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anonymous
 4 years ago
In a triangle ABC, AD is the bisector of angle BAC and angle C is greater than angle B.
Prove that angle ADB > angle ADC.
anonymous
 4 years ago
In a triangle ABC, AD is the bisector of angle BAC and angle C is greater than angle B. Prove that angle ADB > angle ADC.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1348233132884:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Please help I have an exam tomorrow and need to get my doubts cleared.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@lgbasallote please please help ....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@lgbasallote help!!!!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can you help @Mimi_x3?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0AD is the bisector of angle BAC , so angle BAD = angle CAD angle C >angle B angle ADB =180(ABD+BAD) angle ADC = 180(CAD+ACD) since angle BAD = angle CAD angle ADB =180(BAD+ABD) angle ADC =180(BAD+ACD) angle C >angle B hence, angle ADB > angle ADC.
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