Pre Calc: For what value of k will the graph of 6x + ky = 6 be perpendiculuar to the graph of 2x – 6y = 12? A.1/2 B.)4 C.)2 D.)5

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Pre Calc: For what value of k will the graph of 6x + ky = 6 be perpendiculuar to the graph of 2x – 6y = 12? A.1/2 B.)4 C.)2 D.)5

Mathematics
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first...solve for y in terms of x in 2x - 6y = 12 do you know how?
@lgbasallote y=x/3-2 correct?
right

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now...solve for y in terms of x in 6x + ky = 6
y=6/k-6x/k
right. so that has a slope of 6/k for it to be perpendicular to y = x/3 - 2, the slope should be -3 agree?
wait... i saw wrong
the slope of that equation is -6/k
so now.. equate -6/k to -3 and solve for k \[\huge -\frac 6k = -3\]
k=2 @lgbasallote thank you <3
welcome

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