anonymous
  • anonymous
find line tangent to y=xcosx at point (pi, -pi)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
tangent is -1
anonymous
  • anonymous
just typed y=-1 in. says incorrect
anonymous
  • anonymous
the equation should be y = -x

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anonymous
  • anonymous
yep, ty.
anonymous
  • anonymous
this is how I calculated it. y = xCosx is the function. taking it's derivative gives the slope to be dy/dx = cosx, which when evaluated at x =pi gives -1. now equation of line is y=mx+c, we know m=-1 and putting y = -pi and x = pi we get c =0. thus the equation of line tangent to the curve is y =-x
anonymous
  • anonymous
ok

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