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moser90
Group Title
Use the center, vertices, and asymptotes to graph the hyperbola.
(x  1)2  9(y  2)2 = 9
 one year ago
 one year ago
moser90 Group Title
Use the center, vertices, and asymptotes to graph the hyperbola. (x  1)2  9(y  2)2 = 9
 one year ago
 one year ago

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moser90 Group TitleBest ResponseYou've already chosen the best response.0
I am totally stuck if someone can help me find the center I can figure out the rest
 one year ago

moser90 Group TitleBest ResponseYou've already chosen the best response.0
is the center 0,0
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
http://tutorial.math.lamar.edu/Classes/Alg/Hyperbolas.aspx is a good link to help you!
 one year ago

moser90 Group TitleBest ResponseYou've already chosen the best response.0
I am just really confused because there is nothing on the bottom for a denominator
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
I'm not sure myself, but it looks like it's (1,2) for the center.
 one year ago

waleed_imtiaz Group TitleBest ResponseYou've already chosen the best response.0
First divide the whole equation by 9... (x  1)^2/(9)  (y  2)^2 =1 now U know a=3 and b=1 So focus is (+c,o) because it is on xaxis..... Can u do now ?
 one year ago

moser90 Group TitleBest ResponseYou've already chosen the best response.0
so the center is (1,3)
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{9}{1}=\frac{1}{\frac{1}{9}}=\frac{1}{(\frac{1}{3})^2}\]
 one year ago

moser90 Group TitleBest ResponseYou've already chosen the best response.0
so this would make it the last picture right
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
If the center is (1,2) that is your only option!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Did you check out the link? http://tutorial.math.lamar.edu/Classes/Alg/Hyperbolas.aspx
 one year ago

waleed_imtiaz Group TitleBest ResponseYou've already chosen the best response.0
centre would be (1,2) i think so
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Well that's two of us. I say it's a good bet.
 one year ago

moser90 Group TitleBest ResponseYou've already chosen the best response.0
sometimes the pictures are just hard to go by
 one year ago

moser90 Group TitleBest ResponseYou've already chosen the best response.0
but we know that it is not (0,0) or (1,2) so the last one is the best
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
When you look at formulas that have something like \[(x+h)\], you often want x to be modified only by addition or subtraction. If x is multiplied or divided by anything, get it out of the parenthesis! Anything multiplied or divided by \[(x+h)\]is then something that can really be expressed as just division if you want. By doing so, the equation you have will start to match up with the general formula for the shape of the curve.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
We are sure it is (1,2) when we compare it to the general formula. The position of the center of any shape can be found when you see how all x's and all y's are modified with addition or subtraction. This seems to "shift" graphs.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
You're welcome! :) Back to the "shifting", if you have y = (x), then y = (x+5) is looks to be shifted 5 up. Same with y = 9(x) seeming to shift 5 up when you look at y = 9(x+5).
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
When you look at \[(xh)^2\], \[(xh)\]is how you are modifying x. You are finding the difference between them with subtraction. Then that difference is squared, so only the difference between them matters, not at all whether x>h or x<h.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Lastly, for your future typedup math discussions, it helps to express "to the power of 2" as "^2". It's a very common notation used on the internet.
 one year ago
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