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crystal1

  • 2 years ago

Dana plans to cover this model of a half moon completely with silver foil. How many square centimeters of silver foil would Dana need to cover the model completely? 402.2 536.2 603.4 150.8

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  1. crystal1
    • 2 years ago
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  2. trackzz
    • 2 years ago
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    Dude, this is a homework help site, do not ask for emails :P

  3. crystal1
    • 2 years ago
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    its not and ur a player

  4. crystal1
    • 2 years ago
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    true @trackzz

  5. campbell_st
    • 2 years ago
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    well the surface area of a hemisphere is \[SA = \frac{1}{2}(4pir^2) + \pi r^2\] and you have a radius of 8 cm just substitute and solve.

  6. crystal1
    • 2 years ago
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    i dont know how to do that

  7. crystal1
    • 2 years ago
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    cause i just see leters

  8. crystal1
    • 2 years ago
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    @campbell_st

  9. campbell_st
    • 2 years ago
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    ok... do you have a calculator ?

  10. crystal1
    • 2 years ago
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    yesss

  11. campbell_st
    • 2 years ago
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    ok you need to type in \[0.5 \times 4 \times \pi \times 8^2 + \pi \times 8^2\] that will give the answer to covering the hemisphere in foil..

  12. trackzz
    • 2 years ago
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    Alrii so basically what campbell has show you is the surface are of a sphere. Any problem in which they ask for something that wraps around a specific shape involves surface are. The surface area of a sphere is: 4 pi r^2 Where r is the radius of the sphere.

  13. crystal1
    • 2 years ago
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    what is p 12.18 or 12.14

  14. trackzz
    • 2 years ago
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    If you're familiar with the button pi, it is the value of 3.14. Now for this particular question, it is a hemisphere. So half the surface are of the sphere. 1/2*(4pi r^2) = SA

  15. crystal1
    • 2 years ago
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    thnks

  16. trackzz
    • 2 years ago
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    @crystal1 what are you talking about>

  17. trackzz
    • 2 years ago
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    you said:" what is p 12.18 or 12.14" what do you mean?

  18. crystal1
    • 2 years ago
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    my bad sorry

  19. trackzz
    • 2 years ago
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    so you got the answer?

  20. crystal1
    • 2 years ago
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    wait

  21. crystal1
    • 2 years ago
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    my answer is 5048.1152

  22. campbell_st
    • 2 years ago
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    nope... thats a long way from being correct

  23. campbell_st
    • 2 years ago
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    did you type in the equation I gave you as its written...?

  24. trackzz
    • 2 years ago
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    Shall we break it down Campbell? I think it's the BEDMAS

  25. trackzz
    • 2 years ago
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    Alright crystal, I want you to do r^2 first. Find the value of the radius squared.

  26. crystal1
    • 2 years ago
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    yes i did @campbell_st

  27. campbell_st
    • 2 years ago
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    and tracks... I think you possible solution is missing the circular base... as the question talks about competely covering... it

  28. crystal1
    • 2 years ago
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    you guys lost me now im confuse

  29. campbell_st
    • 2 years ago
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    ok... lets to it in little bits can you calculate \[0.5 \times 4 \times \pi \times 8^2\]

  30. trackzz
    • 2 years ago
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    Ok my bad, alrii yeah you're right. I'll leave this to Campbell. Dont wanna confuse you,

  31. campbell_st
    • 2 years ago
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    @crystal1 did you get an answer for the new calculation..?

  32. crystal1
    • 2 years ago
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    b

  33. campbell_st
    • 2 years ago
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    what was the number..?

  34. crystal1
    • 2 years ago
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    i dont reaally know im sorry im dumb i dont know how to start this thats why i need help

  35. trackzz
    • 2 years ago
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    You're not dumb. Tell yourself you're smart. You'll get the answer. Crystal, you got this. Wake up, look at what campbell wrote for you.

  36. crystal1
    • 2 years ago
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    the answer is a

  37. trackzz
    • 2 years ago
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    you're not finished yet. Add the pi r^2 to what you got to get the answer

  38. campbell_st
    • 2 years ago
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    nope thats only the 1st part of the problem the curved surface has an area of 402.2 cm^2 now you need to find the area of the circular base... \[\pi \times 8^2\]

  39. campbell_st
    • 2 years ago
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    you need to calculate this number...

  40. campbell_st
    • 2 years ago
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    then the final answer will be \[402.2 + \pi \times 8^2 = \]

  41. crystal1
    • 2 years ago
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    6485.44

  42. campbell_st
    • 2 years ago
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    wow... nope not it lets make it easier what is \[\pi \times 8^2 =\]

  43. crystal1
    • 2 years ago
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    75.36

  44. campbell_st
    • 2 years ago
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    nope still not right... \[\pi \times 8^2 = 201.1\]

  45. crystal1
    • 2 years ago
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    how do you get thaat i tough that 8x2 its = 24

  46. campbell_st
    • 2 years ago
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    do you know how to square a number...

  47. crystal1
    • 2 years ago
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    no

  48. campbell_st
    • 2 years ago
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    ok... then perhaps you need to ask you teacher... how to do the problem is you don't know the basics...

  49. crystal1
    • 2 years ago
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    thnks you @campbell_st

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