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An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ
 one year ago
 one year ago
An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ
 one year ago
 one year ago

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ParthKohliBest ResponseYou've already chosen the best response.1
What have you tried till now?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Well,\[\tan \theta = {opposite \over adjacent}\]From \(\sin \theta\), we know that "opposite" is 6.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Also, you must must find the adjacent side through Pythagorean Theorem.\[6^2 + b^2 = 7^2\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Yeah, also recall that\[\cot \theta = {adjacent \over opposite}\]
 one year ago

babydoll332Best ResponseYou've already chosen the best response.1
so thats right? :)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
\[b = \sqrt{7^2  6^2} = \sqrt{13}\]Yay!
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
No, your answer is right.
 one year ago

babydoll332Best ResponseYou've already chosen the best response.1
ok i gt confused for a seccc
 one year ago
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