jaersyn

What is the derivative of:
(secu)^(n-2)?
Is it (n-2)(secu)^(n-3) tanu?

Delete
Share
This Question is Closed

jaersyn

Best Response

You've already chosen the best response.

1
n is an integer

hsmt

Best Response

You've already chosen the best response.

1
hi. oh, ok

hsmt

Best Response

You've already chosen the best response.

1
what about u?

jaersyn

Best Response

You've already chosen the best response.

1
just a variable

hsmt

Best Response

You've already chosen the best response.

1
not a function of x?

hsmt

Best Response

You've already chosen the best response.

1
ok, u is not a function of x, then i think you are gonna want to check the exponent of sec u

hsmt

Best Response

You've already chosen the best response.

1
still there?

jaersyn

Best Response

You've already chosen the best response.

1
yeah

jaersyn

Best Response

You've already chosen the best response.

1
i got it

hsmt

Best Response

You've already chosen the best response.

1
in case you get this, everything looks ok except the exponent on sec u. the n-2 out front is good, the sec^(n-3) times the sec u tan u (chain rule) is what is affecting the exponent

hsmt

Best Response

You've already chosen the best response.

1
do you see what the exponent is now for sec u?

jaersyn

Best Response

You've already chosen the best response.

1
it's n-3 no?

hsmt

Best Response

You've already chosen the best response.

1
the n-2 in front is correct. you also have product of secu^(n-3) and then there is the chain rule that multiplies by secutanu. so, it is not n-3

hsmt

Best Response

You've already chosen the best response.

1
do you see what i am trying to point out?
feel free to ask any questions

hsmt

Best Response

You've already chosen the best response.

1
are you still having difficulty?

jaersyn

Best Response

You've already chosen the best response.

1
oh pellet

jaersyn

Best Response

You've already chosen the best response.

1
you are correct

jaersyn

Best Response

You've already chosen the best response.

1
it would still be sec^(n-2)

hsmt

Best Response

You've already chosen the best response.

1
niiice

jaersyn

Best Response

You've already chosen the best response.

1
(n-2)(secu)^(n-3) times secutanu which equals (n-2)(secu)^(n-2) times tanu

hsmt

Best Response

You've already chosen the best response.

1
very cool
you got it

jaersyn

Best Response

You've already chosen the best response.

1
now i have to rewrite this wholeeeeeeeeeee thing......... thanks

hsmt

Best Response

You've already chosen the best response.

1
dontcha just hate the whole rewriting thing? If there is nothing else i can help with, i will bid you adieu

hsmt

Best Response

You've already chosen the best response.

1
take care