andriod09
  • andriod09
Factor trinominal times a binomial equation in the comments
Mathematics
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SOLVED
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chestercat
  • chestercat
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andriod09
  • andriod09
\[\left( 2x+4y+7 \right)\left( 5x+8 \right)\]
andriod09
  • andriod09
@ganeshie8
ganeshie8
  • ganeshie8
is it 'factor' or 'multiply' ?

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andriod09
  • andriod09
you have to factor it. but its presented as a multiplication question.
ganeshie8
  • ganeshie8
hmm interesting.. its already in factored form i guess we cant factor it any further
andriod09
  • andriod09
i think it might be multiplying it though. the question is: 7.How about multiplying a trinomial times a binomial?
ganeshie8
  • ganeshie8
yea this makes sense :)
ganeshie8
  • ganeshie8
just have to multiply..
ganeshie8
  • ganeshie8
you familiar wid multuplying these right ?
andriod09
  • andriod09
somewhat
ganeshie8
  • ganeshie8
\((2x+4y+7)(5x+8)\) \((\color{green}{2x}+4y+7)(\color{green}{5x+8})\)
ganeshie8
  • ganeshie8
first distribute 2x
ganeshie8
  • ganeshie8
then 4y and lastly 7
andriod09
  • andriod09
in between them, would i use ()+()+() or just ()()()?
ganeshie8
  • ganeshie8
thats right ! in between we add. () + () + ()
ganeshie8
  • ganeshie8
\((\color{green}{2x}+4y+7)(\color{green}{5x+8}) \) \(10x^2 + 16x + 20xy + 32y + 35x + 56 \)
ganeshie8
  • ganeshie8
see if above makes sense
andriod09
  • andriod09
\[\left( 10x^{2}+16x \right)+\left( 20xy+24y \right)+\left( 35x+56? \right)\]
ganeshie8
  • ganeshie8
thats almost right !! except for \(24y\)
andriod09
  • andriod09
i mistyped it. lool. its (20xy+32)
ganeshie8
  • ganeshie8
right ! now remove ()
ganeshie8
  • ganeshie8
and see if any like terms are there
andriod09
  • andriod09
16x and 35x and thats it.
ganeshie8
  • ganeshie8
yup :)
ganeshie8
  • ganeshie8
add them and write it in order
andriod09
  • andriod09
\[(10x^{2}+51x+20xy+24y+56)\]
ganeshie8
  • ganeshie8
\(\left( 10x^{2}+16x \right)+\left( 20xy+32y \right)+\left( 35x+56? \right) \) \(10x^{2}+16x +20xy+32y +35x+56 \) \(10x^{2}+20xy +51x+32y + 56 \)
ganeshie8
  • ganeshie8
again 24y. ...
ganeshie8
  • ganeshie8
if we ignore that 24y mistype, your final polynomial looks good except for one thing
andriod09
  • andriod09
\[(10x^{2}+51x+20xy+32y+56)\]
ganeshie8
  • ganeshie8
20xy order is more
ganeshie8
  • ganeshie8
so you have to move it to left,
ganeshie8
  • ganeshie8
and 51x to right.. swap 20xy and 51x

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