andriod09
  • andriod09
Multiplying binomial by a trinomial now. Equation in comments
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
andriod09
  • andriod09
(4x^3-y^4)(3x+4x^8-9)
andriod09
  • andriod09
@ganeshie8
ganeshie8
  • ganeshie8
same method, we distribute term by term

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ganeshie8
  • ganeshie8
\((4x^3-y^4)(3x+4x^8-9) \)
ganeshie8
  • ganeshie8
\((\color{green}{4x^3}-y^4)(\color{green}{3x+4x^8-9}) \)
andriod09
  • andriod09
I can't see equation using the buttons.
ganeshie8
  • ganeshie8
first distribute 3x^3, then \(-y^4\)
ganeshie8
  • ganeshie8
ohh i think there is some bug, its not working properly i heard mods were saying equation editor not working properly
andriod09
  • andriod09
(4x^3-y^4)(3x+4x^8-9) is the equation.
ganeshie8
  • ganeshie8
hmm didnt get u
andriod09
  • andriod09
you put (3x^3) its (4x^3)
ganeshie8
  • ganeshie8
oh gotcha :)
ganeshie8
  • ganeshie8
lol that was a typpo.. nothing to do wid editor hehe \( (\color{green}{4x^3}-y^4)(\color{green}{3x+4x^8-9}) \)
andriod09
  • andriod09
okay.
ganeshie8
  • ganeshie8
yea distribute \(4x^3\) first
andriod09
  • andriod09
okay.
andriod09
  • andriod09
is it: (12x^3+16x^11y^5-36x^3)?
ganeshie8
  • ganeshie8
\((\color{green}{4x^3}-y^4)(\color{green}{3x+4x^8-9}) \) \(\color{green}{4x^3}(\color{green}{3x+4x^8-9}) - y^4(3x+4x^8-9) \)
andriod09
  • andriod09
I can't see the equations used from the buttons! please just type them! im totally confunsed. :/
ganeshie8
  • ganeshie8
oh you cant see the latex thats frustrating
andriod09
  • andriod09
all i see is \((\color{})(\color{}{}) \) but fulled with the equation
ganeshie8
  • ganeshie8
(4x^3 - y^4)(3x+4x^8-9) 4x^3(3x+4x^8-9) - y^4(3x+4x^8-9)
andriod09
  • andriod09
anyhoo, i have (12x^3+16x^11y^5-36x^3)
ganeshie8
  • ganeshie8
is that better
andriod09
  • andriod09
yea, thank you i can read it now! :)
ganeshie8
  • ganeshie8
4x^3(3x+4x^8-9) - y^4(3x+4x^8-9) (12x^4 + 16x^11 - 36x^3) - (3xy^4 + 4x^8y^4 - 9y^4)
andriod09
  • andriod09
i have to condense my paper, give me a second.
ganeshie8
  • ganeshie8
(12x^4 + 16x^11 - 36x^3- 3xy^4 - 4x^8y^4 + 9y^4)
ganeshie8
  • ganeshie8
ok if u see any like terms, just add them. i think somthing went wrong in ur answer.. . check :)
andriod09
  • andriod09
for which part of the equation though?
ganeshie8
  • ganeshie8
i dont see any like terms. so thats it i hope
ganeshie8
  • ganeshie8
(12x^4 + 16x^11 - 36x^3- 3xy^4 - 4x^8y^4 + 9y^4)
andriod09
  • andriod09
12x^4 + 16x^11- 36x^3, 3xy^4 - 4x^8y^. are all like terms
ganeshie8
  • ganeshie8
why do u think they are like terms
andriod09
  • andriod09
they are all the same i.e. (x)^4,(x)^11,(-x)^3; (xy)^4,(x)^8(y)^4
andriod09
  • andriod09
@ganeshie8
ganeshie8
  • ganeshie8
(x)^4 and (x)^11 are not like terms
ganeshie8
  • ganeshie8
to be called as like terms, terms should satisfy two things- 1) variable letters, for example x, y 2) exponent of variables
ganeshie8
  • ganeshie8
terms listed by you are satisfying first condition. but they are failing second condition
ganeshie8
  • ganeshie8
if u see, (x)^4,(x)^11 first one has an exponent of 4, and second one has an exponent of 11 so they are not like terms. we cant add them
andriod09
  • andriod09
oh but they are. they are both (x)s. so by that, all you would do is att the exponets and the numerals.
