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zachktBest ResponseYou've already chosen the best response.0
srry hold on something went wrong
 one year ago

zachktBest ResponseYou've already chosen the best response.0
let me add in the Voltage and resistor values
 one year ago

pitankarBest ResponseYou've already chosen the best response.0
do you want me to give you the answer or the way to solve it?
 one year ago

pitankarBest ResponseYou've already chosen the best response.0
you know superposition?
 one year ago

zachktBest ResponseYou've already chosen the best response.0
Assuming you know the program "Multisim" i simulated this circuit and i have certain values already so I do not think i need to use a complex calculation. I guess my question is, what exactly in the circuit do i need to solve the potential difference Vxy
 one year ago

pitankarBest ResponseYou've already chosen the best response.0
ok! this problem can be solved using superposition theorem. which states, "In a linear network the overall response is the sum of the responses, one energy source acting at a time." So the approach to the problem is like this. first keep the source of 2V on and calculate the voltage at x and when you do this, short circuit all other voltage sources. Similarly repeat the procedure by keeping the 4V source on (on the extreme right) and short circuiting all other sources, find potential at y. now you have potential at X and Y and also the potential that bridges them, i.e 4V. see the polarity and add. you will get the answer
 one year ago

zachktBest ResponseYou've already chosen the best response.0
so i just need to find the voltage at X and Y? then what?
 one year ago

pitankarBest ResponseYou've already chosen the best response.0
then you add the voltage as per polarity from x3ohm4V3ohmY
 one year ago

zachktBest ResponseYou've already chosen the best response.0
so i subtract the voltageX by 3ohms then subtract by 4V then subtract by 3ohms then subtract by voltageY?
 one year ago

zachktBest ResponseYou've already chosen the best response.0
okay Voltage X is 1.2V and Y is 2.5, can you show me how to do the rest?
 one year ago

pitankarBest ResponseYou've already chosen the best response.0
Vx4VVy 1.242.5 1.26.5 5.3V Vxy = 5.3V
 one year ago

zachktBest ResponseYou've already chosen the best response.0
now why is it Vx4V instead of Vy4V? is it because Vx is at higher potential ?
 one year ago

pitankarBest ResponseYou've already chosen the best response.0
no it's because when I go from X to Y I need to follow a convention. chose all voltage drops to be +ve and all voltage rises to be Ve. So from X, the resistor gives me a voltage drop of 1.2V which I consider positive. The as I walk further I see a battery in reverse with 4V, since it is reverse, it gives me a voltage rise of 4V (ve terminal is at lover potential to +ve, so it's a rise) and I consider it to be Ve.
 one year ago

pitankarBest ResponseYou've already chosen the best response.0
and also dude, I have assumed that you chose the same convention to solve for voltages. The sketch you have uploaded doesn't show the right half properly, if possible redraw and i'll tell you the way to solve it
 one year ago

pitankarBest ResponseYou've already chosen the best response.0
@kashyapbharat48 seems to have solved it.
 one year ago

zachktBest ResponseYou've already chosen the best response.0
that was all that was drawn in the problem, so that is all the information i know. I then had to use a computer program to simulate the circuit and i have the values of the voltages at X an Y
 one year ago

kashyapbharat48Best ResponseYou've already chosen the best response.0
whats the correct ans?
 one year ago

zachktBest ResponseYou've already chosen the best response.0
i do not have the correct answer, I just want to know how you solved that?
 one year ago

kashyapbharat48Best ResponseYou've already chosen the best response.0
try the superposition method u'll get it
 one year ago

MillerZBest ResponseYou've already chosen the best response.1
the correct solution is:
 one year ago
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