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babydoll332

An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ

  • one year ago
  • one year ago

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  1. ParthKohli
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    What have you tried till now?

    • one year ago
  2. babydoll332
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    • one year ago
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  3. ParthKohli
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    Well,\[\tan \theta = {opposite \over adjacent}\]From \(\sin \theta\), we know that "opposite" is 6.

    • one year ago
  4. babydoll332
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  5. ParthKohli
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    Also, you must must find the adjacent side through Pythagorean Theorem.\[6^2 + b^2 = 7^2\]

    • one year ago
  6. ParthKohli
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    Yeah, also recall that\[\cot \theta = {adjacent \over opposite}\]

    • one year ago
  7. babydoll332
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    so thats right? :)

    • one year ago
  8. ParthKohli
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    \[b = \sqrt{7^2 - 6^2} = \sqrt{13}\]Yay!

    • one year ago
  9. babydoll332
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    ohh so 6/√13 ?

    • one year ago
  10. ParthKohli
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    No, your answer is right.

    • one year ago
  11. babydoll332
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    ok i gt confused for a seccc

    • one year ago
  12. babydoll332
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    love ur pic btw

    • one year ago
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