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Rebbbtx
Group Title
Can someone please show me step by step, how to factor this equation? a^3xb^3xa^3y+b^3y
the answer = (ab)(a^2+ab+b^2)(xy)
 one year ago
 one year ago
Rebbbtx Group Title
Can someone please show me step by step, how to factor this equation? a^3xb^3xa^3y+b^3y the answer = (ab)(a^2+ab+b^2)(xy)
 one year ago
 one year ago

This Question is Open

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
a^3xb^3xa^3y+b^3y (a^3b^3)x  (a^3 b^3)y
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Did u get that step?
 one year ago

Rebbbtx Group TitleBest ResponseYou've already chosen the best response.0
okay, yes. First you take the x and y out
 one year ago

Rebbbtx Group TitleBest ResponseYou've already chosen the best response.0
what next?
 one year ago

Hezekieli Group TitleBest ResponseYou've already chosen the best response.0
One could also start by taking a and b out:\[a^{3}(xy)+b^{3}(yx)\] But I don't really know how to get to that answer or why to aim at that? :o
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
The best way to do it: FIND THE COMMON NUMBER BETWEEN EVERYTHING.
 one year ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.1
\[a^3b^3=(ab)(a^2+ab+b^2)\]
 one year ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.1
Got the answer?
 one year ago

Hezekieli Group TitleBest ResponseYou've already chosen the best response.0
You can check that what abdul said by going backwards: \[(a  b)(a ^{2} + ab + b ^{2})\] \[= (a^{3}+a^{2}b + ab^{2}) + (a^{2}b  ab^{2}  b^{3})\] \[= a^{3}+a^{2}b  a^{2}b + ab^{2}  ab^{2}  b^{3}\] \[= a^{3}  b^{3}\] Not sure yet how to get that (x  y) out o.O
 one year ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.1
\[a^3xb^3xa^3y+b^3y\] \[x(a^3b^3)y(a^3b^3)\] \[(a^3b^3)(xy)\] \[(ab)(a^2+ab+b^2)(xy)\]
 one year ago
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