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zachkt
 2 years ago
Best ResponseYou've already chosen the best response.0srry hold on something went wrong

zachkt
 2 years ago
Best ResponseYou've already chosen the best response.0let me add in the Voltage and resistor values

pitankar
 2 years ago
Best ResponseYou've already chosen the best response.0do you want me to give you the answer or the way to solve it?

pitankar
 2 years ago
Best ResponseYou've already chosen the best response.0you know superposition?

zachkt
 2 years ago
Best ResponseYou've already chosen the best response.0Assuming you know the program "Multisim" i simulated this circuit and i have certain values already so I do not think i need to use a complex calculation. I guess my question is, what exactly in the circuit do i need to solve the potential difference Vxy

pitankar
 2 years ago
Best ResponseYou've already chosen the best response.0ok! this problem can be solved using superposition theorem. which states, "In a linear network the overall response is the sum of the responses, one energy source acting at a time." So the approach to the problem is like this. first keep the source of 2V on and calculate the voltage at x and when you do this, short circuit all other voltage sources. Similarly repeat the procedure by keeping the 4V source on (on the extreme right) and short circuiting all other sources, find potential at y. now you have potential at X and Y and also the potential that bridges them, i.e 4V. see the polarity and add. you will get the answer

zachkt
 2 years ago
Best ResponseYou've already chosen the best response.0so i just need to find the voltage at X and Y? then what?

pitankar
 2 years ago
Best ResponseYou've already chosen the best response.0then you add the voltage as per polarity from x3ohm4V3ohmY

zachkt
 2 years ago
Best ResponseYou've already chosen the best response.0so i subtract the voltageX by 3ohms then subtract by 4V then subtract by 3ohms then subtract by voltageY?

zachkt
 2 years ago
Best ResponseYou've already chosen the best response.0okay Voltage X is 1.2V and Y is 2.5, can you show me how to do the rest?

pitankar
 2 years ago
Best ResponseYou've already chosen the best response.0Vx4VVy 1.242.5 1.26.5 5.3V Vxy = 5.3V

zachkt
 2 years ago
Best ResponseYou've already chosen the best response.0now why is it Vx4V instead of Vy4V? is it because Vx is at higher potential ?

pitankar
 2 years ago
Best ResponseYou've already chosen the best response.0no it's because when I go from X to Y I need to follow a convention. chose all voltage drops to be +ve and all voltage rises to be Ve. So from X, the resistor gives me a voltage drop of 1.2V which I consider positive. The as I walk further I see a battery in reverse with 4V, since it is reverse, it gives me a voltage rise of 4V (ve terminal is at lover potential to +ve, so it's a rise) and I consider it to be Ve.

pitankar
 2 years ago
Best ResponseYou've already chosen the best response.0and also dude, I have assumed that you chose the same convention to solve for voltages. The sketch you have uploaded doesn't show the right half properly, if possible redraw and i'll tell you the way to solve it

pitankar
 2 years ago
Best ResponseYou've already chosen the best response.0@kashyapbharat48 seems to have solved it.

zachkt
 2 years ago
Best ResponseYou've already chosen the best response.0that was all that was drawn in the problem, so that is all the information i know. I then had to use a computer program to simulate the circuit and i have the values of the voltages at X an Y

kashyapbharat48
 2 years ago
Best ResponseYou've already chosen the best response.0whats the correct ans?

zachkt
 2 years ago
Best ResponseYou've already chosen the best response.0i do not have the correct answer, I just want to know how you solved that?

kashyapbharat48
 2 years ago
Best ResponseYou've already chosen the best response.0try the superposition method u'll get it

MillerZ
 2 years ago
Best ResponseYou've already chosen the best response.1the correct solution is:
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