anonymous
  • anonymous
Ok i understood it finally in regular problems but they had to go and give me a word problem and im confused now i thought i started it right but when i keep working through it i get no answers that match the possible ones
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Gina, Sam and Robby all rented movies from the same video store. They each rented some dramas, comedies and documentaries. Gina rented 11 movies total. Sam rented twice as many dramas, three times as many comedies, and twice as many documentaries as Gina. He rented 27 movies total. If Robby rented 19 movies total with the same number of dramas, twice as many comedies, and twice as many documentaries as Gina, how many movies of each type did Gina rent? 3 dramas, 5 comedies and 3 documentaries 2 dramas, 6 comedies and 3 documentaries 1 dramas, 4 comedies and 6 documentaries 4 dramas, 3 comedies and 4 documentaries
anonymous
  • anonymous
I have to use substitution or elimnation
anonymous
  • anonymous
i started out with these equations from it : a+b+c=11 2a+3b+2c=27 a+2b+2c=19 but, im not sure if these are right or not

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anonymous
  • anonymous
Or at least tell me if i started it off right with those equations ^^^^
anonymous
  • anonymous
Let x represent the number of dramas Let y represent the number of comedies Let z represent the number of documentaries Gina: x + y + z = 11 Sam: 2x + 3y + 2z = 27 Robby: x + 2y +2z = 19
anonymous
  • anonymous
a basically used a b and c but ok
anonymous
  • anonymous
Rearrange the first equation for x: x = 11 - y - z
anonymous
  • anonymous
ok
anonymous
  • anonymous
After rearranging you can put this equation in (2) or (3) and eliminate for y or z. Substitute x = 11 - y - z into (2) 2(11 - y - z) + 3y + 2z = 27 22 - 2y - 2z + 3y + 2z = 27 y = 27 - 22 y = 5 YAY that's the value of y :P Substitute y = 5 into (1) x + y + z = 11 x + 5 + z = 11 x + z = 6 x = 6 - z Substitute x = 6 - z and y = 5 into (3) x + 2y + 2z = 19 6 - z + 2y + 2z = 19 2y + z = 13 z = 13 - 2y z = 13 - 2(5) z = 3 There's your "z" value Substitute y = 5 and z = 3 into (1) to solve for x x + y + z = 11 x + 5 + 3 = 11 x = 11 - 8 x = 3 Check if your values satisfy the equation: LS = 2x + 3y + 2z = 2(3) + 3(5) + 2(3) = 6 + 15 + 6 = 27 RS = 27 Since LS = RS, the values of x, y and z satisfy the equation. Therefore, x = 3, y = 5 and z = 3. WELL?
anonymous
  • anonymous
wow thank you so much
anonymous
  • anonymous
ahah no problem. my back hurts now
anonymous
  • anonymous
awe im sorry :(
anonymous
  • anonymous
aha no worries.
anonymous
  • anonymous
ok and that is what some good ole ibuprofen is for
anonymous
  • anonymous
huh, yeah sure. :P

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