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pratu043
In a triangle ABC, AD is the bisector of angle BAC and angle C is greater than angle B. Prove that angle ADB > angle ADC.
Please help I have an exam tomorrow and need to get my doubts cleared.
@lgbasallote please please help ....
@lgbasallote help!!!!!
Can you help @Mimi_x3?
AD is the bisector of angle BAC , so angle BAD = angle CAD angle C >angle B angle ADB =180-(ABD+BAD) angle ADC = 180-(CAD+ACD) since angle BAD = angle CAD angle ADB =180-(BAD+ABD) angle ADC =180-(BAD+ACD) angle C >angle B hence, angle ADB > angle ADC.