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\[(x-8)(x-k) = x^{2} -5kx + m\]

simplify the left side:
x^2 - kx - 8x + 8k = x^2 - (k+8)x + 8k

x^2 - (k+8)x + 8k = x^2 - 5kx + m

thus you know that k+8 = 5k

and 8k = m

just what bahrom said

Now just solve for both.

bahrom mate can ya help me out with a sum of my own??

@robinfr93 let me see the question

@bahrom7893 What does it mean by true for all values of x?

I don't see how you got k+8 = 5k Where did everything else go?

it just means equate the two equations.

I'm equating the coefficients:
x^2 - (k+8)x + 8k = x^2 - 5kx + m

|dw:1347995814720:dw|

|dw:1347995848017:dw|

for those two equations to be equal to each other for all x, k+8 has to equal 5k and 8k must equal m

Could it go the other way around? Like (k+8) = m? @bahrom7893

No it couldn't, since x coefficients have to equal to corresponding x coefficients

k+8 is coefficient of x^1, and so is 5k
both 8k and m are coefficients of x^0

Ohhhh I see now ok ok thanks