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Isabel.A
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|dw:1348247458539:dw|
Isabel.A
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Solve For r
JakeV8
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Is that all you are given in the problem, or is there more?
Isabel.A
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Thats All .
nustian
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incomplete information
JakeV8
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No, it is ok... right now, it is "solved" for C... you need to get "r" all by itself instead.
Isabel.A
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How Do I Do That Tho ?
JakeV8
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If you divide both sides of the equation by 2pi, the right side simplifies to just "r"
nustian
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exactly
JakeV8
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|dw:1348247556863:dw|
nustian
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u just need values of r
nustian
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|dw:1348074883290:dw|
Isabel.A
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So its C-2pi=r ?
nustian
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whatever the vaue of r is put in that formula
and pi has value 3.14
Isabel.A
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There is no Value of R
JakeV8
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if you don't have a value of r, that's fine... "solving for r" just means writing the expression down in a way where it starts like "r = "
JakeV8
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so, r = C / (2pi) is solving your original expression for "r"
Isabel.A
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Isnt it Negative tho ?
JakeV8
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why would it be negative?
Isabel.A
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|dw:1348247883645:dw|
Isabel.A
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To Be Able To Get It To The Other Side .
JakeV8
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no, you don't subtract anything... don't let the 2pi term confuse you
Isabel.A
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Ohh Okay . Gosh Its Confusing .
JakeV8
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Think of easier stuff like this... if I said C = 5r, solve for r, you would divide both sides by 5, leaving you with C/5 = r, or you could just reverse it and answer r = C/5
Isabel.A
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Ohh Well That Makes Sense . So Basicly The Answers ; R=C2pi ?
JakeV8
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2pi is just some number... happens to be a little more than 6 since pi is about 3.14, but don't even worry about that.... just divide both sides by "2pi". On the r side, the 2pi divides out and "goes away" :)
Isabel.A
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Oooh Okay(:
JakeV8
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R = C / 2pi you divide C by 2pi, just like you divided (2pi)(R) by 2pi to get just R
Isabel.A
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o.o Wait . How do i divide it by C ?
JakeV8
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What class/grade are you in?
Isabel.A
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Algebra 1 & FreshMan
JakeV8
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ok, cool
Isabel.A
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Lol Yeah .
Isabel.A
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& You ?
JakeV8
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so, any equation like y = 2x can be rewritten by dividing both sides of it by the same thing... for example, divide both sides of y = 2x by 2.....
y = 2 x
(y/2) = (2x)/2
y/2 = x
This starts with an expression of y and "solves it for x"
Isabel.A
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Ohhh . Well Thanks For All The Help ! It Is Very Very Appreciated(:
JakeV8
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you need the same idea with C = (2pi)R
C = (2pi)R
C/2pi = [ (2pi)(R) ] / (2pi)
C/2pi = R <<<--- because the 2pi cancels out
JakeV8
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No problem... btw, I graduated... just like math and helping :) Keep up the good work :)
Isabel.A
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Ohh Very Cool . (: & Ima Try Lol .