anonymous
  • anonymous
An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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ParthKohli
  • ParthKohli
What have you tried till now?
anonymous
  • anonymous
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ParthKohli
  • ParthKohli
Well,\[\tan \theta = {opposite \over adjacent}\]From \(\sin \theta\), we know that "opposite" is 6.

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anonymous
  • anonymous
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ParthKohli
  • ParthKohli
Also, you must must find the adjacent side through Pythagorean Theorem.\[6^2 + b^2 = 7^2\]
ParthKohli
  • ParthKohli
Yeah, also recall that\[\cot \theta = {adjacent \over opposite}\]
anonymous
  • anonymous
so thats right? :)
ParthKohli
  • ParthKohli
\[b = \sqrt{7^2 - 6^2} = \sqrt{13}\]Yay!
anonymous
  • anonymous
ohh so 6/√13 ?
ParthKohli
  • ParthKohli
No, your answer is right.
anonymous
  • anonymous
ok i gt confused for a seccc
anonymous
  • anonymous
love ur pic btw

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