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moser90
 2 years ago
Use the center, vertices, and asymptotes to graph the hyperbola.
(x  1)2  9(y  2)2 = 9
moser90
 2 years ago
Use the center, vertices, and asymptotes to graph the hyperbola. (x  1)2  9(y  2)2 = 9

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moser90
 2 years ago
Best ResponseYou've already chosen the best response.0I am totally stuck if someone can help me find the center I can figure out the rest

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1http://tutorial.math.lamar.edu/Classes/Alg/Hyperbolas.aspx is a good link to help you!

moser90
 2 years ago
Best ResponseYou've already chosen the best response.0I am just really confused because there is nothing on the bottom for a denominator

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1I'm not sure myself, but it looks like it's (1,2) for the center.

waleed_imtiaz
 2 years ago
Best ResponseYou've already chosen the best response.0First divide the whole equation by 9... (x  1)^2/(9)  (y  2)^2 =1 now U know a=3 and b=1 So focus is (+c,o) because it is on xaxis..... Can u do now ?

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{9}{1}=\frac{1}{\frac{1}{9}}=\frac{1}{(\frac{1}{3})^2}\]

moser90
 2 years ago
Best ResponseYou've already chosen the best response.0so this would make it the last picture right

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1If the center is (1,2) that is your only option!

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1Did you check out the link? http://tutorial.math.lamar.edu/Classes/Alg/Hyperbolas.aspx

waleed_imtiaz
 2 years ago
Best ResponseYou've already chosen the best response.0centre would be (1,2) i think so

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1Well that's two of us. I say it's a good bet.

moser90
 2 years ago
Best ResponseYou've already chosen the best response.0sometimes the pictures are just hard to go by

moser90
 2 years ago
Best ResponseYou've already chosen the best response.0but we know that it is not (0,0) or (1,2) so the last one is the best

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1When you look at formulas that have something like \[(x+h)\], you often want x to be modified only by addition or subtraction. If x is multiplied or divided by anything, get it out of the parenthesis! Anything multiplied or divided by \[(x+h)\]is then something that can really be expressed as just division if you want. By doing so, the equation you have will start to match up with the general formula for the shape of the curve.

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1We are sure it is (1,2) when we compare it to the general formula. The position of the center of any shape can be found when you see how all x's and all y's are modified with addition or subtraction. This seems to "shift" graphs.

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1You're welcome! :) Back to the "shifting", if you have y = (x), then y = (x+5) is looks to be shifted 5 up. Same with y = 9(x) seeming to shift 5 up when you look at y = 9(x+5).

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1When you look at \[(xh)^2\], \[(xh)\]is how you are modifying x. You are finding the difference between them with subtraction. Then that difference is squared, so only the difference between them matters, not at all whether x>h or x<h.

theEric
 2 years ago
Best ResponseYou've already chosen the best response.1Lastly, for your future typedup math discussions, it helps to express "to the power of 2" as "^2". It's a very common notation used on the internet.
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