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inkyvoyd

  • 3 years ago

Exponential and logarithmic functions 7. Calculate the amount of interest earned on $100 in one year at 6% compounded countinuosly. Then determine the exact interest rate in terms of e required to earn the same amount of interest when $100 is deposited in an account where the interest is compounded a. yearly b. semi-annually c. monthly d. quarterly

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  1. inkyvoyd
    • 3 years ago
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    formulas given to me: interest compounded continuously:A=Pe^(rt) A=P(1+r/n)^(nt) what I need help with: I'm supposed to express these solutions as a form of e

  2. inkyvoyd
    • 3 years ago
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    What I have:I put in the numbers for b, and got e^0.06=(1+r)^2 0=(1+0.5r)^2-e^0.06 0=(1+0.5r+e^0.03)(1+0.5r-e^0.03) 1+0.5r-e^0.03=0 r=2e^0.03-2 In other words, I used the difference of squares what everyone else got in my virtual discussion board: 0.0224e how did they get this answer and what am i doing wrong?

  3. inkyvoyd
    • 3 years ago
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    Sigh. Can't even do the beginng of BC calc rite.

  4. completeidiot
    • 3 years ago
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    you do realize e is just a number right? e=2.71828...

  5. inkyvoyd
    • 3 years ago
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    I know e is a number. But I'm supposed to give this answer in terms of e, just like giving an answer in terms of pi.

  6. completeidiot
    • 3 years ago
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    (2e^0.03-2) /e = .224

  7. completeidiot
    • 3 years ago
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    so r=(2e^0.03-2)=.224e

  8. inkyvoyd
    • 3 years ago
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    yaeh but there isn't any point in using e if you are going to approximate in the first place.

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