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kimmy0394

  • 2 years ago

find limit as x approaches infinity sqrt. (x+3) / sqrt. (3x+1)

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  1. completeidiot
    • 2 years ago
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    \[\lim_{x \rightarrow \infty}\frac{\sqrt{x+3}}{\sqrt{3x+1}}=\lim_{x \rightarrow \infty}\sqrt{\frac{x+3}{3x+1}}\]

  2. completeidiot
    • 2 years ago
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    now just look at the expression within the square root \[\lim_{x \rightarrow \infty}\frac{{x+3}}{{3x+1}}\] remember that it is all under a square root, so if the limit of that is negative, then there is no solution because you cant take the square root of a negative number

  3. completeidiot
    • 2 years ago
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    can you solve it now?

  4. kimmy0394
    • 2 years ago
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    i thought it was 1/3 but it's not

  5. cinar
    • 2 years ago
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    |dw:1348034899805:dw|

  6. kimmy0394
    • 2 years ago
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    ohhhhhhhhhh!

  7. cinar
    • 2 years ago
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    (:

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