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Can someone please show me step by step, how to factor this equation? a^3xb^3xa^3y+b^3y
the answer = (ab)(a^2+ab+b^2)(xy)
 one year ago
 one year ago
Can someone please show me step by step, how to factor this equation? a^3xb^3xa^3y+b^3y the answer = (ab)(a^2+ab+b^2)(xy)
 one year ago
 one year ago

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sauravshakyaBest ResponseYou've already chosen the best response.2
a^3xb^3xa^3y+b^3y (a^3b^3)x  (a^3 b^3)y
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Did u get that step?
 one year ago

RebbbtxBest ResponseYou've already chosen the best response.0
okay, yes. First you take the x and y out
 one year ago

HezekieliBest ResponseYou've already chosen the best response.0
One could also start by taking a and b out:\[a^{3}(xy)+b^{3}(yx)\] But I don't really know how to get to that answer or why to aim at that? :o
 one year ago

andriod09Best ResponseYou've already chosen the best response.0
The best way to do it: FIND THE COMMON NUMBER BETWEEN EVERYTHING.
 one year ago

abdul_shabeerBest ResponseYou've already chosen the best response.1
\[a^3b^3=(ab)(a^2+ab+b^2)\]
 one year ago

HezekieliBest ResponseYou've already chosen the best response.0
You can check that what abdul said by going backwards: \[(a  b)(a ^{2} + ab + b ^{2})\] \[= (a^{3}+a^{2}b + ab^{2}) + (a^{2}b  ab^{2}  b^{3})\] \[= a^{3}+a^{2}b  a^{2}b + ab^{2}  ab^{2}  b^{3}\] \[= a^{3}  b^{3}\] Not sure yet how to get that (x  y) out o.O
 one year ago

abdul_shabeerBest ResponseYou've already chosen the best response.1
\[a^3xb^3xa^3y+b^3y\] \[x(a^3b^3)y(a^3b^3)\] \[(a^3b^3)(xy)\] \[(ab)(a^2+ab+b^2)(xy)\]
 one year ago
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