymous
  • anonymous
what's your answer?
anonymous
  • anonymous
4y =2x-5
anonymous
  • anonymous
dy/dx= 6x - 2 6x - 2 = 1 x= 1/2 y= -5/4
anonymous
  • anonymous
cn u shw the working
anonymous
  • anonymous
find y', set it equal to -1 and solve for x; that's an x coord. on your line. plug into y = 3x^2-2x-1to get a y coord. you have a point and the slope now.. find the line?
anonymous
  • anonymous
why do we set it equal to -1 instead of 1?
anonymous
  • anonymous
you don't like negative one so you went with one instead? and got the wrong answer?
anonymous
  • anonymous
when the tangent to the parabola has a slope of -1, the normal at that point has a slope of 1
anonymous
  • anonymous
i got it thanks :)

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