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anonymous
 3 years ago
Dana plans to cover this model of a half moon completely with silver foil.
How many square centimeters of silver foil would Dana need to cover the model completely?
402.2
536.2
603.4
150.8
anonymous
 3 years ago
Dana plans to cover this model of a half moon completely with silver foil. How many square centimeters of silver foil would Dana need to cover the model completely? 402.2 536.2 603.4 150.8

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Dude, this is a homework help site, do not ask for emails :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its not and ur a player

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3well the surface area of a hemisphere is \[SA = \frac{1}{2}(4pir^2) + \pi r^2\] and you have a radius of 8 cm just substitute and solve.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont know how to do that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cause i just see leters

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3ok... do you have a calculator ?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3ok you need to type in \[0.5 \times 4 \times \pi \times 8^2 + \pi \times 8^2\] that will give the answer to covering the hemisphere in foil..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Alrii so basically what campbell has show you is the surface are of a sphere. Any problem in which they ask for something that wraps around a specific shape involves surface are. The surface area of a sphere is: 4 pi r^2 Where r is the radius of the sphere.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what is p 12.18 or 12.14

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you're familiar with the button pi, it is the value of 3.14. Now for this particular question, it is a hemisphere. So half the surface are of the sphere. 1/2*(4pi r^2) = SA

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@crystal1 what are you talking about>

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you said:" what is p 12.18 or 12.14" what do you mean?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so you got the answer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my answer is 5048.1152

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3nope... thats a long way from being correct

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3did you type in the equation I gave you as its written...?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Shall we break it down Campbell? I think it's the BEDMAS

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Alright crystal, I want you to do r^2 first. Find the value of the radius squared.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes i did @campbell_st

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3and tracks... I think you possible solution is missing the circular base... as the question talks about competely covering... it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you guys lost me now im confuse

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3ok... lets to it in little bits can you calculate \[0.5 \times 4 \times \pi \times 8^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok my bad, alrii yeah you're right. I'll leave this to Campbell. Dont wanna confuse you,

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3@crystal1 did you get an answer for the new calculation..?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3what was the number..?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont reaally know im sorry im dumb i dont know how to start this thats why i need help

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You're not dumb. Tell yourself you're smart. You'll get the answer. Crystal, you got this. Wake up, look at what campbell wrote for you.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you're not finished yet. Add the pi r^2 to what you got to get the answer

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3nope thats only the 1st part of the problem the curved surface has an area of 402.2 cm^2 now you need to find the area of the circular base... \[\pi \times 8^2\]

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3you need to calculate this number...

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3then the final answer will be \[402.2 + \pi \times 8^2 = \]

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3wow... nope not it lets make it easier what is \[\pi \times 8^2 =\]

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3nope still not right... \[\pi \times 8^2 = 201.1\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how do you get thaat i tough that 8x2 its = 24

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3do you know how to square a number...

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.3ok... then perhaps you need to ask you teacher... how to do the problem is you don't know the basics...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thnks you @campbell_st
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