saifoo.khan 3 years ago Please give a short explanation too.

1. saifoo.khan

2. miteshchvm

a. because if we put x= -6 the function approaches infinity

3. hartnn

divide x in numerator and denominator. then because x->infinity, 12/x->0 so u are left with 3/2 only

4. saifoo.khan

So in short we have to the function undefined?

5. miteshchvm

ya right i guess m wrong :p

6. saifoo.khan

Sorry, don't get you.. @hartnn

7. hartnn

dividing x in numerator and denominator , we get (3+12/x)/(2-12/x) agreed ?

8. saifoo.khan

Yes.

9. hartnn

now when X gets infinitely larger 12/x and -12/x gets infinitely smaller. agreed ?

10. saifoo.khan

I think, yes..

11. miteshchvm

opposite

12. hartnn

so to find what f(x) approaches, we put 12/x =0 and -12/x =0 then we get only 3/2. ok ?

13. saifoo.khan

Nope. Don't get this step.

14. hartnn

$\lim_{x \rightarrow \infty}\frac{ 3+12/x }{ 2-12/x }=\frac{ 3+0 }{ 2-0 }=\frac{ 3 }{ 2 }$ because X is very large 1/X is very small and can be taken as 0.

15. saifoo.khan

i see.. thanks.

16. hartnn

welcome :)