Here's the question you clicked on:
omgitsana
calculus: f(x)=(sin(x+1)/(x+1). does it have a vertical asymptote or a removeable discontinuity at x=-1??
Well, how do you think you should start this problem?
well my main concern is idk if you can cancel the x+1 out
Of course you can't. Find the limits manually.
Or, you can use l'hopital's rule given that you have learned it.
cannot cancel because it is not the exact same!!!
and, here's a hint: sin(a+b)=sin(a)cos(b)+sin(b)cos(a)
oh ok so it has vertical asymp?
Find the left and right hand limits. Are they the same?
\[\lim_{x \rightarrow -1^-}=\lim_{x \rightarrow -1^+}\] is what I'm asking here.