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babydoll332

  • 3 years ago

An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ

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  1. ParthKohli
    • 3 years ago
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    What have you tried till now?

  2. babydoll332
    • 3 years ago
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  3. ParthKohli
    • 3 years ago
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    Well,\[\tan \theta = {opposite \over adjacent}\]From \(\sin \theta\), we know that "opposite" is 6.

  4. babydoll332
    • 3 years ago
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  5. ParthKohli
    • 3 years ago
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    Also, you must must find the adjacent side through Pythagorean Theorem.\[6^2 + b^2 = 7^2\]

  6. ParthKohli
    • 3 years ago
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    Yeah, also recall that\[\cot \theta = {adjacent \over opposite}\]

  7. babydoll332
    • 3 years ago
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    so thats right? :)

  8. ParthKohli
    • 3 years ago
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    \[b = \sqrt{7^2 - 6^2} = \sqrt{13}\]Yay!

  9. babydoll332
    • 3 years ago
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    ohh so 6/√13 ?

  10. ParthKohli
    • 3 years ago
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    No, your answer is right.

  11. babydoll332
    • 3 years ago
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    ok i gt confused for a seccc

  12. babydoll332
    • 3 years ago
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    love ur pic btw

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