A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
anonymous
 4 years ago
Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each?
anonymous
 4 years ago
Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0tony is 16, belinda is 40

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1let tony's age be x. so Belindas age = 56x. Belinda is 8 more than twice Tony’s age. so 56x = 2x+8 can u solve this and find x ?

farmdawgnation
 4 years ago
Best ResponseYou've already chosen the best response.0@Turner Please provide more than just the answer. Try to work with the asker as hartnn has.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.056  8 = 48 48 / 3 = 16 (tony's age) 16 x 2 + 8 = 40 (belinda's age)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.