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Not sure about the answer ... this is just an attempt.
|dw:1348160490381:dw|

|dw:1348160596123:dw|
i hope this picture is correct.

|dw:1348160758615:dw|

oops ... this is a unit circle. the the coordinate is \( (h, \sqrt{1 - h^2})\)|dw:1348161039200:dw|

|dw:1348161529794:dw|

the magnification must be \[ \tan ({ \theta _i - \theta_r}) \times \sqrt{1 - h^2 } + h \over h\]

@experimentX in the diagram above pls make clear the angle \[\theta 1 - \theta 2\]

|dw:1348162335702:dw|

Also make clear the angle of incidence and that of refraction

theta_1 is angle of refraction and theta 2 is angle of incidence.

im on it..trying to figgy it out

how did you derive the magnification formula

which should i follow the first or the second

Image size/ object size ... isn't it? i haven't done this for quite a long time though.

yep u right

@experimentX how did u derive that magnificaton formular

|dw:1348163866108:dw|

all right ... I'm sleeping. carry on!!

so how did magnification becomes refractive index

pls dont delete

so you mean angle OA'A is the incidence angle while OAC is refracted angle?

pls dont remove any thing...

@woleraymond what did you get?

@woleraymond mind sharing it?

pls can i delete now?

just close it?