lovinglyhated
how do you find out how many solutions there are for x^2+2x+8
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anonymous
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try to solve
or use \(b^2-4ac\) are you allowed complex solutions?
lovinglyhated
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yeah
dape
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Fundamental theorem of algebra implies that a polynomial of degree n always has n roots, counting repeated roots. So since it's of degree 2, it has 2 roots.
lovinglyhated
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?
dape
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Since it's a second degree polynomial (highest term is a power of 2, the x^2), it automatically must have 2 solutions.
lovinglyhated
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oh ok
harsh314
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the maximum no. of solutions is 2.............
dape
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It has 2 solutions,
\[ x=-1±i\sqrt{7}. \]
harsh314
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it has no real solution........
lovinglyhated
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thankx