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babydoll332
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An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ
 one year ago
 one year ago
babydoll332 Group Title
An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ
 one year ago
 one year ago

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ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
What have you tried till now?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Well,\[\tan \theta = {opposite \over adjacent}\]From \(\sin \theta\), we know that "opposite" is 6.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Also, you must must find the adjacent side through Pythagorean Theorem.\[6^2 + b^2 = 7^2\]
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Yeah, also recall that\[\cot \theta = {adjacent \over opposite}\]
 one year ago

babydoll332 Group TitleBest ResponseYou've already chosen the best response.1
so thats right? :)
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
\[b = \sqrt{7^2  6^2} = \sqrt{13}\]Yay!
 one year ago

babydoll332 Group TitleBest ResponseYou've already chosen the best response.1
ohh so 6/√13 ?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
No, your answer is right.
 one year ago

babydoll332 Group TitleBest ResponseYou've already chosen the best response.1
ok i gt confused for a seccc
 one year ago

babydoll332 Group TitleBest ResponseYou've already chosen the best response.1
love ur pic btw
 one year ago
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