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Calle87
 2 years ago
differentiate using the definition
Calle87
 2 years ago
differentiate using the definition

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Calle87
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ \sqrt{x} }\]

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2it's lim as h>0 (f(x+h)f(x))/h

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2f(x+h) = 1/sqrt(x+h) f(x) = 1/sqrt(x)

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2Do some algebra, cancel out the hs

Calle87
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ \frac{ 1 }{ \sqrt{x+h} }\frac{ 1 }{ \sqrt{x} } }{ h }\]

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2yea, now multiply by the conjugate i think.. both top and bottom

Calle87
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ \frac{ \sqrt{x}+\sqrt{xh}}{ \sqrt{x}\sqrt{x+h} } }{ h }\]

Calle87
 2 years ago
Best ResponseYou've already chosen the best response.0oops meant to put the h on the bottom :}

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2it's supposed to be a minus

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2all the way on top in the middle

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2and the other one on top must be a plus

across
 2 years ago
Best ResponseYou've already chosen the best response.1Inside the radical, too.

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2u mixed up the signs

Calle87
 2 years ago
Best ResponseYou've already chosen the best response.0ok so i got all that part, the conjugates are what get me

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2twiddla time then.. hang on a sec

Calle87
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ h }{ h \sqrt{x}\sqrt{x+h(\sqrt{x}+\sqrt{x+h})} }\]

Calle87
 2 years ago
Best ResponseYou've already chosen the best response.0that square root is mess up in the bottom

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2No, since h is 0, on the bottom u just have sqrt(x+0)

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2so it's 1/sqrt(x) which is correct

Calle87
 2 years ago
Best ResponseYou've already chosen the best response.0at what point do i make h = 0?

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.2when u dont run into trouble if u do.

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.21/h < NO 1/(4+1) < YES
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