Factor trinominal times a binomial equation in the comments

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Factor trinominal times a binomial equation in the comments

Mathematics
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\[\left( 2x+4y+7 \right)\left( 5x+8 \right)\]
is it 'factor' or 'multiply' ?

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you have to factor it. but its presented as a multiplication question.
hmm interesting.. its already in factored form i guess we cant factor it any further
i think it might be multiplying it though. the question is: 7.How about multiplying a trinomial times a binomial?
yea this makes sense :)
just have to multiply..
you familiar wid multuplying these right ?
somewhat
\((2x+4y+7)(5x+8)\) \((\color{green}{2x}+4y+7)(\color{green}{5x+8})\)
first distribute 2x
then 4y and lastly 7
in between them, would i use ()+()+() or just ()()()?
thats right ! in between we add. () + () + ()
\((\color{green}{2x}+4y+7)(\color{green}{5x+8}) \) \(10x^2 + 16x + 20xy + 32y + 35x + 56 \)
see if above makes sense
\[\left( 10x^{2}+16x \right)+\left( 20xy+24y \right)+\left( 35x+56? \right)\]
thats almost right !! except for \(24y\)
i mistyped it. lool. its (20xy+32)
right ! now remove ()
and see if any like terms are there
16x and 35x and thats it.
yup :)
add them and write it in order
\[(10x^{2}+51x+20xy+24y+56)\]
\(\left( 10x^{2}+16x \right)+\left( 20xy+32y \right)+\left( 35x+56? \right) \) \(10x^{2}+16x +20xy+32y +35x+56 \) \(10x^{2}+20xy +51x+32y + 56 \)
again 24y. ...
if we ignore that 24y mistype, your final polynomial looks good except for one thing
\[(10x^{2}+51x+20xy+32y+56)\]
20xy order is more
so you have to move it to left,
and 51x to right.. swap 20xy and 51x

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