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Dallasb22

  • 2 years ago

Find the area of the trapezoid shown.

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  1. Dallasb22
    • 2 years ago
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  2. Zekarias
    • 2 years ago
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    1/2 *8 *4 sin(60) + 4*12 +1/2*4*4

  3. Zekarias
    • 2 years ago
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    The area for the right triangle at the left is 1/2 *8*4 *sin(60) where 60 is the angle b/n the sides with length 8 and 4.

  4. Dallasb22
    • 2 years ago
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    Okay. So the equation is 1/2 *8 *4 sin(60) + 4*12 +1/2*4*4 ?

  5. Zekarias
    • 2 years ago
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    And the area of the 4 by 12 rectangle is 12*4

  6. Dallasb22
    • 2 years ago
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    48 is the area of the rectangle, plus the area of the triangle= Area of Trapezoid?

  7. Zekarias
    • 2 years ago
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    nope Finally the right triangle at the right of the trapezoid (16-12)*4

  8. Dallasb22
    • 2 years ago
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    16 + 48 +area of triangle?

  9. Zekarias
    • 2 years ago
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    sorry 1/2*(16-12)*4

  10. Dallasb22
    • 2 years ago
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    So 8?

  11. Zekarias
    • 2 years ago
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    yes thus the area is 16sin(60) + 48 +8

  12. Dallasb22
    • 2 years ago
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    51?

  13. Zekarias
    • 2 years ago
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    Nope 8*3^(1/2) +56

  14. Dallasb22
    • 2 years ago
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    That turns into a radical? @ zekarias

  15. Zekarias
    • 2 years ago
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    yes

  16. Dallasb22
    • 2 years ago
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    They don't want a radical...

  17. Zekarias
    • 2 years ago
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    But the answer need.

  18. Dallasb22
    • 2 years ago
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    The answer should just be a normal integer

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