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samalami

  • 3 years ago

Pre Calc: For what value of k will the graph of 6x + ky = 6 be perpendiculuar to the graph of 2x – 6y = 12? A.1/2 B.)4 C.)2 D.)5

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  1. lgbasallote
    • 3 years ago
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    first...solve for y in terms of x in 2x - 6y = 12 do you know how?

  2. samalami
    • 3 years ago
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    @lgbasallote y=x/3-2 correct?

  3. lgbasallote
    • 3 years ago
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    right

  4. lgbasallote
    • 3 years ago
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    now...solve for y in terms of x in 6x + ky = 6

  5. samalami
    • 3 years ago
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    y=6/k-6x/k

  6. samalami
    • 3 years ago
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    @lgbasallote

  7. lgbasallote
    • 3 years ago
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    right. so that has a slope of 6/k for it to be perpendicular to y = x/3 - 2, the slope should be -3 agree?

  8. samalami
    • 3 years ago
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    @lgbasallote yessss

  9. lgbasallote
    • 3 years ago
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    wait... i saw wrong

  10. lgbasallote
    • 3 years ago
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    the slope of that equation is -6/k

  11. lgbasallote
    • 3 years ago
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    so now.. equate -6/k to -3 and solve for k \[\huge -\frac 6k = -3\]

  12. samalami
    • 3 years ago
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    k=2 @lgbasallote thank you <3

  13. lgbasallote
    • 3 years ago
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    welcome

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