andriod09
  • andriod09
(x-4)(x-(1/4))(x+10)=(log(pi)+sin(pi/7)^0-1
Mathematics
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andriod09
  • andriod09
(x-4)(x-(1/4))(x+10)=(log(pi)+sin(pi/7)^0-1
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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dape
  • dape
So it looks pretty complicated, but if you take a look at the right side you see that the complex pi/log/sin stuff is all raised to the 0th power, which means it's 1 (ANYTHING raised to the 0th power is 1). So if we replace that by 1 we get \[ (x-4)(x-\frac{1}{4})(x+10)=1-1=0 \] Now it should be pretty easy.
andriod09
  • andriod09
I CANNOT SEE EQUATIONS FRO MTHE EQUATION BUTTON!!! ALL I SEE ARE THE SLASHES AND THE BRACKETS AND THE BRACES!!
dape
  • dape
Okay, what I wrote was: (x-4)(x-1/4)(x+10)=1-1=0

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andriod09
  • andriod09
and also, i kthe answer, i was wondering how many others can get it.

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