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lovinglyhated

how do you find out how many solutions there are for x^2+2x+8

  • one year ago
  • one year ago

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  1. satellite73
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    try to solve or use \(b^2-4ac\) are you allowed complex solutions?

    • one year ago
  2. lovinglyhated
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    yeah

    • one year ago
  3. dape
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    Fundamental theorem of algebra implies that a polynomial of degree n always has n roots, counting repeated roots. So since it's of degree 2, it has 2 roots.

    • one year ago
  4. lovinglyhated
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    ?

    • one year ago
  5. dape
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    Since it's a second degree polynomial (highest term is a power of 2, the x^2), it automatically must have 2 solutions.

    • one year ago
  6. lovinglyhated
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    oh ok

    • one year ago
  7. harsh314
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    the maximum no. of solutions is 2.............

    • one year ago
  8. dape
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    It has 2 solutions, \[ x=-1±i\sqrt{7}. \]

    • one year ago
  9. harsh314
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    it has no real solution........

    • one year ago
  10. lovinglyhated
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    thankx

    • one year ago
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