ganeshie8
  • ganeshie8
for addition, BOTH variable(x)s and exponents(4, 11) MUST be equal for multiplication, variables must be equal.
ganeshie8
  • ganeshie8
|dw:1348066341953:dw|
andriod09
  • andriod09
@myininaya Hold on ima get a moderator to see whos right. i don't doubt you or anything, i just think that because they are both (x)s, then they could be added.
ganeshie8
  • ganeshie8
|dw:1348066394415:dw|
ganeshie8
  • ganeshie8
hmm
andriod09
  • andriod09
How? |dw:1348066447218:dw|
ganeshie8
  • ganeshie8
|dw:1348066558698:dw|
ganeshie8
  • ganeshie8
first row you cannot add, second row terms you can add
andriod09
  • andriod09
|dw:1348066611963:dw|
ganeshie8
  • ganeshie8
|dw:1348066641503:dw|
ganeshie8
  • ganeshie8
exponent must match, then only they are called like-terms, like-terms we can add
andriod09
  • andriod09
@Callisto @cshalvey @myininaya @amistre64
andriod09
  • andriod09
I don't get it though, lets see if we can get a mod in here to help me explain it.
ganeshie8
  • ganeshie8
ok
andriod09
  • andriod09
@Callisto @cshalvey @myininaya @amistre64
andriod09
  • andriod09
@Callisto @cshalvey @myininaya @amistre64
andriod09
  • andriod09
callisto, can you explain how (x)^4and(x)^11and(-x)^3(stop)(xy)^4And(x)^8(y)^4 arn't like terms? the (stop) seperates two different types of variables
andriod09
  • andriod09
@ganeshie8
Callisto
  • Callisto
@ganeshie8 has explained it actually. For like terms, the unknown variable should be the same, and of the same power. For instance, x^4 and x^5 are not like term. Even though they share the same variable, their powers are not the same. So, we cannot do addition or subtraction for these two terms.
andriod09
  • andriod09
but to be a like term, they have to be the SAME variable though, so wouldn't you add the exponites? x^4+x^5=x^9??
Callisto
  • Callisto
To be a like terms, there are TWO conditions: 1. same variable 2. same variable of the SAME POWER For x^4 and x^5, they have the same variable x. I think you agree on that. But the problem comes when they fail to meet the SECOND condition, that is they do NOT share the SAME power - for x^4, the power of x is 4; for x^5, the power of x is 5. So, in this case, they CANNOT be added together nor subtraction from each other.
Callisto
  • Callisto
Perhaps you should know this: x^a + x^b ≠ x^(a+b) BUT! (x^a) (x^b) = x^(a+b) when x is a non-zero real number and a, b are integers.
andriod09
  • andriod09
Ohh. I MUST FAIL EPICLY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Callisto
  • Callisto
It's okay!
andriod09
  • andriod09
no. i fail epicly. its a fact of life
Callisto
  • Callisto
It's okay... When you don't fail again!
Callisto
  • Callisto
So, do you understand it now?
andriod09
  • andriod09
What about the 12x^3 and the -36^3? arn't they like terms?
andriod09
  • andriod09
wait, never mind. i fail......... AGAIN
Callisto
  • Callisto
They are the like terms, aren't they?
andriod09
  • andriod09
i forgot the the 4x^3*3x=12x^4 not ^3
andriod09
  • andriod09
Hi hartnn
Callisto
  • Callisto
Oh.. Just be careful next time :)
andriod09
  • andriod09
i will
hartnn
  • hartnn
u won't fail @andriod09 , u are learning from great teachers @ganeshie8 and @Callisto :)
andriod09
  • andriod09
@hartnn ik its just that i NEVER see the slightest thing, whether in math or irl, it makes me annoyed
hartnn
  • hartnn
practice and u will become good........
andriod09
  • andriod09
ik i will. Thanks. |dw:1348068458083:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.