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In a triangle ABC, AD is the bisector of angle BAC and angle C is greater than angle B.
Prove that angle ADB > angle ADC.
 one year ago
 one year ago
In a triangle ABC, AD is the bisector of angle BAC and angle C is greater than angle B. Prove that angle ADB > angle ADC.
 one year ago
 one year ago

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pratu043Best ResponseYou've already chosen the best response.0
dw:1348233132884:dw
 one year ago

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Please help I have an exam tomorrow and need to get my doubts cleared.
 one year ago

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@lgbasallote please please help ....
 one year ago

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@lgbasallote help!!!!!
 one year ago

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Can you help @Mimi_x3?
 one year ago

wwe123Best ResponseYou've already chosen the best response.1
AD is the bisector of angle BAC , so angle BAD = angle CAD angle C >angle B angle ADB =180(ABD+BAD) angle ADC = 180(CAD+ACD) since angle BAD = angle CAD angle ADB =180(BAD+ABD) angle ADC =180(BAD+ACD) angle C >angle B hence, angle ADB > angle ADC.
 one year ago
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