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What is the derivative of: (secu)^(n-2)? Is it (n-2)(secu)^(n-3) tanu?

Mathematics
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n is an integer
hi. oh, ok
what about u?

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Other answers:

just a variable
not a function of x?
ok, u is not a function of x, then i think you are gonna want to check the exponent of sec u
still there?
yeah
i got it
in case you get this, everything looks ok except the exponent on sec u. the n-2 out front is good, the sec^(n-3) times the sec u tan u (chain rule) is what is affecting the exponent
do you see what the exponent is now for sec u?
it's n-3 no?
the n-2 in front is correct. you also have product of secu^(n-3) and then there is the chain rule that multiplies by secutanu. so, it is not n-3
do you see what i am trying to point out? feel free to ask any questions
are you still having difficulty?
oh pellet
you are correct
it would still be sec^(n-2)
niiice
(n-2)(secu)^(n-3) times secutanu which equals (n-2)(secu)^(n-2) times tanu
very cool you got it
now i have to rewrite this wholeeeeeeeeeee thing......... thanks
dontcha just hate the whole rewriting thing? If there is nothing else i can help with, i will bid you adieu
take care

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