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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0try to solve or use \(b^24ac\) are you allowed complex solutions?

dape
 2 years ago
Best ResponseYou've already chosen the best response.0Fundamental theorem of algebra implies that a polynomial of degree n always has n roots, counting repeated roots. So since it's of degree 2, it has 2 roots.

dape
 2 years ago
Best ResponseYou've already chosen the best response.0Since it's a second degree polynomial (highest term is a power of 2, the x^2), it automatically must have 2 solutions.

harsh314
 2 years ago
Best ResponseYou've already chosen the best response.0the maximum no. of solutions is 2.............

dape
 2 years ago
Best ResponseYou've already chosen the best response.0It has 2 solutions, \[ x=1±i\sqrt{7}. \]

harsh314
 2 years ago
Best ResponseYou've already chosen the best response.0it has no real solution........
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