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samalami
Group Title
Pre Calc: For what value of k will the graph of 6x + ky = 6 be perpendiculuar to the graph of 2x – 6y = 12?
A.1/2
B.)4
C.)2
D.)5
 one year ago
 one year ago
samalami Group Title
Pre Calc: For what value of k will the graph of 6x + ky = 6 be perpendiculuar to the graph of 2x – 6y = 12? A.1/2 B.)4 C.)2 D.)5
 one year ago
 one year ago

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lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
first...solve for y in terms of x in 2x  6y = 12 do you know how?
 one year ago

samalami Group TitleBest ResponseYou've already chosen the best response.1
@lgbasallote y=x/32 correct?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
now...solve for y in terms of x in 6x + ky = 6
 one year ago

samalami Group TitleBest ResponseYou've already chosen the best response.1
y=6/k6x/k
 one year ago

samalami Group TitleBest ResponseYou've already chosen the best response.1
@lgbasallote
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
right. so that has a slope of 6/k for it to be perpendicular to y = x/3  2, the slope should be 3 agree?
 one year ago

samalami Group TitleBest ResponseYou've already chosen the best response.1
@lgbasallote yessss
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
wait... i saw wrong
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
the slope of that equation is 6/k
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
so now.. equate 6/k to 3 and solve for k \[\huge \frac 6k = 3\]
 one year ago

samalami Group TitleBest ResponseYou've already chosen the best response.1
k=2 @lgbasallote thank you <3
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.2
welcome
 one year ago
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