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ksandoval

  • 2 years ago

how do you find the limit of this (attached) algebraically?

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  1. robinfr93
    • 2 years ago
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    attached??

  2. ksandoval
    • 2 years ago
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    \[\lim_{x \rightarrow \pm \infty} \frac{ x^4 + x^3 }{ 12x^3 + 128 }\]

  3. satellite73
    • 2 years ago
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    numerator is larger than the denominator, so no limit or you could say \(\infty\) as \(x\to \infty\) and \(-\infty\) as \(x\to -\infty\)

  4. jamesumner93
    • 2 years ago
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    you can see that the top gets larger faster than the bottom so it is either going to be positive infinity or negative infinity, depending on if your taking the limit as x approaches infinity or negative infinity respectively

  5. ksandoval
    • 2 years ago
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    oh. thats all you do? okay! so what if the denominator was larger?

  6. jamesumner93
    • 2 years ago
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    then it would be 0

  7. jamesumner93
    • 2 years ago
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    because it would be like 1/2 , 1/4. 1/8, 1/16. 1/32, 1/64 (closer and closer to 0)

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