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zachkt Group Title

determine the potential difference Vxy in the circuit.

  • 2 years ago
  • 2 years ago

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  1. zachkt Group Title
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    |dw:1348230038272:dw|

    • 2 years ago
  2. zachkt Group Title
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    srry hold on something went wrong

    • 2 years ago
  3. zachkt Group Title
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    let me add in the Voltage and resistor values

    • 2 years ago
  4. pitankar Group Title
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    sure

    • 2 years ago
  5. zachkt Group Title
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    |dw:1348230380036:dw|

    • 2 years ago
  6. pitankar Group Title
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    do you want me to give you the answer or the way to solve it?

    • 2 years ago
  7. zachkt Group Title
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    the way

    • 2 years ago
  8. pitankar Group Title
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    you know superposition?

    • 2 years ago
  9. zachkt Group Title
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    like a super node?

    • 2 years ago
  10. zachkt Group Title
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    Assuming you know the program "Multisim" i simulated this circuit and i have certain values already so I do not think i need to use a complex calculation. I guess my question is, what exactly in the circuit do i need to solve the potential difference Vxy

    • 2 years ago
  11. pitankar Group Title
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    ok! this problem can be solved using superposition theorem. which states, "In a linear network the overall response is the sum of the responses, one energy source acting at a time." So the approach to the problem is like this. first keep the source of 2V on and calculate the voltage at x and when you do this, short circuit all other voltage sources. Similarly repeat the procedure by keeping the 4V source on (on the extreme right) and short circuiting all other sources, find potential at y. now you have potential at X and Y and also the potential that bridges them, i.e 4V. see the polarity and add. you will get the answer

    • 2 years ago
  12. zachkt Group Title
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    so i just need to find the voltage at X and Y? then what?

    • 2 years ago
  13. pitankar Group Title
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    then you add the voltage as per polarity from x-3ohm-4V-3ohm-Y

    • 2 years ago
  14. zachkt Group Title
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    so i subtract the voltageX by 3ohms then subtract by 4V then subtract by 3ohms then subtract by voltageY?

    • 2 years ago
  15. zachkt Group Title
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    okay Voltage X is 1.2V and Y is 2.5, can you show me how to do the rest?

    • 2 years ago
  16. pitankar Group Title
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    Vx-4V-Vy 1.2-4-2.5 1.2-6.5 -5.3V Vxy = -5.3V

    • 2 years ago
  17. zachkt Group Title
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    now why is it Vx-4V instead of Vy-4V? is it because Vx is at higher potential ?

    • 2 years ago
  18. kashyapbharat48 Group Title
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    Vxy = -.5

    • 2 years ago
  19. pitankar Group Title
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    no it's because when I go from X to Y I need to follow a convention. chose all voltage drops to be +ve and all voltage rises to be -Ve. So from X, the resistor gives me a voltage drop of 1.2V which I consider positive. The as I walk further I see a battery in reverse with 4V, since it is reverse, it gives me a voltage rise of 4V (-ve terminal is at lover potential to +ve, so it's a rise) and I consider it to be -Ve.

    • 2 years ago
  20. pitankar Group Title
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    and also dude, I have assumed that you chose the same convention to solve for voltages. The sketch you have uploaded doesn't show the right half properly, if possible redraw and i'll tell you the way to solve it

    • 2 years ago
  21. pitankar Group Title
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    @kashyapbharat48 seems to have solved it.

    • 2 years ago
  22. zachkt Group Title
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    that was all that was drawn in the problem, so that is all the information i know. I then had to use a computer program to simulate the circuit and i have the values of the voltages at X an Y

    • 2 years ago
  23. zachkt Group Title
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    how is it -0.5?

    • 2 years ago
  24. kashyapbharat48 Group Title
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    whats the correct ans?

    • 2 years ago
  25. zachkt Group Title
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    i do not have the correct answer, I just want to know how you solved that?

    • 2 years ago
  26. kashyapbharat48 Group Title
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    try the superposition method u'll get it

    • 2 years ago
  27. MillerZ Group Title
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    the correct solution is:

    • 2 years ago
  28. MillerZ Group Title
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    Vy-Vx=-3.7V

    • 2 years ago
  29. MillerZ Group Title
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    • 2 years ago
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  30. MillerZ Group Title
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    review the file...

    • 2 years ago
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