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In the morning, Alan drove 100 miles at the rate of
60 miles per hour; in the afternoon, he drove
another 100 miles at the rate of 40 miles
per hour. What was his average rate of speed,
in miles per hour, for the day?
 one year ago
 one year ago
In the morning, Alan drove 100 miles at the rate of 60 miles per hour; in the afternoon, he drove another 100 miles at the rate of 40 miles per hour. What was his average rate of speed, in miles per hour, for the day?
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.1
oh i mean heck no to 50
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
average speed is not the average of the speeds
 one year ago

luiszBest ResponseYou've already chosen the best response.1
you are even higher than DA PANIC!!!!!!
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Oh, sorry...just been a while since I've done these...
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
figure out how long it took to get there, then figure out how long it took to get back that is the total time divide the total distance (200 miles ) by the total time to get the average speed
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
time going it \(\frac{100}{60}\) time returning is \(\frac{100}{40}\) total time is \[\frac{100}{60}+\frac{100}{40}=\frac{25}{6}\] and \[200\div \frac{25}{6}=200\times \frac{6}{25}=8\times 6=48\] as luisz said
 one year ago

luiszBest ResponseYou've already chosen the best response.1
you nothing about truth tables, guru?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
now redo the problem replacing 100 by \(m\) and see that the answer is still 48 mph
 one year ago

luiszBest ResponseYou've already chosen the best response.1
by friend, aripotta needs help with them?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
yes, we can do them
 one year ago

luiszBest ResponseYou've already chosen the best response.1
its not me who needs help with them
 one year ago

luiszBest ResponseYou've already chosen the best response.1
I'm posting a different problem
 one year ago
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