find line tangent to y=xcosx at point (pi, -pi)

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find line tangent to y=xcosx at point (pi, -pi)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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tangent is -1
just typed y=-1 in. says incorrect
the equation should be y = -x

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yep, ty.
this is how I calculated it. y = xCosx is the function. taking it's derivative gives the slope to be dy/dx = cosx, which when evaluated at x =pi gives -1. now equation of line is y=mx+c, we know m=-1 and putting y = -pi and x = pi we get c =0. thus the equation of line tangent to the curve is y =-x
ok

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