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if jane walks 15m straight and then she turns left and walks for 5 m after that she walks another 3 m towards right then how far is she from the point of start? i am finding it tough to picturize this ..
 one year ago
 one year ago
if jane walks 15m straight and then she turns left and walks for 5 m after that she walks another 3 m towards right then how far is she from the point of start? i am finding it tough to picturize this ..
 one year ago
 one year ago

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acrossBest ResponseYou've already chosen the best response.2
You have to use the Pythagorean theorem.
 one year ago

erica.dBest ResponseYou've already chosen the best response.1
i know that but how to plot this or draw this
 one year ago

tyteen4a03Best ResponseYou've already chosen the best response.0
The diagram you're looking for is this:dw:1348068681247:dw
 one year ago

tyteen4a03Best ResponseYou've already chosen the best response.0
Excuse my drawing, but you get the idea.
 one year ago

erica.dBest ResponseYou've already chosen the best response.1
@tyteen4a03 thanks...now what?
 one year ago

tyteen4a03Best ResponseYou've already chosen the best response.0
Putting this in the coordinate plane, assuming that the starting point is the origin, the final point would be (5, 18). Now plug these numbers into the distance formula \(\sqrt{(x2x1)^2 + (y2y1)^2}\) and you get the answer.
 one year ago

erica.dBest ResponseYou've already chosen the best response.1
@across if i'll join the two end points ..still i am unable to find the distance ...
 one year ago

acrossBest ResponseYou've already chosen the best response.2
If you join the two ends, you will end up with a right triangle that has a base of length 5 and a height of length 15+3.
 one year ago

erica.dBest ResponseYou've already chosen the best response.1
dw:1348069046132:dw ?? @across
 one year ago

erica.dBest ResponseYou've already chosen the best response.1
that's amazing....@across you are genius :) thanks a lot
 one year ago

erica.dBest ResponseYou've already chosen the best response.1
dw:1348069219200:dw i was doing it this way...and i guess there is no need to plot it on graph and point out coordinates ..... @across thanks alot again
 one year ago

erica.dBest ResponseYou've already chosen the best response.1
i wish i could give you all the medals lol
 one year ago

tyteen4a03Best ResponseYou've already chosen the best response.0
@erica.d One thing about mathematics is that there are many solution to the same problem. The Distance Formula, for example, is useful when you only know the starting and the ending point (imagine your question, but you're only given 2 points). In this case, using Pythagoras's theorem is like reinventing the wheel.
 one year ago

erica.dBest ResponseYou've already chosen the best response.1
i know that but what @across has done was not imagined by me ...by the way thanks
 one year ago
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