saifoo.khan
Please give a short explanation too.
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saifoo.khan
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miteshchvm
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a.
because if we put x= -6 the function approaches infinity
hartnn
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divide x in numerator and denominator.
then because x->infinity, 12/x->0
so u are left with 3/2 only
saifoo.khan
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So in short we have to the function undefined?
miteshchvm
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ya right
i guess m wrong :p
saifoo.khan
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Sorry, don't get you.. @hartnn
hartnn
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dividing x in numerator and denominator , we get (3+12/x)/(2-12/x)
agreed ?
saifoo.khan
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Yes.
hartnn
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now when X gets infinitely larger 12/x and -12/x gets infinitely smaller.
agreed ?
saifoo.khan
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I think, yes..
miteshchvm
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opposite
hartnn
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so to find what f(x) approaches, we put 12/x =0 and -12/x =0
then we get only 3/2.
ok ?
saifoo.khan
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Nope. Don't get this step.
hartnn
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\[\lim_{x \rightarrow \infty}\frac{ 3+12/x }{ 2-12/x }=\frac{ 3+0 }{ 2-0 }=\frac{ 3 }{ 2 }\]
because X is very large 1/X is very small and can be taken as 0.
saifoo.khan
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i see.. thanks.
hartnn
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welcome :)