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Find the area of the trapezoid shown.

Mathematics
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1 Attachment
1/2 *8 *4 sin(60) + 4*12 +1/2*4*4
The area for the right triangle at the left is 1/2 *8*4 *sin(60) where 60 is the angle b/n the sides with length 8 and 4.

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Other answers:

Okay. So the equation is 1/2 *8 *4 sin(60) + 4*12 +1/2*4*4 ?
And the area of the 4 by 12 rectangle is 12*4
48 is the area of the rectangle, plus the area of the triangle= Area of Trapezoid?
nope Finally the right triangle at the right of the trapezoid (16-12)*4
16 + 48 +area of triangle?
sorry 1/2*(16-12)*4
So 8?
yes thus the area is 16sin(60) + 48 +8
51?
Nope 8*3^(1/2) +56
That turns into a radical? @ zekarias
yes
They don't want a radical...
But the answer need.
The answer should just be a normal integer

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