amistre64
  • amistre64
When trying to find out a spring constant, should the platforms mass be included in the calculations if the scale has been zeroed out by the weight of the platform?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
|dw:1348234155317:dw|
anonymous
  • anonymous
no
amistre64
  • amistre64
my gut says no as well; but my physics teacher said that we have to.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

mathslover
  • mathslover
Yes same here... since : when you have already taken the mass including that of the platform mass as 0 , then we should not include the mass of the platform again.
anonymous
  • anonymous
the new deformation is caused only by new mass
anonymous
  • anonymous
so no
amistre64
  • amistre64
|dw:1348234340830:dw| he "asked the math major" will the first point be at the origin. To which I stated, "hopefully".
anonymous
  • anonymous
you will read only \[\Delta x\]
mathslover
  • mathslover
@RaphaelFilgueiras is right (acc. to me)
anonymous
  • anonymous
so he wants you to find the slope of a line but he insists the y intercept matters...
anonymous
  • anonymous
humor him I guess...
amistre64
  • amistre64
the slope of the linear approximation is the spring constant. And that slope is not dependant on where you begin so long as the data points are in the proper relation
amistre64
  • amistre64
i humored him .... i figure its best not to disrupt the delicate balance of the non math students of the class :)
amistre64
  • amistre64
if the platform totally stretches out the spring, that might be a concern ... but wouldnt you just use a different platform?
anonymous
  • anonymous
I guess he's technically right, since you could get into a region where the spring is non-linear ... but for practical purposes, kind of pointless extra busy work...
anonymous
  • anonymous
pointless extra superfluous* busy work
amistre64
  • amistre64
lol, sounds alot like number theory class this term too; alot of busy work to learn how to divide
anonymous
  • anonymous
heh. busy work is a global constant.
amistre64
  • amistre64
ive got another gripe that I will post anew ;)
mathslover
  • mathslover
Go for it.. :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.