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- anonymous

help factor. 5y8 - 125

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- anonymous

help factor. 5y8 - 125

- katieb

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- anonymous

\[5y^8=125\] ---> \[y^8=25\]---->\[y=\sqrt[8]{25}\]

- jackellyn

Is it factor or solve for y? (which is what @akash809 did)

- anonymous

its factor for y @jackellyn which im not good at :I

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- jackellyn

Okay, so the term that 5 and 125 have in common is 5, so you factor that out
125/5=25
so that leaves you with
\[5(y ^{8}-25)\]

- jackellyn

now, let's look at (y^8-25)
y^8 is the same as (y^4)^2
and 25 is the same as (5)^2

- jackellyn

which will be a difference of squares
so you split it into two
(y⁴-5)(y⁴+5)
and one has a + and one has a - because the product of a + and - is -
and dont forget the 5 up front
so the answer is
5(y⁴-5)(y⁴+5)

- anonymous

@jackellyn idk why its so hard for me to understand :c i used to know how to do factors but i forgot ._.

- jackellyn

its all about practice and knowing the rules lol

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