andriod09
Multiplying binomial by a trinomial now.
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andriod09
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(4x^3-y^4)(3x+4x^8-9)
andriod09
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@ganeshie8
ganeshie8
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same method, we distribute term by term
ganeshie8
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\((4x^3-y^4)(3x+4x^8-9) \)
ganeshie8
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\((\color{green}{4x^3}-y^4)(\color{green}{3x+4x^8-9}) \)
andriod09
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I can't see equation using the buttons.
ganeshie8
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first distribute 3x^3, then \(-y^4\)
ganeshie8
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ohh i think there is some bug, its not working properly i heard mods were saying equation editor not working properly
andriod09
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(4x^3-y^4)(3x+4x^8-9) is the equation.
ganeshie8
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hmm didnt get u
andriod09
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you put (3x^3) its (4x^3)
ganeshie8
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oh gotcha :)
ganeshie8
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lol that was a typpo.. nothing to do wid editor hehe
\( (\color{green}{4x^3}-y^4)(\color{green}{3x+4x^8-9}) \)
andriod09
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okay.
ganeshie8
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yea distribute \(4x^3\) first
andriod09
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okay.
andriod09
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is it:
(12x^3+16x^11y^5-36x^3)?
ganeshie8
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\((\color{green}{4x^3}-y^4)(\color{green}{3x+4x^8-9}) \)
\(\color{green}{4x^3}(\color{green}{3x+4x^8-9}) - y^4(3x+4x^8-9) \)
andriod09
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I can't see the equations used from the buttons! please just type them! im totally confunsed. :/
ganeshie8
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oh you cant see the latex thats frustrating
andriod09
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all i see is \((\color{})(\color{}{}) \) but fulled with the equation
ganeshie8
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(4x^3 - y^4)(3x+4x^8-9)
4x^3(3x+4x^8-9) - y^4(3x+4x^8-9)
andriod09
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anyhoo, i have (12x^3+16x^11y^5-36x^3)
ganeshie8
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is that better
andriod09
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yea, thank you i can read it now! :)
ganeshie8
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4x^3(3x+4x^8-9) - y^4(3x+4x^8-9)
(12x^4 + 16x^11 - 36x^3) - (3xy^4 + 4x^8y^4 - 9y^4)
andriod09
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i have to condense my paper, give me a second.
ganeshie8
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(12x^4 + 16x^11 - 36x^3- 3xy^4 - 4x^8y^4 + 9y^4)
ganeshie8
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ok if u see any like terms, just add them. i think somthing went wrong in ur answer.. . check :)
andriod09
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for which part of the equation though?
ganeshie8
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i dont see any like terms. so thats it i hope
ganeshie8
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(12x^4 + 16x^11 - 36x^3- 3xy^4 - 4x^8y^4 + 9y^4)
andriod09
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12x^4 + 16x^11- 36x^3, 3xy^4 - 4x^8y^. are all like terms
ganeshie8
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why do u think they are like terms
andriod09
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they are all the same i.e. (x)^4,(x)^11,(-x)^3; (xy)^4,(x)^8(y)^4
andriod09
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@ganeshie8
ganeshie8
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(x)^4 and (x)^11 are not like terms
ganeshie8
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to be called as like terms, terms should satisfy two things-
1) variable letters, for example x, y
2) exponent of variables
ganeshie8
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terms listed by you are satisfying first condition.
but they are failing second condition
ganeshie8
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if u see,
(x)^4,(x)^11
first one has an exponent of 4, and second one has an exponent of 11
so they are not like terms. we cant add them
andriod09
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oh but they are. they are both (x)s. so by that, all you would do is att the exponets and the numerals.
ganeshie8
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for addition, BOTH variable(x)s and exponents(4, 11) MUST be equal
for multiplication, variables must be equal.
ganeshie8
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andriod09
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@myininaya Hold on ima get a moderator to see whos right. i don't doubt you or anything, i just think that because they are both (x)s, then they could be added.
ganeshie8
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|dw:1348066394415:dw|
ganeshie8
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hmm
andriod09
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How? |dw:1348066447218:dw|
ganeshie8
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|dw:1348066558698:dw|
ganeshie8
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first row you cannot add,
second row terms you can add
andriod09
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|dw:1348066611963:dw|
ganeshie8
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|dw:1348066641503:dw|
ganeshie8
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exponent must match, then only they are called like-terms, like-terms we can add
andriod09
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@Callisto @cshalvey @myininaya @amistre64
andriod09
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I don't get it though, lets see if we can get a mod in here to help me explain it.
ganeshie8
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ok
andriod09
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@Callisto @cshalvey @myininaya @amistre64
andriod09
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@Callisto @cshalvey @myininaya @amistre64
andriod09
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callisto, can you explain how (x)^4and(x)^11and(-x)^3(stop)(xy)^4And(x)^8(y)^4 arn't like terms? the (stop) seperates two different types of variables
andriod09
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@ganeshie8
Callisto
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@ganeshie8 has explained it actually. For like terms, the unknown variable should be the same, and of the same power. For instance, x^4 and x^5 are not like term. Even though they share the same variable, their powers are not the same. So, we cannot do addition or subtraction for these two terms.
andriod09
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but to be a like term, they have to be the SAME variable though, so wouldn't you add the exponites? x^4+x^5=x^9??
Callisto
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To be a like terms, there are TWO conditions:
1. same variable
2. same variable of the SAME POWER
For x^4 and x^5, they have the same variable x. I think you agree on that. But the problem comes when they fail to meet the SECOND condition, that is they do NOT share the SAME power - for x^4, the power of x is 4; for x^5, the power of x is 5.
So, in this case, they CANNOT be added together nor subtraction from each other.
Callisto
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Perhaps you should know this:
x^a + x^b ≠ x^(a+b)
BUT!
(x^a) (x^b) = x^(a+b) when x is a non-zero real number and a, b are integers.
andriod09
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Ohh. I MUST FAIL EPICLY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Callisto
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It's okay!
andriod09
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no. i fail epicly. its a fact of life
Callisto
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It's okay... When you don't fail again!
Callisto
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So, do you understand it now?
andriod09
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What about the 12x^3 and the -36^3? arn't they like terms?
andriod09
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wait, never mind. i fail......... AGAIN
Callisto
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They are the like terms, aren't they?
andriod09
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i forgot the the 4x^3*3x=12x^4 not ^3
andriod09
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Hi hartnn
Callisto
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Oh.. Just be careful next time :)
andriod09
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i will
hartnn
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u won't fail @andriod09 , u are learning from great teachers @ganeshie8 and @Callisto :)
andriod09
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@hartnn ik its just that i NEVER see the slightest thing, whether in math or irl, it makes me annoyed
hartnn
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practice and u will become good........
andriod09
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ik i will. Thanks.
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