babydoll332
An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ



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ParthKohli
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What have you tried till now?

babydoll332
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ParthKohli
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Well,\[\tan \theta = {opposite \over adjacent}\]From \(\sin \theta\), we know that "opposite" is 6.

babydoll332
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ParthKohli
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Also, you must must find the adjacent side through Pythagorean Theorem.\[6^2 + b^2 = 7^2\]

ParthKohli
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Yeah, also recall that\[\cot \theta = {adjacent \over opposite}\]

babydoll332
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so thats right? :)

ParthKohli
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\[b = \sqrt{7^2  6^2} = \sqrt{13}\]Yay!

babydoll332
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ohh so 6/√13 ?

ParthKohli
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No, your answer is right.

babydoll332
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ok i gt confused for a seccc

babydoll332
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love ur pic btw