anonymous
  • anonymous
What is the derivative of: (secu)^(n-2)? Is it (n-2)(secu)^(n-3) tanu?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
n is an integer
anonymous
  • anonymous
hi. oh, ok
anonymous
  • anonymous
what about u?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
just a variable
anonymous
  • anonymous
not a function of x?
anonymous
  • anonymous
ok, u is not a function of x, then i think you are gonna want to check the exponent of sec u
anonymous
  • anonymous
still there?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
i got it
anonymous
  • anonymous
in case you get this, everything looks ok except the exponent on sec u. the n-2 out front is good, the sec^(n-3) times the sec u tan u (chain rule) is what is affecting the exponent
anonymous
  • anonymous
do you see what the exponent is now for sec u?
anonymous
  • anonymous
it's n-3 no?
anonymous
  • anonymous
the n-2 in front is correct. you also have product of secu^(n-3) and then there is the chain rule that multiplies by secutanu. so, it is not n-3
anonymous
  • anonymous
do you see what i am trying to point out? feel free to ask any questions
anonymous
  • anonymous
are you still having difficulty?
anonymous
  • anonymous
oh pellet
anonymous
  • anonymous
you are correct
anonymous
  • anonymous
it would still be sec^(n-2)
anonymous
  • anonymous
niiice
anonymous
  • anonymous
(n-2)(secu)^(n-3) times secutanu which equals (n-2)(secu)^(n-2) times tanu
anonymous
  • anonymous
very cool you got it
anonymous
  • anonymous
now i have to rewrite this wholeeeeeeeeeee thing......... thanks
anonymous
  • anonymous
dontcha just hate the whole rewriting thing? If there is nothing else i can help with, i will bid you adieu
anonymous
  • anonymous
take care

Looking for something else?

Not the answer you are looking for? Search for more explanations.