samalami
Pre Calc: For what value of k will the graph of 6x + ky = 6 be perpendiculuar to the graph of 2x – 6y = 12?
A.1/2
B.)4
C.)2
D.)5



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lgbasallote
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first...solve for y in terms of x in 2x  6y = 12
do you know how?

samalami
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@lgbasallote y=x/32 correct?

lgbasallote
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right

lgbasallote
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now...solve for y in terms of x in 6x + ky = 6

samalami
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y=6/k6x/k

samalami
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@lgbasallote

lgbasallote
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right. so that has a slope of 6/k
for it to be perpendicular to y = x/3  2, the slope should be 3
agree?

samalami
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@lgbasallote yessss

lgbasallote
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wait... i saw wrong

lgbasallote
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the slope of that equation is 6/k

lgbasallote
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so now.. equate 6/k to 3 and solve for k \[\huge \frac 6k = 3\]

samalami
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k=2 @lgbasallote thank you <3

lgbasallote
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3
welcome