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moser90

Use the center, vertices, and asymptotes to graph the hyperbola. (x - 1)2 - 9(y - 2)2 = 9

  • one year ago
  • one year ago

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  1. moser90
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    • one year ago
  2. moser90
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    I am totally stuck if someone can help me find the center I can figure out the rest

    • one year ago
  3. moser90
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    is the center 0,0

    • one year ago
  4. theEric
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    http://tutorial.math.lamar.edu/Classes/Alg/Hyperbolas.aspx is a good link to help you!

    • one year ago
  5. moser90
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    I am just really confused because there is nothing on the bottom for a denominator

    • one year ago
  6. theEric
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    I'm not sure myself, but it looks like it's (1,2) for the center.

    • one year ago
  7. waleed_imtiaz
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    First divide the whole equation by 9... (x - 1)^2/(9) - (y - 2)^2 =1 now U know a=3 and b=1 So focus is (+-c,o) because it is on x-axis..... Can u do now ?

    • one year ago
  8. moser90
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    so the center is (1,3)

    • one year ago
  9. theEric
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    \[\frac{9}{1}=\frac{1}{\frac{1}{9}}=\frac{1}{(\frac{1}{3})^2}\]

    • one year ago
  10. moser90
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    so this would make it the last picture right

    • one year ago
  11. moser90
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    this one

    • one year ago
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  12. theEric
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    If the center is (1,2) that is your only option!

    • one year ago
  13. theEric
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    Did you check out the link? http://tutorial.math.lamar.edu/Classes/Alg/Hyperbolas.aspx

    • one year ago
  14. moser90
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    yes

    • one year ago
  15. waleed_imtiaz
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    centre would be (1,2) i think so

    • one year ago
  16. theEric
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    Well that's two of us. I say it's a good bet.

    • one year ago
  17. moser90
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    sometimes the pictures are just hard to go by

    • one year ago
  18. moser90
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    but we know that it is not (0,0) or (-1,2) so the last one is the best

    • one year ago
  19. theEric
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    When you look at formulas that have something like \[(x+h)\], you often want x to be modified only by addition or subtraction. If x is multiplied or divided by anything, get it out of the parenthesis! Anything multiplied or divided by \[(x+h)\]is then something that can really be expressed as just division if you want. By doing so, the equation you have will start to match up with the general formula for the shape of the curve.

    • one year ago
  20. moser90
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    thank you

    • one year ago
  21. theEric
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    We are sure it is (1,2) when we compare it to the general formula. The position of the center of any shape can be found when you see how all x's and all y's are modified with addition or subtraction. This seems to "shift" graphs.

    • one year ago
  22. theEric
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    You're welcome! :) Back to the "shifting", if you have y = (x), then y = (x+5) is looks to be shifted 5 up. Same with y = 9(x) seeming to shift 5 up when you look at y = 9(x+5).

    • one year ago
  23. theEric
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    When you look at \[(x-h)^2\], \[(x-h)\]is how you are modifying x. You are finding the difference between them with subtraction. Then that difference is squared, so only the difference between them matters, not at all whether x>h or x<h.

    • one year ago
  24. theEric
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    Lastly, for your future typed-up math discussions, it helps to express "to the power of 2" as "^2". It's a very common notation used on the internet.

    • one year ago
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