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watching :)

hahah ....

me too ... just for the sake of memory :)

Me three!

This is why OS is awesome, they never teach you subs like this in the USA...

this looks promising
\[ x = a \; \sec ^2 t - b\; \tan ^2 t\]

looks like Euler's subs is like Weierstrass subs ... always gives the answer but really last resort.

Can I try the first one?

yep sure ...

pretty cool technique ... i hadn't seen this either.

you see how you change dx?

dx = dt

I get it.

nice use of symmetry on the previous solution BTW

that is just inverse of cosine hyperbolic ...

\[ \cosh^{-1}\left( t \over c \right) = u \]

Ok. But I don't like \(\sinh(2\;\text{arccosh}\; t) \)

i don't like hyperbolic functions either. because they look like circle in complex plane :)

But this will make easier. Euler subs will make the integral too complicated.

yeah ... agree on that point. I don't like Weierstrass subs either.

i would try makings
\[ x = a \; \sec ^2 t - b\; \tan ^2 t \]
haven't thought of second one.

something is really bad with chrome

damn ... lol. Didn't know it would get involved with two elliptical types.