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stupidinmath

  • 3 years ago

"if the area of a square is 4x^2-12xy+9y^2 , what is its perimeter?" *what will i do first with the area????????

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  1. ParthKohli
    • 3 years ago
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    Your area is already given, and you'd find the square root to get the measure of a side.

  2. hartnn
    • 3 years ago
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    can u factor the equation : 4x^2-12xy+9y^2

  3. ParthKohli
    • 3 years ago
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    Do you know how to complete the square?

  4. stupidinmath
    • 3 years ago
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    4x^2-12xy+9y^2 factored = (2x-3y)(2x-3y)

  5. estudier
    • 3 years ago
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    |dw:1348230466541:dw|

  6. hartnn
    • 3 years ago
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    thats right :) so its (2x-3y)^2 right ?

  7. stupidinmath
    • 3 years ago
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    yup/

  8. hartnn
    • 3 years ago
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    AREA =side^2 so what will be the side if area is (2x-3y)^2

  9. sriramkumar
    • 3 years ago
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    area=(2x-3y)^2= s^2 s=2x-3y and perimeter is 4s= 4(2x-3y) i guess....

  10. hartnn
    • 3 years ago
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    i wanted @stupidinmath to try that^

  11. stupidinmath
    • 3 years ago
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    (2x-3y)+(2x-3y)+(2x-3y)+(2x-3y) =8x^4-12y^4? or . . . 4(2x-3y) =8x-12y? .______________________________.

  12. hartnn
    • 3 years ago
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    since u are adding and not multiplying all sides, it will be 8x-12y

  13. stupidinmath
    • 3 years ago
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    THANKS:)

  14. hartnn
    • 3 years ago
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    welcome :)

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