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Ok i understood it finally in regular problems but they had to go and give me a word problem and im confused now i thought i started it right but when i keep working through it i get no answers that match the possible ones
 one year ago
 one year ago
Ok i understood it finally in regular problems but they had to go and give me a word problem and im confused now i thought i started it right but when i keep working through it i get no answers that match the possible ones
 one year ago
 one year ago

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gdogthegirlBest ResponseYou've already chosen the best response.0
Gina, Sam and Robby all rented movies from the same video store. They each rented some dramas, comedies and documentaries. Gina rented 11 movies total. Sam rented twice as many dramas, three times as many comedies, and twice as many documentaries as Gina. He rented 27 movies total. If Robby rented 19 movies total with the same number of dramas, twice as many comedies, and twice as many documentaries as Gina, how many movies of each type did Gina rent? 3 dramas, 5 comedies and 3 documentaries 2 dramas, 6 comedies and 3 documentaries 1 dramas, 4 comedies and 6 documentaries 4 dramas, 3 comedies and 4 documentaries
 one year ago

gdogthegirlBest ResponseYou've already chosen the best response.0
I have to use substitution or elimnation
 one year ago

gdogthegirlBest ResponseYou've already chosen the best response.0
i started out with these equations from it : a+b+c=11 2a+3b+2c=27 a+2b+2c=19 but, im not sure if these are right or not
 one year ago

gdogthegirlBest ResponseYou've already chosen the best response.0
Or at least tell me if i started it off right with those equations ^^^^
 one year ago

trackzzBest ResponseYou've already chosen the best response.1
Let x represent the number of dramas Let y represent the number of comedies Let z represent the number of documentaries Gina: x + y + z = 11 Sam: 2x + 3y + 2z = 27 Robby: x + 2y +2z = 19
 one year ago

gdogthegirlBest ResponseYou've already chosen the best response.0
a basically used a b and c but ok
 one year ago

trackzzBest ResponseYou've already chosen the best response.1
Rearrange the first equation for x: x = 11  y  z
 one year ago

trackzzBest ResponseYou've already chosen the best response.1
After rearranging you can put this equation in (2) or (3) and eliminate for y or z. Substitute x = 11  y  z into (2) 2(11  y  z) + 3y + 2z = 27 22  2y  2z + 3y + 2z = 27 y = 27  22 y = 5 YAY that's the value of y :P Substitute y = 5 into (1) x + y + z = 11 x + 5 + z = 11 x + z = 6 x = 6  z Substitute x = 6  z and y = 5 into (3) x + 2y + 2z = 19 6  z + 2y + 2z = 19 2y + z = 13 z = 13  2y z = 13  2(5) z = 3 There's your "z" value Substitute y = 5 and z = 3 into (1) to solve for x x + y + z = 11 x + 5 + 3 = 11 x = 11  8 x = 3 Check if your values satisfy the equation: LS = 2x + 3y + 2z = 2(3) + 3(5) + 2(3) = 6 + 15 + 6 = 27 RS = 27 Since LS = RS, the values of x, y and z satisfy the equation. Therefore, x = 3, y = 5 and z = 3. WELL?
 one year ago

gdogthegirlBest ResponseYou've already chosen the best response.0
wow thank you so much
 one year ago

trackzzBest ResponseYou've already chosen the best response.1
ahah no problem. my back hurts now
 one year ago

gdogthegirlBest ResponseYou've already chosen the best response.0
ok and that is what some good ole ibuprofen is for
 one year ago
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