A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
Astronauts on our moon must function with an acceleration due to gravity of 0.170g . If an astronaut can throw a certain wrench 12.0m vertically upward on earth, how high could he throw it on our moon if he gives it the same starting speed in both places?
How much longer would it be in motion (going up and coming down) on the moon than on earth?
 2 years ago
Astronauts on our moon must function with an acceleration due to gravity of 0.170g . If an astronaut can throw a certain wrench 12.0m vertically upward on earth, how high could he throw it on our moon if he gives it the same starting speed in both places? How much longer would it be in motion (going up and coming down) on the moon than on earth?

This Question is Closed

salini
 2 years ago
Best ResponseYou've already chosen the best response.0u know the acceleration on earth and moon for a given distance say x calculate teh time of motion

imron07
 2 years ago
Best ResponseYou've already chosen the best response.0Find h with this: \[v^2=v_0^2+2ah\] Since v=0 at highest point, you can find then: \[0=v_0^2+2ah \\h=\sqrt{\frac{v_0^2}{2a}}\\\frac{h_{m}}{h_{e}}=\frac{\sqrt{\frac{v_0^2}{2a_m}}}{\sqrt{\frac{v_0^2}{2a_e}}} \]

darkwhale
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 9.81 }{ 1.67 }12.0\] h=70.6, but how do u solve the second part?

imron07
 2 years ago
Best ResponseYou've already chosen the best response.0\[v=v_0gt\] again, \[v=0\] then you can find time traveled by wrench for each g's

darkwhale
 2 years ago
Best ResponseYou've already chosen the best response.0i'm not sure how to get Vo

imron07
 2 years ago
Best ResponseYou've already chosen the best response.0You can find v0, but don't really need to. \[0=v_0gt\\t=\frac{v_0}{g}\\\frac{t_e}{t_m}=\frac{v_0/g_e}{v_0/g_m} \]

darkwhale
 2 years ago
Best ResponseYou've already chosen the best response.0but dont i need both Vo and t?

darkwhale
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ Te }{ Tm } =\frac{ 1.67 }{ 9.8 }\]

imron07
 2 years ago
Best ResponseYou've already chosen the best response.0Wait, i'm not native eng speaker. What do they mean when they say how much longer? If they mean \[\Delta t=t_mt_e\] then we're wrong. What we found is \[t_m=0.170t_e\].
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.