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anonymous
 3 years ago
Ok, this is quite a big one.. I just need to know what formulas to use for certain parts of the question:
Matty the moth is on a turntable spinning at (2 3/8) rotations in 8 seconds. Bob is 11cm away from the center.
A)Find the angular displacement of Bob.
B)Find the angular velocity in rads per second.
C)Find the distance that Bob traveled in 8 seconds.
D)Find the linear velocity of Bob in cm per second.
anonymous
 3 years ago
Ok, this is quite a big one.. I just need to know what formulas to use for certain parts of the question: Matty the moth is on a turntable spinning at (2 3/8) rotations in 8 seconds. Bob is 11cm away from the center. A)Find the angular displacement of Bob. B)Find the angular velocity in rads per second. C)Find the distance that Bob traveled in 8 seconds. D)Find the linear velocity of Bob in cm per second.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I already have the answers, just need the formulas and/or some examples of what to do  studying.

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.1\[\omega=\theta/t\] \[l=s/t\]

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.1w is the angular velocity. l is the linear velocity. s is the arc length you can also make another equation for l by using those formula \[s=\theta r\]

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.1so l is also \[l=\omega r\]

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.1also do not forget to convert revolutions (rev) to radians . theta should be in radians you can convert it by multiplying to 2pi

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\theta=revs \times2\pi rads\] Correct?

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.1yes, do you know why it is correct ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I guess i have been paying enough attention in trig haha, thanks again
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