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andriod09

  • 3 years ago

Factor trinominal times a binomial equation in the comments

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  1. andriod09
    • 3 years ago
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    \[\left( 2x+4y+7 \right)\left( 5x+8 \right)\]

  2. andriod09
    • 3 years ago
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    @ganeshie8

  3. ganeshie8
    • 3 years ago
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    is it 'factor' or 'multiply' ?

  4. andriod09
    • 3 years ago
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    you have to factor it. but its presented as a multiplication question.

  5. ganeshie8
    • 3 years ago
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    hmm interesting.. its already in factored form i guess we cant factor it any further

  6. andriod09
    • 3 years ago
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    i think it might be multiplying it though. the question is: 7.How about multiplying a trinomial times a binomial?

  7. ganeshie8
    • 3 years ago
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    yea this makes sense :)

  8. ganeshie8
    • 3 years ago
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    just have to multiply..

  9. ganeshie8
    • 3 years ago
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    you familiar wid multuplying these right ?

  10. andriod09
    • 3 years ago
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    somewhat

  11. ganeshie8
    • 3 years ago
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    \((2x+4y+7)(5x+8)\) \((\color{green}{2x}+4y+7)(\color{green}{5x+8})\)

  12. ganeshie8
    • 3 years ago
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    first distribute 2x

  13. ganeshie8
    • 3 years ago
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    then 4y and lastly 7

  14. andriod09
    • 3 years ago
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    in between them, would i use ()+()+() or just ()()()?

  15. ganeshie8
    • 3 years ago
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    thats right ! in between we add. () + () + ()

  16. ganeshie8
    • 3 years ago
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    \((\color{green}{2x}+4y+7)(\color{green}{5x+8}) \) \(10x^2 + 16x + 20xy + 32y + 35x + 56 \)

  17. ganeshie8
    • 3 years ago
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    see if above makes sense

  18. andriod09
    • 3 years ago
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    \[\left( 10x^{2}+16x \right)+\left( 20xy+24y \right)+\left( 35x+56? \right)\]

  19. ganeshie8
    • 3 years ago
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    thats almost right !! except for \(24y\)

  20. andriod09
    • 3 years ago
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    i mistyped it. lool. its (20xy+32)

  21. ganeshie8
    • 3 years ago
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    right ! now remove ()

  22. ganeshie8
    • 3 years ago
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    and see if any like terms are there

  23. andriod09
    • 3 years ago
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    16x and 35x and thats it.

  24. ganeshie8
    • 3 years ago
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    yup :)

  25. ganeshie8
    • 3 years ago
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    add them and write it in order

  26. andriod09
    • 3 years ago
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    \[(10x^{2}+51x+20xy+24y+56)\]

  27. ganeshie8
    • 3 years ago
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    \(\left( 10x^{2}+16x \right)+\left( 20xy+32y \right)+\left( 35x+56? \right) \) \(10x^{2}+16x +20xy+32y +35x+56 \) \(10x^{2}+20xy +51x+32y + 56 \)

  28. ganeshie8
    • 3 years ago
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    again 24y. ...

  29. ganeshie8
    • 3 years ago
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    if we ignore that 24y mistype, your final polynomial looks good except for one thing

  30. andriod09
    • 3 years ago
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    \[(10x^{2}+51x+20xy+32y+56)\]

  31. ganeshie8
    • 3 years ago
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    20xy order is more

  32. ganeshie8
    • 3 years ago
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    so you have to move it to left,

  33. ganeshie8
    • 3 years ago
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    and 51x to right.. swap 20xy and 51x

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