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anonymous
 4 years ago
Need help! Explain why the function is discontinuous at the given number a. Sketch the graph of the function!
anonymous
 4 years ago
Need help! Explain why the function is discontinuous at the given number a. Sketch the graph of the function!

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jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1what is cos(0)

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1so notice how in the first piece, the y value at x = 0 is 1 but the y value in the second piece at x = 0 is 0 Can you visualize what I'm describing?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea so that means \[\cos x \neq x=0\]

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1do you mean cos(x) doesn't equal x when x = 0?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea because at x its 0 and at x<0 its 1

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1then you are correct, and this shows us that there is a discontinuity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright kool thanks and does the graph looks like this?dw:1348180882506:dw

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1you're on the right track

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1however, you only graph cos(x) when x < 0

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1and you only graph 1  x^2 when x > 0

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1make sure you draw a hole at (0,1) and a closed circle at (0,0)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1348181069990:dw like this?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1closer, but now erase the piece of cos(x) that's to the right of x = 0 and erase the piece of 1  x^2 that's to the left of x = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1348181225073:dw

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1good, you got it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright thanks for ur help!
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