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akash809
 2 years ago
Best ResponseYou've already chosen the best response.0\[5y^8=125\] > \[y^8=25\]>\[y=\sqrt[8]{25}\]

jackellyn
 2 years ago
Best ResponseYou've already chosen the best response.1Is it factor or solve for y? (which is what @akash809 did)

ahoymewmew
 2 years ago
Best ResponseYou've already chosen the best response.0its factor for y @jackellyn which im not good at :I

jackellyn
 2 years ago
Best ResponseYou've already chosen the best response.1Okay, so the term that 5 and 125 have in common is 5, so you factor that out 125/5=25 so that leaves you with \[5(y ^{8}25)\]

jackellyn
 2 years ago
Best ResponseYou've already chosen the best response.1now, let's look at (y^825) y^8 is the same as (y^4)^2 and 25 is the same as (5)^2

jackellyn
 2 years ago
Best ResponseYou've already chosen the best response.1which will be a difference of squares so you split it into two (y⁴5)(y⁴+5) and one has a + and one has a  because the product of a + and  is  and dont forget the 5 up front so the answer is 5(y⁴5)(y⁴+5)

ahoymewmew
 2 years ago
Best ResponseYou've already chosen the best response.0@jackellyn idk why its so hard for me to understand :c i used to know how to do factors but i forgot ._.

jackellyn
 2 years ago
Best ResponseYou've already chosen the best response.1its all about practice and knowing the rules lol
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