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steel11

  • 3 years ago

differentiate 9sec6x do i have to use both product and chain rules?

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  1. pitankar
    • 3 years ago
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    yes!

  2. steel11
    • 3 years ago
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    somebody mind so it as well so i can see how its done? derivative of sec is secxtanx and thats messing me up

  3. steel11
    • 3 years ago
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    doing it as well*

  4. pitankar
    • 3 years ago
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    convert the secx to 1/cosx, that should help. And secx.tanx =sinx

  5. oldrin.bataku
    • 3 years ago
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    What is the function you wish to differentiate? \[\ \ \ \ 9\sec{x} * 6x\\ = 54x\sec{x}\tan{x} + 54\sec{x}\\ = 54\sec{x}\ [x\tan{x} + 1]\]

  6. steel11
    • 3 years ago
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    when i replaced sec6x with 1/cos6x, this is what i got as my final answer, still wrong though. (0*1/cos6x)+(9+1/-sinx*6)

  7. pitankar
    • 3 years ago
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    I guess you made a mistake in writing the post, it says secx6x, the function is sec6x???

  8. steel11
    • 3 years ago
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    oh wow, your right. my fault. differentiate 9sec6x

  9. pitankar
    • 3 years ago
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    use the chain rule only!

  10. steel11
    • 3 years ago
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    ah. so it was a chain rule only problem? or could it be done using both product and chain?

  11. steel11
    • 3 years ago
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    ugh. i just copied pasted your exact answer, says it was wrong. ._.

  12. steel11
    • 3 years ago
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    still keeps saying incorrect. >.<

  13. pitankar
    • 3 years ago
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    I crossed check, the answer indeed is 54*sec6x*tan6x. Just see if the equation was properly written. I mean I wrote 54sec6x.tan6x, try using 54*sec(6x)*tan(6x). hope that would work

  14. steel11
    • 3 years ago
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    yep, was written wrong, thank you for helping me these past 15-20 minutes!

  15. pitankar
    • 3 years ago
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    ^_^

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