In the morning, Alan drove 100 miles at the rate of 60 miles per hour; in the afternoon, he drove another 100 miles at the rate of 40 miles per hour. What was his average rate of speed, in miles per hour, for the day?

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In the morning, Alan drove 100 miles at the rate of 60 miles per hour; in the afternoon, he drove another 100 miles at the rate of 40 miles per hour. What was his average rate of speed, in miles per hour, for the day?

Mathematics
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k...
d=100
anything?

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Other answers:

ahh
60+40/2=50
derp
C.
no
B.
48
nope
that'swrong
it's 48
heck no
oh i mean heck no to 50
average speed is not the average of the speeds
oh man, you are a guru
you are even higher than DA PANIC!!!!!!
Oh, sorry...just been a while since I've done these...
figure out how long it took to get there, then figure out how long it took to get back that is the total time divide the total distance (200 miles ) by the total time to get the average speed
2.5+1.666666667
divided by 200
equal 48
that it?
200/4.166666667?
=48
100/60=5/3
100/40=2.5
time going it \(\frac{100}{60}\) time returning is \(\frac{100}{40}\) total time is \[\frac{100}{60}+\frac{100}{40}=\frac{25}{6}\] and \[200\div \frac{25}{6}=200\times \frac{6}{25}=8\times 6=48\] as luisz said
5/2+5/3=15/6+10/6=25/6
200 divided by 25/6=48
ty
you nothing about truth tables, guru?
now redo the problem replacing 100 by \(m\) and see that the answer is still 48 mph
by friend, aripotta needs help with them?
yes, we can do them
go ahead and post
its not me who needs help with them
its aripotta
I'm posting a different problem

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