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gdogthegirl Group Title

Ok i understood it finally in regular problems but they had to go and give me a word problem and im confused now i thought i started it right but when i keep working through it i get no answers that match the possible ones

  • one year ago
  • one year ago

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  1. gdogthegirl Group Title
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    Gina, Sam and Robby all rented movies from the same video store. They each rented some dramas, comedies and documentaries. Gina rented 11 movies total. Sam rented twice as many dramas, three times as many comedies, and twice as many documentaries as Gina. He rented 27 movies total. If Robby rented 19 movies total with the same number of dramas, twice as many comedies, and twice as many documentaries as Gina, how many movies of each type did Gina rent? 3 dramas, 5 comedies and 3 documentaries 2 dramas, 6 comedies and 3 documentaries 1 dramas, 4 comedies and 6 documentaries 4 dramas, 3 comedies and 4 documentaries

    • one year ago
  2. gdogthegirl Group Title
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    I have to use substitution or elimnation

    • one year ago
  3. gdogthegirl Group Title
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    i started out with these equations from it : a+b+c=11 2a+3b+2c=27 a+2b+2c=19 but, im not sure if these are right or not

    • one year ago
  4. gdogthegirl Group Title
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    Or at least tell me if i started it off right with those equations ^^^^

    • one year ago
  5. trackzz Group Title
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    Let x represent the number of dramas Let y represent the number of comedies Let z represent the number of documentaries Gina: x + y + z = 11 Sam: 2x + 3y + 2z = 27 Robby: x + 2y +2z = 19

    • one year ago
  6. gdogthegirl Group Title
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    a basically used a b and c but ok

    • one year ago
  7. trackzz Group Title
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    Rearrange the first equation for x: x = 11 - y - z

    • one year ago
  8. gdogthegirl Group Title
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    ok

    • one year ago
  9. trackzz Group Title
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    After rearranging you can put this equation in (2) or (3) and eliminate for y or z. Substitute x = 11 - y - z into (2) 2(11 - y - z) + 3y + 2z = 27 22 - 2y - 2z + 3y + 2z = 27 y = 27 - 22 y = 5 YAY that's the value of y :P Substitute y = 5 into (1) x + y + z = 11 x + 5 + z = 11 x + z = 6 x = 6 - z Substitute x = 6 - z and y = 5 into (3) x + 2y + 2z = 19 6 - z + 2y + 2z = 19 2y + z = 13 z = 13 - 2y z = 13 - 2(5) z = 3 There's your "z" value Substitute y = 5 and z = 3 into (1) to solve for x x + y + z = 11 x + 5 + 3 = 11 x = 11 - 8 x = 3 Check if your values satisfy the equation: LS = 2x + 3y + 2z = 2(3) + 3(5) + 2(3) = 6 + 15 + 6 = 27 RS = 27 Since LS = RS, the values of x, y and z satisfy the equation. Therefore, x = 3, y = 5 and z = 3. WELL?

    • one year ago
  10. gdogthegirl Group Title
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    wow thank you so much

    • one year ago
  11. trackzz Group Title
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    ahah no problem. my back hurts now

    • one year ago
  12. gdogthegirl Group Title
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    awe im sorry :(

    • one year ago
  13. trackzz Group Title
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    aha no worries.

    • one year ago
  14. gdogthegirl Group Title
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    ok and that is what some good ole ibuprofen is for

    • one year ago
  15. trackzz Group Title
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    huh, yeah sure. :P

    • one year ago
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