Dana plans to cover this model of a half moon completely with silver foil. How many square centimeters of silver foil would Dana need to cover the model completely? 402.2 536.2 603.4 150.8

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Dana plans to cover this model of a half moon completely with silver foil. How many square centimeters of silver foil would Dana need to cover the model completely? 402.2 536.2 603.4 150.8

Mathematics
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Dude, this is a homework help site, do not ask for emails :P
its not and ur a player

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Other answers:

well the surface area of a hemisphere is \[SA = \frac{1}{2}(4pir^2) + \pi r^2\] and you have a radius of 8 cm just substitute and solve.
i dont know how to do that
cause i just see leters
ok... do you have a calculator ?
yesss
ok you need to type in \[0.5 \times 4 \times \pi \times 8^2 + \pi \times 8^2\] that will give the answer to covering the hemisphere in foil..
Alrii so basically what campbell has show you is the surface are of a sphere. Any problem in which they ask for something that wraps around a specific shape involves surface are. The surface area of a sphere is: 4 pi r^2 Where r is the radius of the sphere.
what is p 12.18 or 12.14
If you're familiar with the button pi, it is the value of 3.14. Now for this particular question, it is a hemisphere. So half the surface are of the sphere. 1/2*(4pi r^2) = SA
thnks
@crystal1 what are you talking about>
you said:" what is p 12.18 or 12.14" what do you mean?
my bad sorry
so you got the answer?
wait
my answer is 5048.1152
nope... thats a long way from being correct
did you type in the equation I gave you as its written...?
Shall we break it down Campbell? I think it's the BEDMAS
Alright crystal, I want you to do r^2 first. Find the value of the radius squared.
yes i did @campbell_st
and tracks... I think you possible solution is missing the circular base... as the question talks about competely covering... it
you guys lost me now im confuse
ok... lets to it in little bits can you calculate \[0.5 \times 4 \times \pi \times 8^2\]
Ok my bad, alrii yeah you're right. I'll leave this to Campbell. Dont wanna confuse you,
@crystal1 did you get an answer for the new calculation..?
b
what was the number..?
i dont reaally know im sorry im dumb i dont know how to start this thats why i need help
You're not dumb. Tell yourself you're smart. You'll get the answer. Crystal, you got this. Wake up, look at what campbell wrote for you.
the answer is a
you're not finished yet. Add the pi r^2 to what you got to get the answer
nope thats only the 1st part of the problem the curved surface has an area of 402.2 cm^2 now you need to find the area of the circular base... \[\pi \times 8^2\]
you need to calculate this number...
then the final answer will be \[402.2 + \pi \times 8^2 = \]
6485.44
wow... nope not it lets make it easier what is \[\pi \times 8^2 =\]
75.36
nope still not right... \[\pi \times 8^2 = 201.1\]
how do you get thaat i tough that 8x2 its = 24
do you know how to square a number...
no
ok... then perhaps you need to ask you teacher... how to do the problem is you don't know the basics...
thnks you @campbell_st

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