anonymous
  • anonymous
Find the area of the trapezoid shown.
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
1/2 *8 *4 sin(60) + 4*12 +1/2*4*4
anonymous
  • anonymous
The area for the right triangle at the left is 1/2 *8*4 *sin(60) where 60 is the angle b/n the sides with length 8 and 4.

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anonymous
  • anonymous
Okay. So the equation is 1/2 *8 *4 sin(60) + 4*12 +1/2*4*4 ?
anonymous
  • anonymous
And the area of the 4 by 12 rectangle is 12*4
anonymous
  • anonymous
48 is the area of the rectangle, plus the area of the triangle= Area of Trapezoid?
anonymous
  • anonymous
nope Finally the right triangle at the right of the trapezoid (16-12)*4
anonymous
  • anonymous
16 + 48 +area of triangle?
anonymous
  • anonymous
sorry 1/2*(16-12)*4
anonymous
  • anonymous
So 8?
anonymous
  • anonymous
yes thus the area is 16sin(60) + 48 +8
anonymous
  • anonymous
51?
anonymous
  • anonymous
Nope 8*3^(1/2) +56
anonymous
  • anonymous
That turns into a radical? @ zekarias
anonymous
  • anonymous
yes
anonymous
  • anonymous
They don't want a radical...
anonymous
  • anonymous
But the answer need.
anonymous
  • anonymous
The answer should just be a normal integer

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