andriod09
HELP PLEASE!
EQUATION IS IN COMMENTS



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andriod09
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x^2y5xy+6y+7x^235x+42

Nicole<3Algebra
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solving for x?

andriod09
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factoring

jasonxx
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xy(x5)+6y+7x(x5)+42=0

jasonxx
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(xy+7x)(x5)+(6y+42)=0
x(y+7)(x5)+6(y+7)=0
{x(x5)+6}(y+7)=0....i am not sure tho

jasonxx
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@andriod09 does that help?

andriod09
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no, not really. but i have the answer.

dhiab
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hello solving for x
x(x5)+6=0
x^25x+6=0
delta =1
x1=3 and x2=3

dhiab
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x2 =2

andriod09
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I AM NOT SOLVING FOR "X"!!! I AM FACTORING THE POLYNOMIAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Nicole<3Algebra
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^^^^got so mad

dhiab
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your question is "HELP PLEASE!
EQUATION IS IN COMMENTS"

andriod09
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"andriod09 0
factoring
10 minutes agoDelete"

jasonxx
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is it incomplete?

andriod09
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all i had to do is factor the polynomial. thats it. i already have the answer.

jasonxx
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that's it

andriod09
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but its not the correct answer

jasonxx
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then do it other way

andriod09
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the correct answer is:
(x2)(x3)(y+7)

jasonxx
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dude factor my last equation...you will get this

jasonxx
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(x^25x+6)(y+7)=0
(x2)(x3)(y+7)=0

andriod09
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no, your last equation as a quadratic equation, this is just a normal polynomial

jasonxx
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{x(x5)+6}(y+7)=0
{x^25x+6}(y+7)=0
(x^23x2x+6)(y+7)=0
(x2)(x3)(y+7)=0 @Nicole<3Algebra can you help further

jasonxx
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@andriod09 hope it is clear to you now?