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andriod09

  • 2 years ago

Multiplying binomial by a trinomial now. Equation in comments

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  1. andriod09
    • 2 years ago
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    (4x^3-y^4)(3x+4x^8-9)

  2. andriod09
    • 2 years ago
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    @ganeshie8

  3. ganeshie8
    • 2 years ago
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    same method, we distribute term by term

  4. ganeshie8
    • 2 years ago
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    \((4x^3-y^4)(3x+4x^8-9) \)

  5. ganeshie8
    • 2 years ago
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    \((\color{green}{4x^3}-y^4)(\color{green}{3x+4x^8-9}) \)

  6. andriod09
    • 2 years ago
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    I can't see equation using the buttons.

  7. ganeshie8
    • 2 years ago
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    first distribute 3x^3, then \(-y^4\)

  8. ganeshie8
    • 2 years ago
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    ohh i think there is some bug, its not working properly i heard mods were saying equation editor not working properly

  9. andriod09
    • 2 years ago
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    (4x^3-y^4)(3x+4x^8-9) is the equation.

  10. ganeshie8
    • 2 years ago
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    hmm didnt get u

  11. andriod09
    • 2 years ago
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    you put (3x^3) its (4x^3)

  12. ganeshie8
    • 2 years ago
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    oh gotcha :)

  13. ganeshie8
    • 2 years ago
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    lol that was a typpo.. nothing to do wid editor hehe \( (\color{green}{4x^3}-y^4)(\color{green}{3x+4x^8-9}) \)

  14. andriod09
    • 2 years ago
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    okay.

  15. ganeshie8
    • 2 years ago
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    yea distribute \(4x^3\) first

  16. andriod09
    • 2 years ago
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    okay.

  17. andriod09
    • 2 years ago
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    is it: (12x^3+16x^11y^5-36x^3)?

  18. ganeshie8
    • 2 years ago
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    \((\color{green}{4x^3}-y^4)(\color{green}{3x+4x^8-9}) \) \(\color{green}{4x^3}(\color{green}{3x+4x^8-9}) - y^4(3x+4x^8-9) \)

  19. andriod09
    • 2 years ago
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    I can't see the equations used from the buttons! please just type them! im totally confunsed. :/

  20. ganeshie8
    • 2 years ago
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    oh you cant see the latex thats frustrating

  21. andriod09
    • 2 years ago
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    all i see is \((\color{})(\color{}{}) \) but fulled with the equation

  22. ganeshie8
    • 2 years ago
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    (4x^3 - y^4)(3x+4x^8-9) 4x^3(3x+4x^8-9) - y^4(3x+4x^8-9)

  23. andriod09
    • 2 years ago
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    anyhoo, i have (12x^3+16x^11y^5-36x^3)

  24. ganeshie8
    • 2 years ago
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    is that better

  25. andriod09
    • 2 years ago
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    yea, thank you i can read it now! :)

  26. ganeshie8
    • 2 years ago
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    4x^3(3x+4x^8-9) - y^4(3x+4x^8-9) (12x^4 + 16x^11 - 36x^3) - (3xy^4 + 4x^8y^4 - 9y^4)

  27. andriod09
    • 2 years ago
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    i have to condense my paper, give me a second.

  28. ganeshie8
    • 2 years ago
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    (12x^4 + 16x^11 - 36x^3- 3xy^4 - 4x^8y^4 + 9y^4)

  29. ganeshie8
    • 2 years ago
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    ok if u see any like terms, just add them. i think somthing went wrong in ur answer.. . check :)

  30. andriod09
    • 2 years ago
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    for which part of the equation though?

  31. ganeshie8
    • 2 years ago
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    i dont see any like terms. so thats it i hope

  32. ganeshie8
    • 2 years ago
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    (12x^4 + 16x^11 - 36x^3- 3xy^4 - 4x^8y^4 + 9y^4)

  33. andriod09
    • 2 years ago
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    12x^4 + 16x^11- 36x^3, 3xy^4 - 4x^8y^. are all like terms

  34. ganeshie8
    • 2 years ago
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    why do u think they are like terms

  35. andriod09
    • 2 years ago
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    they are all the same i.e. (x)^4,(x)^11,(-x)^3; (xy)^4,(x)^8(y)^4

  36. andriod09
    • 2 years ago
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    @ganeshie8

  37. ganeshie8
    • 2 years ago
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    (x)^4 and (x)^11 are not like terms

  38. ganeshie8
    • 2 years ago
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    to be called as like terms, terms should satisfy two things- 1) variable letters, for example x, y 2) exponent of variables

  39. ganeshie8
    • 2 years ago
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    terms listed by you are satisfying first condition. but they are failing second condition

  40. ganeshie8
    • 2 years ago
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    if u see, (x)^4,(x)^11 first one has an exponent of 4, and second one has an exponent of 11 so they are not like terms. we cant add them

  41. andriod09
    • 2 years ago
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    oh but they are. they are both (x)s. so by that, all you would do is att the exponets and the numerals.

