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x^2y-5xy+6y+7x^2-35x+42

solving for x?

factoring

xy(x-5)+6y+7x(x-5)+42=0

(xy+7x)(x-5)+(6y+42)=0
x(y+7)(x-5)+6(y+7)=0
{x(x-5)+6}(y+7)=0....i am not sure tho

@andriod09 does that help?

no, not really. but i have the answer.

hello solving for x
x(x-5)+6=0
x^2-5x+6=0
delta =1
x1=3 and x2=3

x2 =2

^^^^got so mad

your question is "HELP PLEASE!
EQUATION IS IN COMMENTS"

"andriod09 0
factoring
10 minutes agoDelete"

is it incomplete?

all i had to do is factor the polynomial. thats it. i already have the answer.

that's it

but its not the correct answer

then do it other way

the correct answer is:
(x-2)(x-3)(y+7)

dude factor my last equation...you will get this

(x^2-5x+6)(y+7)=0
(x-2)(x-3)(y+7)=0

no, your last equation as a quadratic equation, this is just a normal polynomial

@andriod09 hope it is clear to you now?