A community for students.

    Here's the question you clicked on:

    55 members online
    • 0 replying
    • 0 viewing


    • 3 years ago

    You find a compound composed only of element "X" and hydrogen, and know that it is 91.26% element X by mass. Each molecule has 2.67 times as many H atoms as X atoms. What is element X?

    • This Question is Closed
    1. JFraser
      • 3 years ago
      Best Response
      You've already chosen the best response.
      Medals 0

      Since you know the ratio of atoms, you can start to put a formula togeter. The formula might look like:\[XH_{2.67}\] but since atoms can't come in fractional amounts, we have to multiply the formula by some number in order to turn 2.67 into a whole #, while still maintaining the ratio. Multiplying 2.67 by 3 yields 8, so the most likely ratio in the molecule is \[X_3H_8\]so the ratio of 1:2.67 is still maintained. The mass percent tells you that out of every 100g of compound, 91.26g is element X, so the other 8.74g must be H. Dividing each mass by the number of moles in the formula gets us the molar mass of each element (approximately). DIviding 8.74g by 8 gets 1.09, roughly the molar mass of hydrogen. Dividing 91.26g by 3 gets us 30.4, roughly the molar mass of phosphorus. Element X is most likely phosphorus

    2. Not the answer you are looking for?
      Search for more explanations.

      • Attachments:

    Ask your own question

    Sign Up
    Find more explanations on OpenStudy
    Privacy Policy

    Your question is ready. Sign up for free to start getting answers.

    spraguer (Moderator)
    5 → View Detailed Profile

    is replying to Can someone tell me what button the professor is hitting...


    • Teamwork 19 Teammate
    • Problem Solving 19 Hero
    • You have blocked this person.
    • ✔ You're a fan Checking fan status...

    Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

    This is the testimonial you wrote.
    You haven't written a testimonial for Owlfred.