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lovinglyhated
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how do you find out how many solutions there are for x^2+2x+8
 one year ago
 one year ago
lovinglyhated Group Title
how do you find out how many solutions there are for x^2+2x+8
 one year ago
 one year ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
try to solve or use \(b^24ac\) are you allowed complex solutions?
 one year ago

lovinglyhated Group TitleBest ResponseYou've already chosen the best response.0
yeah
 one year ago

dape Group TitleBest ResponseYou've already chosen the best response.0
Fundamental theorem of algebra implies that a polynomial of degree n always has n roots, counting repeated roots. So since it's of degree 2, it has 2 roots.
 one year ago

dape Group TitleBest ResponseYou've already chosen the best response.0
Since it's a second degree polynomial (highest term is a power of 2, the x^2), it automatically must have 2 solutions.
 one year ago

lovinglyhated Group TitleBest ResponseYou've already chosen the best response.0
oh ok
 one year ago

harsh314 Group TitleBest ResponseYou've already chosen the best response.0
the maximum no. of solutions is 2.............
 one year ago

dape Group TitleBest ResponseYou've already chosen the best response.0
It has 2 solutions, \[ x=1±i\sqrt{7}. \]
 one year ago

harsh314 Group TitleBest ResponseYou've already chosen the best response.0
it has no real solution........
 one year ago

lovinglyhated Group TitleBest ResponseYou've already chosen the best response.0
thankx
 one year ago
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