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andriod09 Group Title

HELP PLEASE! EQUATION IS IN COMMENTS

  • 2 years ago
  • 2 years ago

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  1. andriod09 Group Title
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    x^2y-5xy+6y+7x^2-35x+42

    • 2 years ago
  2. Nicole<3Algebra Group Title
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    solving for x?

    • 2 years ago
  3. andriod09 Group Title
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    factoring

    • 2 years ago
  4. jasonxx Group Title
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    xy(x-5)+6y+7x(x-5)+42=0

    • 2 years ago
  5. jasonxx Group Title
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    (xy+7x)(x-5)+(6y+42)=0 x(y+7)(x-5)+6(y+7)=0 {x(x-5)+6}(y+7)=0....i am not sure tho

    • 2 years ago
  6. jasonxx Group Title
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    @andriod09 does that help?

    • 2 years ago
  7. andriod09 Group Title
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    no, not really. but i have the answer.

    • 2 years ago
  8. dhiab Group Title
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    hello solving for x x(x-5)+6=0 x^2-5x+6=0 delta =1 x1=3 and x2=3

    • 2 years ago
  9. dhiab Group Title
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    x2 =2

    • 2 years ago
  10. andriod09 Group Title
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    I AM NOT SOLVING FOR "X"!!! I AM FACTORING THE POLYNOMIAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

    • 2 years ago
  11. Nicole<3Algebra Group Title
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    ^^^^got so mad

    • 2 years ago
  12. dhiab Group Title
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    your question is "HELP PLEASE! EQUATION IS IN COMMENTS"

    • 2 years ago
  13. andriod09 Group Title
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    "andriod09 0 factoring 10 minutes agoDelete"

    • 2 years ago
  14. jasonxx Group Title
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    is it incomplete?

    • 2 years ago
  15. andriod09 Group Title
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    all i had to do is factor the polynomial. thats it. i already have the answer.

    • 2 years ago
  16. jasonxx Group Title
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    that's it

    • 2 years ago
  17. andriod09 Group Title
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    but its not the correct answer

    • 2 years ago
  18. jasonxx Group Title
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    then do it other way

    • 2 years ago
  19. andriod09 Group Title
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    the correct answer is: (x-2)(x-3)(y+7)

    • 2 years ago
  20. jasonxx Group Title
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    dude factor my last equation...you will get this

    • 2 years ago
  21. jasonxx Group Title
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    (x^2-5x+6)(y+7)=0 (x-2)(x-3)(y+7)=0

    • 2 years ago
  22. andriod09 Group Title
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    no, your last equation as a quadratic equation, this is just a normal polynomial

    • 2 years ago
  23. jasonxx Group Title
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    {x(x-5)+6}(y+7)=0 {x^2-5x+6}(y+7)=0 (x^2-3x-2x+6)(y+7)=0 (x-2)(x-3)(y+7)=0 @Nicole<3Algebra can you help further

    • 2 years ago
  24. jasonxx Group Title
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    @andriod09 hope it is clear to you now?

    • 2 years ago
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