Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
3-inch radius
A = sq. in.

- anonymous

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- anonymous

Area= 1/2ap

- anonymous

I draw an auxiliary triangle off of the radius, the radius being the hypotenuse

- anonymous

By 3 inch radius, do you mean that it is inscribed in a circle of radius 3 inches?

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## More answers

- anonymous

|dw:1348254489061:dw|

- anonymous

The apothem is half of the radius

- anonymous

|dw:1348254528658:dw| So it looks like both are drawings are similar?

- anonymous

So its 1.5

- anonymous

I multiply 1.5 times √3 to get the long side

- anonymous

Than i multiply that answer "3√3" by 2 to get the side of the big triangle

- anonymous

I multiply that by 3 to get the perimeter. So i have the perimeter and the apothem.

- anonymous

Yes, and to make matters easier, the angle and segment bisectors will meet 2/3 of the way to the other side, making the height = 1.5 x apothem.

- anonymous

The answer i got the first time is: 6 3/4√3 but they told me its wrong.

- anonymous

height = 1.5 x apothem = 1.5 x (r/2) = 3r/4.

- anonymous

I don't need the height to find the area though.

- anonymous

All i need is the apothem and the perimeter

- anonymous

You're right, you don't, but you can take advantage of some easy trigonometry to get the answer easier.

- anonymous

Ok, well i'm only in Geometry.. So i'm not suppose to be doing trig

- anonymous

*Well i don't know any

- anonymous

Ok, then I'll stop with that approach.

- anonymous

Lol, if it's fairly easy, I don't mind learning it

- anonymous

It must be easier than the book's method because everyone I talk to on here starts using trig

- anonymous

No, that's ok. I can do it the other way. That's the way you're supposed to be doing it and it will blow others away.

- anonymous

I'll explain the methodology and you can do the work. It won't be that hard, really.

- anonymous

I got most of my questions right, but this one i got wrong and i'm not sure why.

- anonymous

We'll use apothem and perimeter and derive some cool measurements from them.

- anonymous

Groovy

- anonymous

We can use one thing I said above, that height = 3r/4 because that does come from the apothem to radius relationship and the fact that angle and side bisectors meet in the middle and make that height 3r/4. Stop and draw yourself that on paper to convince yourself. Because that's going to be key. And grooviness is good here!

- anonymous

r= radius?

- anonymous

9/4 is the height?

- anonymous

yes.

- anonymous

Now, here's the trick, and it's really cool conceptually, but a little hard to explain. maybe I can draw a picture.

- anonymous

Ok.

- anonymous

|dw:1348255695035:dw|

- anonymous

For an equilateral triangle circumcentre, incentre , centroid are all at the same point
use this property to solve the problem

- anonymous

I forgot to put a letter at the top, call it c and call the, here, I'll draw again

- anonymous

@tcarroll010 , has given you the correct diagram, just name the angles and measures of sides

- anonymous

|dw:1348255924927:dw| There.

- anonymous

We know ac = 9/4. We know oa is 3/4. We know ob is 3/4, so we can get ab and you can do 1/2 of h x b for oab. Then double for the whole triangle.

- anonymous

|dw:1348255963318:dw|

- anonymous

Sorry, I did ob wrong, but you can do it. It's 2/3 of oa.

- anonymous

ob is 2/3 of ac.

- anonymous

Ob is 2/3 of 3/4?

- anonymous

Sorry, I'm trying to do 3 things at once, but it's right there in the diagram and just use pythagorean on the lengths.

- anonymous

I don't follow.

- anonymous

2/3 of 9/4 so its 3/2

- anonymous

1.5

- anonymous

ob is 3/2 oa is 3/4, so you can get ab.

- anonymous

ab will be your base. ac your height. Then you can easily get area of triangle.

- anonymous

Ab being 1.5√3

- anonymous

ac: 3

- anonymous

ac is 9/2 or (4 and 1/2)

- anonymous

oa is apothem which is 1/2 of r, so add 3 (which is oc) to 1 and 1/2 which is oa. so ac is 9/2

- anonymous

Ahhh

- anonymous

ob = oc = 3. So, you have a right triangle where you can figure out ab. ab^2 + oa^2 = ob^2

- anonymous

Once you get ab, it's a piece of cake.

- anonymous

Are you all set now?

- anonymous

I gotta go. I hope you are all set.

- anonymous

No.. Lol, ab^2 + 3/4^2 =3^2?

- anonymous

I just got back to my computer after a half hour. You don't happen to still be there are you?

- anonymous

Sadly, i am.

- anonymous

My condolences. I'm thinking that you're not liking this problem anymore. I'm going to try to simplify it all in one post and you can just work from info in that and the diagram.

- anonymous

OK

- anonymous

oa is apothem and = r/2. oc=ob=r. ac=oc+oa. oa^2 + ab^2 = ob^2. Triangle area = ab x ac. That's all there is to it. My guess is that you're having trouble working with oa^2 + ab^2 = ob^2. So, for that ab: ab = sqrt(ob^2 - oa^2).

- anonymous

oa= 3/2 right?

- anonymous

yes

- anonymous

Are you having trouble with the square root and getting ab? Is that the hangup?

- anonymous

I don't think so, let me work out your equation above ^^

- anonymous

OK, so i got: √6.75
So √6.75 times 4.5 = area?
√6.75 = ab
4.5 = ac

- anonymous

yes, you're getting it, you really are. It might be a little better to think of that ab length, which is sqrt(6.75), as(3 x sqrt(3)) / 2. But either way works. Whatever is easier for you.

- anonymous

Because when you're done, and you really almost are, enough that I can give you the answer, the area is (27 x sqrt(3)) / 4.

- anonymous

OKay.

- anonymous

You should be able to get to that last number with what should be your upcoming and last step.

- anonymous

So...
27√3
------
4
???

- anonymous

\[27√3\div4\]

- anonymous

yes, but more importantly, do you see the flow of the steps? That's the important thing.

- anonymous

I can't carry that out?

- anonymous

You can put it in decimal from or any other representation if you want. Sqrt(3) is irrational, so any decimal representation will truncate digits, but that's ok.

- anonymous

Decimal-wise, it can be truncated to 11.69134.

- anonymous

Oh wait sorry,
27√3/4 is the area!!
Okay

- anonymous

yes, and area is ac x ab.

- anonymous

I put the answer as: 27/4√3

- anonymous

I'll let you know if they accept it in 5 minutes.

- anonymous

Not 27/4√3. It's \[27\sqrt{3}/4\]

- anonymous

The order of those multiplicands is important.

- anonymous

Ok

- anonymous

Correct Score: 100
Thank you!!

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