determine the potential difference Vxy in the circuit.

- anonymous

determine the potential difference Vxy in the circuit.

- schrodinger

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- anonymous

|dw:1348230038272:dw|

- anonymous

srry hold on something went wrong

- anonymous

let me add in the Voltage and resistor values

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## More answers

- anonymous

sure

- anonymous

|dw:1348230380036:dw|

- anonymous

do you want me to give you the answer or the way to solve it?

- anonymous

the way

- anonymous

you know superposition?

- anonymous

like a super node?

- anonymous

Assuming you know the program "Multisim" i simulated this circuit and i have certain values already so I do not think i need to use a complex calculation. I guess my question is, what exactly in the circuit do i need to solve the potential difference Vxy

- anonymous

ok! this problem can be solved using superposition theorem. which states, "In a linear network the overall response is the sum of the responses, one energy source acting at a time."
So the approach to the problem is like this. first keep the source of 2V on and calculate the voltage at x and when you do this, short circuit all other voltage sources. Similarly repeat the procedure by keeping the 4V source on (on the extreme right) and short circuiting all other sources, find potential at y.
now you have potential at X and Y and also the potential that bridges them, i.e 4V. see the polarity and add. you will get the answer

- anonymous

so i just need to find the voltage at X and Y? then what?

- anonymous

then you add the voltage as per polarity from x-3ohm-4V-3ohm-Y

- anonymous

so i subtract the voltageX by 3ohms then subtract by 4V then subtract by 3ohms then subtract by voltageY?

- anonymous

okay Voltage X is 1.2V and Y is 2.5, can you show me how to do the rest?

- anonymous

Vx-4V-Vy
1.2-4-2.5
1.2-6.5
-5.3V
Vxy = -5.3V

- anonymous

now why is it Vx-4V instead of Vy-4V? is it because Vx is at higher potential ?

- anonymous

Vxy = -.5

- anonymous

no it's because when I go from X to Y I need to follow a convention. chose all voltage drops to be +ve and all voltage rises to be -Ve.
So from X, the resistor gives me a voltage drop of 1.2V which I consider positive. The as I walk further I see a battery in reverse with 4V, since it is reverse, it gives me a voltage rise of 4V (-ve terminal is at lover potential to +ve, so it's a rise) and I consider it to be -Ve.

- anonymous

and also dude, I have assumed that you chose the same convention to solve for voltages. The sketch you have uploaded doesn't show the right half properly, if possible redraw and i'll tell you the way to solve it

- anonymous

@kashyapbharat48 seems to have solved it.

- anonymous

that was all that was drawn in the problem, so that is all the information i know. I then had to use a computer program to simulate the circuit and i have the values of the voltages at X an Y

- anonymous

how is it -0.5?

- anonymous

whats the correct ans?

- anonymous

i do not have the correct answer, I just want to know how you solved that?

- anonymous

try the superposition method u'll get it

- anonymous

the correct solution is:

- anonymous

Vy-Vx=-3.7V

- anonymous

##### 1 Attachment

- anonymous

review the file...

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