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HELP PLEASE! EQUATION IS IN COMMENTS

Mathematics
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x^2y-5xy+6y+7x^2-35x+42
solving for x?
factoring

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Other answers:

xy(x-5)+6y+7x(x-5)+42=0
(xy+7x)(x-5)+(6y+42)=0 x(y+7)(x-5)+6(y+7)=0 {x(x-5)+6}(y+7)=0....i am not sure tho
@andriod09 does that help?
no, not really. but i have the answer.
hello solving for x x(x-5)+6=0 x^2-5x+6=0 delta =1 x1=3 and x2=3
x2 =2
I AM NOT SOLVING FOR "X"!!! I AM FACTORING THE POLYNOMIAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
^^^^got so mad
your question is "HELP PLEASE! EQUATION IS IN COMMENTS"
"andriod09 0 factoring 10 minutes agoDelete"
is it incomplete?
all i had to do is factor the polynomial. thats it. i already have the answer.
that's it
but its not the correct answer
then do it other way
the correct answer is: (x-2)(x-3)(y+7)
dude factor my last equation...you will get this
(x^2-5x+6)(y+7)=0 (x-2)(x-3)(y+7)=0
no, your last equation as a quadratic equation, this is just a normal polynomial
{x(x-5)+6}(y+7)=0 {x^2-5x+6}(y+7)=0 (x^2-3x-2x+6)(y+7)=0 (x-2)(x-3)(y+7)=0 @Nicole<3Algebra can you help further
@andriod09 hope it is clear to you now?

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