1. andriod09

x^2y-5xy+6y+7x^2-35x+42

2. Nicole<3Algebra

solving for x?

3. andriod09

factoring

4. jasonxx

xy(x-5)+6y+7x(x-5)+42=0

5. jasonxx

(xy+7x)(x-5)+(6y+42)=0 x(y+7)(x-5)+6(y+7)=0 {x(x-5)+6}(y+7)=0....i am not sure tho

6. jasonxx

@andriod09 does that help?

7. andriod09

no, not really. but i have the answer.

8. dhiab

hello solving for x x(x-5)+6=0 x^2-5x+6=0 delta =1 x1=3 and x2=3

9. dhiab

x2 =2

10. andriod09

I AM NOT SOLVING FOR "X"!!! I AM FACTORING THE POLYNOMIAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

11. Nicole<3Algebra

12. dhiab

13. andriod09

"andriod09 0 factoring 10 minutes agoDelete"

14. jasonxx

is it incomplete?

15. andriod09

16. jasonxx

that's it

17. andriod09

but its not the correct answer

18. jasonxx

then do it other way

19. andriod09

20. jasonxx

dude factor my last equation...you will get this

21. jasonxx

(x^2-5x+6)(y+7)=0 (x-2)(x-3)(y+7)=0

22. andriod09

no, your last equation as a quadratic equation, this is just a normal polynomial

23. jasonxx

{x(x-5)+6}(y+7)=0 {x^2-5x+6}(y+7)=0 (x^2-3x-2x+6)(y+7)=0 (x-2)(x-3)(y+7)=0 @Nicole<3Algebra can you help further

24. jasonxx

@andriod09 hope it is clear to you now?