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anonymous
 4 years ago
Find the equation of the normal to the curve y = 3x^22x1 which parellel to the line y = x3
anonymous
 4 years ago
Find the equation of the normal to the curve y = 3x^22x1 which parellel to the line y = x3

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya @TuringTest @satellite73

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find y', set it equal to 1 and solve for x; that's an x coord. on your line. plug into y = 3x^22x1to get a y coord. you have a point and the slope now.. find the line?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01º. Find the derivative of y 2º Put it in some form you like (slope intercept, general...) 3º change it's direction vector to perpendicular 4º find x, for which it's slope is 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got the points, why is the slope 1, it has to be 1 since we take the normal line?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if slope of the tangent = 1, slope of the normal =1.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u show it in a diagram?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1347988256856:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i cant picture the problem clearly?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Algebraic! where the parellel like y=x3?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u show the parellel line y =x3 in the diagram?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1347988441351:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this was just a general sketch to illustrate the point. this isn't your parabola. but that's the line x3 in black

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why cant we directly get the gradient as m=1 instead of 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im getting a different answer and the answer is wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dy/dx= 6x  2 6x  2 = 1 x= 1/2 y= 5/4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find y', set it equal to 1 and solve for x; that's an x coord. on your line. plug into y = 3x^22x1to get a y coord. you have a point and the slope now.. find the line?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why do we set it equal to 1 instead of 1?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you don't like negative one so you went with one instead? and got the wrong answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when the tangent to the parabola has a slope of 1, the normal at that point has a slope of 1
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