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amistre64
 4 years ago
When trying to find out a spring constant, should the platforms mass be included in the calculations if the scale has been zeroed out by the weight of the platform?
amistre64
 4 years ago
When trying to find out a spring constant, should the platforms mass be included in the calculations if the scale has been zeroed out by the weight of the platform?

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1348234155317:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1my gut says no as well; but my physics teacher said that we have to.

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1Yes same here... since : when you have already taken the mass including that of the platform mass as 0 , then we should not include the mass of the platform again.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the new deformation is caused only by new mass

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1348234340830:dw he "asked the math major" will the first point be at the origin. To which I stated, "hopefully".

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you will read only \[\Delta x\]

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1@RaphaelFilgueiras is right (acc. to me)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so he wants you to find the slope of a line but he insists the y intercept matters...

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1the slope of the linear approximation is the spring constant. And that slope is not dependant on where you begin so long as the data points are in the proper relation

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i humored him .... i figure its best not to disrupt the delicate balance of the non math students of the class :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1if the platform totally stretches out the spring, that might be a concern ... but wouldnt you just use a different platform?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I guess he's technically right, since you could get into a region where the spring is nonlinear ... but for practical purposes, kind of pointless extra busy work...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0pointless extra superfluous* busy work

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1lol, sounds alot like number theory class this term too; alot of busy work to learn how to divide

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0heh. busy work is a global constant.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1ive got another gripe that I will post anew ;)
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