## anonymous 4 years ago An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ

1. ParthKohli

What have you tried till now?

2. anonymous

3. ParthKohli

Well,$\tan \theta = {opposite \over adjacent}$From $$\sin \theta$$, we know that "opposite" is 6.

4. anonymous

5. ParthKohli

Also, you must must find the adjacent side through Pythagorean Theorem.$6^2 + b^2 = 7^2$

6. ParthKohli

Yeah, also recall that$\cot \theta = {adjacent \over opposite}$

7. anonymous

so thats right? :)

8. ParthKohli

$b = \sqrt{7^2 - 6^2} = \sqrt{13}$Yay!

9. anonymous

ohh so 6/√13 ?

10. ParthKohli

11. anonymous

ok i gt confused for a seccc

12. anonymous

love ur pic btw