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anonymous
 4 years ago
In the morning, Alan drove 100 miles at the rate of
60 miles per hour; in the afternoon, he drove
another 100 miles at the rate of 40 miles
per hour. What was his average rate of speed,
in miles per hour, for the day?
anonymous
 4 years ago
In the morning, Alan drove 100 miles at the rate of 60 miles per hour; in the afternoon, he drove another 100 miles at the rate of 40 miles per hour. What was his average rate of speed, in miles per hour, for the day?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh i mean heck no to 50

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0average speed is not the average of the speeds

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh man, you are a guru

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you are even higher than DA PANIC!!!!!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh, sorry...just been a while since I've done these...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0figure out how long it took to get there, then figure out how long it took to get back that is the total time divide the total distance (200 miles ) by the total time to get the average speed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0time going it \(\frac{100}{60}\) time returning is \(\frac{100}{40}\) total time is \[\frac{100}{60}+\frac{100}{40}=\frac{25}{6}\] and \[200\div \frac{25}{6}=200\times \frac{6}{25}=8\times 6=48\] as luisz said

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.05/2+5/3=15/6+10/6=25/6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0200 divided by 25/6=48

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you nothing about truth tables, guru?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now redo the problem replacing 100 by \(m\) and see that the answer is still 48 mph

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0by friend, aripotta needs help with them?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its not me who needs help with them

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm posting a different problem
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