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miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
a. because if we put x= 6 the function approaches infinity
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
divide x in numerator and denominator. then because x>infinity, 12/x>0 so u are left with 3/2 only
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
So in short we have to the function undefined?
 2 years ago

miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
ya right i guess m wrong :p
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
Sorry, don't get you.. @hartnn
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
dividing x in numerator and denominator , we get (3+12/x)/(212/x) agreed ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
now when X gets infinitely larger 12/x and 12/x gets infinitely smaller. agreed ?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
I think, yes..
 2 years ago

miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
opposite
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
so to find what f(x) approaches, we put 12/x =0 and 12/x =0 then we get only 3/2. ok ?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
Nope. Don't get this step.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
\[\lim_{x \rightarrow \infty}\frac{ 3+12/x }{ 212/x }=\frac{ 3+0 }{ 20 }=\frac{ 3 }{ 2 }\] because X is very large 1/X is very small and can be taken as 0.
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
i see.. thanks.
 2 years ago
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