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akash809Best ResponseYou've already chosen the best response.0
\[5y^8=125\] > \[y^8=25\]>\[y=\sqrt[8]{25}\]
 one year ago

jackellynBest ResponseYou've already chosen the best response.1
Is it factor or solve for y? (which is what @akash809 did)
 one year ago

ahoymewmewBest ResponseYou've already chosen the best response.0
its factor for y @jackellyn which im not good at :I
 one year ago

jackellynBest ResponseYou've already chosen the best response.1
Okay, so the term that 5 and 125 have in common is 5, so you factor that out 125/5=25 so that leaves you with \[5(y ^{8}25)\]
 one year ago

jackellynBest ResponseYou've already chosen the best response.1
now, let's look at (y^825) y^8 is the same as (y^4)^2 and 25 is the same as (5)^2
 one year ago

jackellynBest ResponseYou've already chosen the best response.1
which will be a difference of squares so you split it into two (y⁴5)(y⁴+5) and one has a + and one has a  because the product of a + and  is  and dont forget the 5 up front so the answer is 5(y⁴5)(y⁴+5)
 one year ago

ahoymewmewBest ResponseYou've already chosen the best response.0
@jackellyn idk why its so hard for me to understand :c i used to know how to do factors but i forgot ._.
 one year ago

jackellynBest ResponseYou've already chosen the best response.1
its all about practice and knowing the rules lol
 one year ago
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