Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

sara1234

  • 2 years ago

State the horizontal asymptote of the rational function.

  • This Question is Closed
  1. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    numerator degree is 1, denominator has degree 2 and since 2 is larger than 1 the horizontal asymptote is \(y=0\)

  2. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    for the vertical asymptotes, set the denominator equal to zero and solve for \(x\)

  3. sara1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i dont get how you got y=o pplz help with horizontal

  4. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if the degree of the numerator is smaller than the degree of the denominator, you will have a horizontal asymptote at \(y=0\) aka the \(x\)- axis do you know what i mean by degree?

  5. sara1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah i know what degree is

  6. sara1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    what if the degree of the numnater is bigger

  7. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok then that is all you need to consider think about what would happen if you put in say \(x=10^6\) you would have a million in the numerator but you would have \(10^{12}\) in the denominator, and get a very small number (close to zero)

  8. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if the degree of the numerator is larger, no horizontal asymptote

  9. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    and if the degrees are the same, it is the ratio of the leading coefficients

  10. sara1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so its allways y=0 when the top is smaller and none when the top is larger

  11. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, always

  12. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    and if they are the same, for example \[\frac{2x^2+3x-3}{5x^2+10}\] i would be \(y=\frac{2}{5}\)

  13. sara1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    why 5?

  14. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you got that? three cases 1) top is larger: none 2) bottom is larger :\(y=0\) 3) the degrees are equal: \(y=\text{ratio of leading coefficients}\)

  15. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    in my example \[\frac{2x^2+3x-3}{5x^2+10}\] the degrees are both two the leading coefficient of the numerator is 2 the leading coefficent of the denominator is 5 so horizontal asymptote is \(y=\frac{2}{5}\)

  16. sara1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    State the horizontal asymptote of the rational function. 9x^2-3x-8 --------- 4x^2-5x+3 so this would be y=9/4?

  17. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sure would

  18. sara1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    thanks your the best!! can you fan me so i can message you if i need help plz?

  19. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you have to admit this is rather easy, right? i mean once you know what you are doing

  20. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    k

  21. sara1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah i posted this because i am home schooled and i have no one to teach me the concepts

  22. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that must be tough guess you can always post here. there are lots of on line resources, but here you may get a direct answer

  23. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.