anonymous
  • anonymous
differentiate 9sec6x do i have to use both product and chain rules?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
yes!
anonymous
  • anonymous
somebody mind so it as well so i can see how its done? derivative of sec is secxtanx and thats messing me up
anonymous
  • anonymous
doing it as well*

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anonymous
  • anonymous
convert the secx to 1/cosx, that should help. And secx.tanx =sinx
anonymous
  • anonymous
What is the function you wish to differentiate? \[\ \ \ \ 9\sec{x} * 6x\\ = 54x\sec{x}\tan{x} + 54\sec{x}\\ = 54\sec{x}\ [x\tan{x} + 1]\]
anonymous
  • anonymous
when i replaced sec6x with 1/cos6x, this is what i got as my final answer, still wrong though. (0*1/cos6x)+(9+1/-sinx*6)
anonymous
  • anonymous
I guess you made a mistake in writing the post, it says secx6x, the function is sec6x???
anonymous
  • anonymous
oh wow, your right. my fault. differentiate 9sec6x
anonymous
  • anonymous
use the chain rule only!
anonymous
  • anonymous
ah. so it was a chain rule only problem? or could it be done using both product and chain?
anonymous
  • anonymous
ugh. i just copied pasted your exact answer, says it was wrong. ._.
anonymous
  • anonymous
still keeps saying incorrect. >.<
anonymous
  • anonymous
I crossed check, the answer indeed is 54*sec6x*tan6x. Just see if the equation was properly written. I mean I wrote 54sec6x.tan6x, try using 54*sec(6x)*tan(6x). hope that would work
anonymous
  • anonymous
yep, was written wrong, thank you for helping me these past 15-20 minutes!
anonymous
  • anonymous
^_^

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