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samalami Group Title

Pre Calc: For what value of k will the graph of 6x + ky = 6 be perpendiculuar to the graph of 2x – 6y = 12? A.1/2 B.)4 C.)2 D.)5

  • one year ago
  • one year ago

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  1. lgbasallote Group Title
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    first...solve for y in terms of x in 2x - 6y = 12 do you know how?

    • one year ago
  2. samalami Group Title
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    @lgbasallote y=x/3-2 correct?

    • one year ago
  3. lgbasallote Group Title
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    right

    • one year ago
  4. lgbasallote Group Title
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    now...solve for y in terms of x in 6x + ky = 6

    • one year ago
  5. samalami Group Title
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    y=6/k-6x/k

    • one year ago
  6. samalami Group Title
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    @lgbasallote

    • one year ago
  7. lgbasallote Group Title
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    right. so that has a slope of 6/k for it to be perpendicular to y = x/3 - 2, the slope should be -3 agree?

    • one year ago
  8. samalami Group Title
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    @lgbasallote yessss

    • one year ago
  9. lgbasallote Group Title
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    wait... i saw wrong

    • one year ago
  10. lgbasallote Group Title
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    the slope of that equation is -6/k

    • one year ago
  11. lgbasallote Group Title
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    so now.. equate -6/k to -3 and solve for k \[\huge -\frac 6k = -3\]

    • one year ago
  12. samalami Group Title
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    k=2 @lgbasallote thank you <3

    • one year ago
  13. lgbasallote Group Title
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    welcome

    • one year ago
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