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What is the equation of the line perpendicular to the line y = x – 2 that passes through the point (4,3)?
y = –x – 2
y = x + 6
y = –x + 12
y = –x – 12
 one year ago
 one year ago
What is the equation of the line perpendicular to the line y = x – 2 that passes through the point (4,3)? y = –x – 2 y = x + 6 y = –x + 12 y = –x – 12
 one year ago
 one year ago

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ajprincessBest ResponseYou've already chosen the best response.0
The gradient of the required line*The gradient of the given line=1 That is m*m1=1 m1=1 m*1=1 m=1 \[m=\frac{ yy_1 }{ xx_1 }\] \[1=\frac{ y3 }{ x4}\] Can u find nw?
 one year ago
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