  42. ganeshie8
    • 2 years ago
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    for addition, BOTH variable(x)s and exponents(4, 11) MUST be equal for multiplication, variables must be equal.

  43. ganeshie8
    • 2 years ago
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    |dw:1348066341953:dw|

  44. andriod09
    • 2 years ago
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    @myininaya Hold on ima get a moderator to see whos right. i don't doubt you or anything, i just think that because they are both (x)s, then they could be added.

  45. ganeshie8
    • 2 years ago
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    |dw:1348066394415:dw|

  46. ganeshie8
    • 2 years ago
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    hmm

  47. andriod09
    • 2 years ago
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    How? |dw:1348066447218:dw|

  48. ganeshie8
    • 2 years ago
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    |dw:1348066558698:dw|

  49. ganeshie8
    • 2 years ago
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    first row you cannot add, second row terms you can add

  50. andriod09
    • 2 years ago
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    |dw:1348066611963:dw|

  51. ganeshie8
    • 2 years ago
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    |dw:1348066641503:dw|

  52. ganeshie8
    • 2 years ago
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    exponent must match, then only they are called like-terms, like-terms we can add

  53. andriod09
    • 2 years ago
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    @Callisto @cshalvey @myininaya @amistre64

  54. andriod09
    • 2 years ago
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    I don't get it though, lets see if we can get a mod in here to help me explain it.

  55. ganeshie8
    • 2 years ago
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    ok

  56. andriod09
    • 2 years ago
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    @Callisto @cshalvey @myininaya @amistre64

  57. andriod09
    • 2 years ago
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    @Callisto @cshalvey @myininaya @amistre64

  58. andriod09
    • 2 years ago
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    callisto, can you explain how (x)^4and(x)^11and(-x)^3(stop)(xy)^4And(x)^8(y)^4 arn't like terms? the (stop) seperates two different types of variables

  59. andriod09
    • 2 years ago
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    @ganeshie8

  60. Callisto
    • 2 years ago
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    @ganeshie8 has explained it actually. For like terms, the unknown variable should be the same, and of the same power. For instance, x^4 and x^5 are not like term. Even though they share the same variable, their powers are not the same. So, we cannot do addition or subtraction for these two terms.

  61. andriod09
    • 2 years ago
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    but to be a like term, they have to be the SAME variable though, so wouldn't you add the exponites? x^4+x^5=x^9??

  62. Callisto
    • 2 years ago
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    To be a like terms, there are TWO conditions: 1. same variable 2. same variable of the SAME POWER For x^4 and x^5, they have the same variable x. I think you agree on that. But the problem comes when they fail to meet the SECOND condition, that is they do NOT share the SAME power - for x^4, the power of x is 4; for x^5, the power of x is 5. So, in this case, they CANNOT be added together nor subtraction from each other.

  63. Callisto
    • 2 years ago
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    Perhaps you should know this: x^a + x^b ≠ x^(a+b) BUT! (x^a) (x^b) = x^(a+b) when x is a non-zero real number and a, b are integers.

  64. andriod09
    • 2 years ago
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    Ohh. I MUST FAIL EPICLY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

  65. Callisto
    • 2 years ago
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    It's okay!

  66. andriod09
    • 2 years ago
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    no. i fail epicly. its a fact of life

  67. Callisto
    • 2 years ago
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    It's okay... When you don't fail again!

  68. Callisto
    • 2 years ago
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    So, do you understand it now?

  69. andriod09
    • 2 years ago
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    What about the 12x^3 and the -36^3? arn't they like terms?

  70. andriod09
    • 2 years ago
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    wait, never mind. i fail......... AGAIN

  71. Callisto
    • 2 years ago
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    They are the like terms, aren't they?

  72. andriod09
    • 2 years ago
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    i forgot the the 4x^3*3x=12x^4 not ^3

  73. andriod09
    • 2 years ago
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    Hi hartnn

  74. Callisto
    • 2 years ago
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    Oh.. Just be careful next time :)

  75. andriod09
    • 2 years ago
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    i will

  76. hartnn
    • 2 years ago
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    u won't fail @andriod09 , u are learning from great teachers @ganeshie8 and @Callisto :)

  77. andriod09
    • 2 years ago
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    @hartnn ik its just that i NEVER see the slightest thing, whether in math or irl, it makes me annoyed

  78. hartnn
    • 2 years ago
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    practice and u will become good........

  79. andriod09
    • 2 years ago
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    ik i will. Thanks. |dw:1348068458083:dw|

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