anonymous
  • anonymous
In the morning, Alan drove 100 miles at the rate of 60 miles per hour; in the afternoon, he drove another 100 miles at the rate of 40 miles per hour. What was his average rate of speed, in miles per hour, for the day?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
k...
anonymous
  • anonymous
d=100
anonymous
  • anonymous
anything?

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More answers

anonymous
  • anonymous
ahh
anonymous
  • anonymous
60+40/2=50
anonymous
  • anonymous
derp
anonymous
  • anonymous
C.
anonymous
  • anonymous
no
anonymous
  • anonymous
B.
anonymous
  • anonymous
48
anonymous
  • anonymous
nope
anonymous
  • anonymous
that'swrong
anonymous
  • anonymous
it's 48
anonymous
  • anonymous
heck no
anonymous
  • anonymous
oh i mean heck no to 50
anonymous
  • anonymous
average speed is not the average of the speeds
anonymous
  • anonymous
oh man, you are a guru
anonymous
  • anonymous
you are even higher than DA PANIC!!!!!!
anonymous
  • anonymous
Oh, sorry...just been a while since I've done these...
anonymous
  • anonymous
figure out how long it took to get there, then figure out how long it took to get back that is the total time divide the total distance (200 miles ) by the total time to get the average speed
anonymous
  • anonymous
2.5+1.666666667
anonymous
  • anonymous
divided by 200
anonymous
  • anonymous
equal 48
anonymous
  • anonymous
that it?
anonymous
  • anonymous
200/4.166666667?
anonymous
  • anonymous
=48
anonymous
  • anonymous
100/60=5/3
anonymous
  • anonymous
100/40=2.5
anonymous
  • anonymous
time going it \(\frac{100}{60}\) time returning is \(\frac{100}{40}\) total time is \[\frac{100}{60}+\frac{100}{40}=\frac{25}{6}\] and \[200\div \frac{25}{6}=200\times \frac{6}{25}=8\times 6=48\] as luisz said
anonymous
  • anonymous
5/2+5/3=15/6+10/6=25/6
anonymous
  • anonymous
200 divided by 25/6=48
anonymous
  • anonymous
ty
anonymous
  • anonymous
you nothing about truth tables, guru?
anonymous
  • anonymous
now redo the problem replacing 100 by \(m\) and see that the answer is still 48 mph
anonymous
  • anonymous
by friend, aripotta needs help with them?
anonymous
  • anonymous
yes, we can do them
anonymous
  • anonymous
go ahead and post
anonymous
  • anonymous
its not me who needs help with them
anonymous
  • anonymous
its aripotta
anonymous
  • anonymous
I'm posting a different problem

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