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baddinlol
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Differential equation question; if dp/dt = PkP where P is population of rabbits. In a certain year the population is too high and they decide to shoot "S" rabbits each year. Therefore dp/dt = PkP  S. Find in terms P and k the maximum amount of rabbits that can be shot each year to make the population stable.
 one year ago
 one year ago
baddinlol Group Title
Differential equation question; if dp/dt = PkP where P is population of rabbits. In a certain year the population is too high and they decide to shoot "S" rabbits each year. Therefore dp/dt = PkP  S. Find in terms P and k the maximum amount of rabbits that can be shot each year to make the population stable.
 one year ago
 one year ago

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akash809 Group TitleBest ResponseYou've already chosen the best response.1
\[dp/p=(1k)dt\] > \[\ln p=(1k)t + c\] equation of population before shooting after shooting ln p=(1ks)t + k ...differentiate it, get expression of s and equate it to zero to get the answer
 one year ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
So do i equate dp/dt to 0?
 one year ago

akash809 Group TitleBest ResponseYou've already chosen the best response.1
\[1/p=1ks\]
 one year ago

akash809 Group TitleBest ResponseYou've already chosen the best response.1
sorry for previous reply...dont do dp/dt but get expression of s and do ds/dt
 one year ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
OK thanks
 one year ago
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