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saifoo.khan Group Title

Please give a short explanation too.

  • one year ago
  • one year ago

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  1. saifoo.khan Group Title
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    • one year ago
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  2. miteshchvm Group Title
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    a. because if we put x= -6 the function approaches infinity

    • one year ago
  3. hartnn Group Title
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    divide x in numerator and denominator. then because x->infinity, 12/x->0 so u are left with 3/2 only

    • one year ago
  4. saifoo.khan Group Title
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    So in short we have to the function undefined?

    • one year ago
  5. miteshchvm Group Title
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    ya right i guess m wrong :p

    • one year ago
  6. saifoo.khan Group Title
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    Sorry, don't get you.. @hartnn

    • one year ago
  7. hartnn Group Title
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    dividing x in numerator and denominator , we get (3+12/x)/(2-12/x) agreed ?

    • one year ago
  8. saifoo.khan Group Title
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    Yes.

    • one year ago
  9. hartnn Group Title
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    now when X gets infinitely larger 12/x and -12/x gets infinitely smaller. agreed ?

    • one year ago
  10. saifoo.khan Group Title
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    I think, yes..

    • one year ago
  11. miteshchvm Group Title
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    opposite

    • one year ago
  12. hartnn Group Title
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    so to find what f(x) approaches, we put 12/x =0 and -12/x =0 then we get only 3/2. ok ?

    • one year ago
  13. saifoo.khan Group Title
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    Nope. Don't get this step.

    • one year ago
  14. hartnn Group Title
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    \[\lim_{x \rightarrow \infty}\frac{ 3+12/x }{ 2-12/x }=\frac{ 3+0 }{ 2-0 }=\frac{ 3 }{ 2 }\] because X is very large 1/X is very small and can be taken as 0.

    • one year ago
  15. saifoo.khan Group Title
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    i see.. thanks.

    • one year ago
  16. hartnn Group Title
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    welcome :)

    • one year ago
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