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babydoll332
 3 years ago
An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ
babydoll332
 3 years ago
An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ

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ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.2What have you tried till now?

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.2Well,\[\tan \theta = {opposite \over adjacent}\]From \(\sin \theta\), we know that "opposite" is 6.

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.2Also, you must must find the adjacent side through Pythagorean Theorem.\[6^2 + b^2 = 7^2\]

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.2Yeah, also recall that\[\cot \theta = {adjacent \over opposite}\]

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.2\[b = \sqrt{7^2  6^2} = \sqrt{13}\]Yay!

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.2No, your answer is right.

babydoll332
 3 years ago
Best ResponseYou've already chosen the best response.1ok i gt confused for a seccc
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