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luisz
 3 years ago
In the morning, Alan drove 100 miles at the rate of
60 miles per hour; in the afternoon, he drove
another 100 miles at the rate of 40 miles
per hour. What was his average rate of speed,
in miles per hour, for the day?
luisz
 3 years ago
In the morning, Alan drove 100 miles at the rate of 60 miles per hour; in the afternoon, he drove another 100 miles at the rate of 40 miles per hour. What was his average rate of speed, in miles per hour, for the day?

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satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1oh i mean heck no to 50

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1average speed is not the average of the speeds

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1you are even higher than DA PANIC!!!!!!

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, sorry...just been a while since I've done these...

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1figure out how long it took to get there, then figure out how long it took to get back that is the total time divide the total distance (200 miles ) by the total time to get the average speed

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1time going it \(\frac{100}{60}\) time returning is \(\frac{100}{40}\) total time is \[\frac{100}{60}+\frac{100}{40}=\frac{25}{6}\] and \[200\div \frac{25}{6}=200\times \frac{6}{25}=8\times 6=48\] as luisz said

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1you nothing about truth tables, guru?

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1now redo the problem replacing 100 by \(m\) and see that the answer is still 48 mph

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1by friend, aripotta needs help with them?

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1yes, we can do them

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1its not me who needs help with them

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1I'm posting a different problem
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