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darkwhale
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Astronauts on our moon must function with an acceleration due to gravity of 0.170g . If an astronaut can throw a certain wrench 12.0m vertically upward on earth, how high could he throw it on our moon if he gives it the same starting speed in both places?
How much longer would it be in motion (going up and coming down) on the moon than on earth?
 2 years ago
 2 years ago
darkwhale Group Title
Astronauts on our moon must function with an acceleration due to gravity of 0.170g . If an astronaut can throw a certain wrench 12.0m vertically upward on earth, how high could he throw it on our moon if he gives it the same starting speed in both places? How much longer would it be in motion (going up and coming down) on the moon than on earth?
 2 years ago
 2 years ago

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salini Group TitleBest ResponseYou've already chosen the best response.0
u know the acceleration on earth and moon for a given distance say x calculate teh time of motion
 2 years ago

darkwhale Group TitleBest ResponseYou've already chosen the best response.0
2. t=Vo/A
 2 years ago

imron07 Group TitleBest ResponseYou've already chosen the best response.0
Find h with this: \[v^2=v_0^2+2ah\] Since v=0 at highest point, you can find then: \[0=v_0^2+2ah \\h=\sqrt{\frac{v_0^2}{2a}}\\\frac{h_{m}}{h_{e}}=\frac{\sqrt{\frac{v_0^2}{2a_m}}}{\sqrt{\frac{v_0^2}{2a_e}}} \]
 2 years ago

darkwhale Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 9.81 }{ 1.67 }12.0\] h=70.6, but how do u solve the second part?
 2 years ago

imron07 Group TitleBest ResponseYou've already chosen the best response.0
\[v=v_0gt\] again, \[v=0\] then you can find time traveled by wrench for each g's
 2 years ago

darkwhale Group TitleBest ResponseYou've already chosen the best response.0
i'm not sure how to get Vo
 2 years ago

darkwhale Group TitleBest ResponseYou've already chosen the best response.0
oh is it 12m/s?
 2 years ago

imron07 Group TitleBest ResponseYou've already chosen the best response.0
You can find v0, but don't really need to. \[0=v_0gt\\t=\frac{v_0}{g}\\\frac{t_e}{t_m}=\frac{v_0/g_e}{v_0/g_m} \]
 2 years ago

darkwhale Group TitleBest ResponseYou've already chosen the best response.0
but dont i need both Vo and t?
 2 years ago

darkwhale Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ Te }{ Tm } =\frac{ 1.67 }{ 9.8 }\]
 2 years ago

darkwhale Group TitleBest ResponseYou've already chosen the best response.0
so its 0.170?
 2 years ago

imron07 Group TitleBest ResponseYou've already chosen the best response.0
Wait, i'm not native eng speaker. What do they mean when they say how much longer? If they mean \[\Delta t=t_mt_e\] then we're wrong. What we found is \[t_m=0.170t_e\].
 2 years ago

darkwhale Group TitleBest ResponseYou've already chosen the best response.0
yeah Δt=tm−te
 2 years ago
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