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inkyvoyd
 3 years ago
Exponential and logarithmic functions
7.
Calculate the amount of interest earned on $100 in one year at 6% compounded countinuosly. Then determine the exact interest rate in terms of e required to earn the same amount of interest when $100 is deposited in an account where the interest is compounded
a. yearly
b. semiannually
c. monthly
d. quarterly
inkyvoyd
 3 years ago
Exponential and logarithmic functions 7. Calculate the amount of interest earned on $100 in one year at 6% compounded countinuosly. Then determine the exact interest rate in terms of e required to earn the same amount of interest when $100 is deposited in an account where the interest is compounded a. yearly b. semiannually c. monthly d. quarterly

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inkyvoyd
 3 years ago
Best ResponseYou've already chosen the best response.0formulas given to me: interest compounded continuously:A=Pe^(rt) A=P(1+r/n)^(nt) what I need help with: I'm supposed to express these solutions as a form of e

inkyvoyd
 3 years ago
Best ResponseYou've already chosen the best response.0What I have:I put in the numbers for b, and got e^0.06=(1+r)^2 0=(1+0.5r)^2e^0.06 0=(1+0.5r+e^0.03)(1+0.5re^0.03) 1+0.5re^0.03=0 r=2e^0.032 In other words, I used the difference of squares what everyone else got in my virtual discussion board: 0.0224e how did they get this answer and what am i doing wrong?

inkyvoyd
 3 years ago
Best ResponseYou've already chosen the best response.0Sigh. Can't even do the beginng of BC calc rite.

completeidiot
 3 years ago
Best ResponseYou've already chosen the best response.0you do realize e is just a number right? e=2.71828...

inkyvoyd
 3 years ago
Best ResponseYou've already chosen the best response.0I know e is a number. But I'm supposed to give this answer in terms of e, just like giving an answer in terms of pi.

completeidiot
 3 years ago
Best ResponseYou've already chosen the best response.0(2e^0.032) /e = .224

completeidiot
 3 years ago
Best ResponseYou've already chosen the best response.0so r=(2e^0.032)=.224e

inkyvoyd
 3 years ago
Best ResponseYou've already chosen the best response.0yaeh but there isn't any point in using e if you are going to approximate in the first place.
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