## samalami Group Title Pre Calc: For what value of k will the graph of 6x + ky = 6 be perpendiculuar to the graph of 2x – 6y = 12? A.1/2 B.)4 C.)2 D.)5 one year ago one year ago

1. lgbasallote Group Title

first...solve for y in terms of x in 2x - 6y = 12 do you know how?

2. samalami Group Title

@lgbasallote y=x/3-2 correct?

3. lgbasallote Group Title

right

4. lgbasallote Group Title

now...solve for y in terms of x in 6x + ky = 6

5. samalami Group Title

y=6/k-6x/k

6. samalami Group Title

@lgbasallote

7. lgbasallote Group Title

right. so that has a slope of 6/k for it to be perpendicular to y = x/3 - 2, the slope should be -3 agree?

8. samalami Group Title

@lgbasallote yessss

9. lgbasallote Group Title

wait... i saw wrong

10. lgbasallote Group Title

the slope of that equation is -6/k

11. lgbasallote Group Title

so now.. equate -6/k to -3 and solve for k $\huge -\frac 6k = -3$

12. samalami Group Title

k=2 @lgbasallote thank you <3

13. lgbasallote Group Title

welcome